1. Introduction
Let
be the forward difference operator defined on sequences
by
. Let operator
be

Define the
-Hausdorff matrix
as the lower triangular matrix
with entries

For
, it is the Hausdorff matrix
, see [1] .
When
is the moment sequence of a measure i.e.
, the matrix arising from a Borel measure
is denoted by
, a simple calculation then gives

Let
be the unit polydisk in the complex vector space
,
be the space of all holomorphic functions on
, and
be the Borel measures on
,
,
.
In [2] , the Lipschitz space
is defined on
by

where
. It is easy to prove that
is a Banach space under the norm
.
Let
, suppose
, and
be the
- Hausdorff matrices arising by Borel measures
. The
-Hausdorff operator
is defined as follows:
. For
, we obtain the classical Hausdorff operator
, see [3] .
Hausdorff matrix and Hausdorff operator have studied on various space of holomorphic functions, see, e.g., [3] -[9] . In [3] , the author obtained that the Hausdorff operator
is bounded on Hardy space
, and in [4] we showed that this conclusion cannot be extended to the Bloch space directly. Then we try to study on the Lipschitz space, found that when the measure is common Lebesgue measure
, the Hausdorff operator
is unbounded on Lipschitz space
, see the remark. In this paper, we study the operator which is got by amending the Hausdorff operator and called it
-Hausdorff operator. The results of this paper can be deemed as a continuation of the results in [3] on Lipschitz space.
2. Main Results
The main results in this paper is the following:
Theorem 1 Let
be finite Borel measures on (0,1) and
be corresponding
-Hausdorff matrices,
be
-Hausdorff operator. For
,
is bounded on
if

In this case, the operator norm satisfies

for some constant
.
In order to prove the main results, we need some auxiliary result.
Lemma 1 [2] Let
,then
.
For each
, we note the functions
given by
Lemma 2 Let
be finite Borel measures on
and
be corresponding
-Hausdorff matrices. Suppose

Then(a) The power series
in (2) represents a holomorphic functions on
;
(b)
can be written in terms of weighted composition operators as follows:
. For each
.
Proof (a) Let
. Since
the sequence of Taylor coefficients of
is bounded by a constant
, then

Hence the coefficients of the series (2) are bounded and consequently
is defined and analytic on
.
(b) By the Schwarz lemma we have
for each
. Hence applying (3) we have

On the other hand,

Hence

is finite and analytic on
.
Now we proof
, in order to avoid tedious calculations, we may assume that
, For a fixed
we have

It easy to see that

Hence,

Denote
as follows

where
is defined in (4).
Now we obtain estimates for the norms of the weighted composition operator
.
Lemma 3 Suppose
, then
is bounded on
. Further more, there is a constant 
such that
. For each
.
Proof Let
, in which
,
and the function
is defined in (4).

and
. Hence we obtain that

Now we proof the main results.
The Proof of Theorem 1 For each
, by (5) we can obtain

Then by (1) and (6),

from which the result follows.
Remark When the Borel measure
is the common Lebesgue measure
, the Hausdorff operator arising from measure
is denoted as
.
is bounded on Hardy space
, see [3] .
However, it is unbounded on Lipschitz space. For example, fix
, and let
, it is easy to see that
, then

From this it follows that

NOTES
*This work is Supported by the Sichuan Provincial Natural Science Foundation (13ZB0101,13ZB0102).
#Corresponding author.