The Family of Global Attractors of Coupled Kirchhoff Equations

Abstract

In this paper, we study the initial boundary value problem of coupled generalized Kirchhoff equations. Firstly, the rigid term and nonlinear term of Kirchhoff equation are assumed appropriately to obtain the prior estimates of the equation in E0 and Ek space, and then the existence and uniqueness of solution is verified by Galerkin’s method. Then, the solution semigroup S(t) is defined, and the bounded absorptive set Bk is obtained on the basis of prior estimation. Through using Rellich-Kondrachov compact embedding theorem, it is proved that the solution semigroup S(t) has the family of the global attractors Ak in space Ek. Finally, by linearizing the equation, it is proved that the solution semigroup S(t) is Frechet differentiable on Ek, and the family of global attractors Ak have finite Hausdroff dimension and Fractal dimension.

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Lin, G. and Chen, F. (2022) The Family of Global Attractors of Coupled Kirchhoff Equations. Journal of Applied Mathematics and Physics, 10, 1651-1677. doi: 10.4236/jamp.2022.105115.

1. Introduction

This paper mainly studies the initial boundary value problem of the coupled generalized Kirchhoff equations:

{ u t t + M ( m u p p + m v 2 ) ( Δ ) 2 m u + β ( Δ ) 2 m u t + g 1 ( u t , v t ) = f 1 ( x ) , (1) v t t + M ( m u p p + m v 2 ) ( Δ ) 2 m v + β ( Δ ) 2 m v t + g 2 ( u t , v t ) = f 2 ( x ) , (2) u ( x , 0 ) = u 0 ( x ) , u t ( x , 0 ) = u 1 ( x ) , x Ω , (3) v ( x , 0 ) = v 0 ( x ) , v t ( x , 0 ) = v 1 ( x ) , x Ω , (4) i u n i = 0 , i v n i = 0 , ( i = 0 , 1 , 2 , , 2 m 1 ) , x Ω . ( 5 )

where Ω R n ( n 1 ) is a bounded domain with a smooth boundary Ω , g 1 ( u t , v t ) , g 2 ( u t , v t ) are nonlinear source terms, M ( m u p p + m v 2 ) ( Δ ) 2 m u , M ( m u p p + m v 2 ) ( Δ ) 2 m v are the rigid terms which M ( m u p p + m v 2 ) is

real function, f 1 ( x ) , f 2 ( x ) are the external force disturbance, and β ( Δ ) 2 m u t , β ( Δ ) 2 m v t ( β 0 ) are strong dissipative terms. Assumption of rigid and nonlinear source term will be presented at the back, to get the equation of the long time behavior of some theoretical results.

Kirchhoff equation is an important nonlinear wave equation. In 1883, when studying the free vibration of elastic strings, Kirchhoff [1] proposed a physical model

ρ h 2 u 2 t + δ u t = P 0 + E h 2 L ( 0 L | u x | 2 d x ) + f ( x ) , 0 < x < L , t > 0 .

where t is the time variable, E is the elastic modulus, h is the cross-sectional area, L is the length of the string, ρ is the mass density, P 0 is the initial axial tension, δ is the drag coefficient, f ( x ) is the external force term, and u = u ( x , t ) is the transverse displacement of space time t and coordinates x. This equation describes the movement of the elastic rod more accurately than the classical wave equation. Subsequently, many scholars have studied the existence, regularity, decay, and asymptotic behavior of global solutions of Kirchhoff equations with strong damping or dissipative terms.

Masamro [2] studied the initial boundary value problem for a class of Kirchhoff type equations with dissipative and damping terms

{ u t t M ( u 2 ) Δ u + δ | u | ρ u + γ u t = f ( x ) , x Ω , t > 0 , u ( x , t ) = 0 , x Ω , t 0 , u ( x , 0 ) = u 0 ( x ) , u t ( x , 0 ) = u 1 ( x ) , x Ω .

By using Galerkin’s method, the existence of global solution of the equation under initial boundary value condition is proved, where Ω R n is a bounded domain with smooth Boundary Ω , and δ > 0 , α 0 , γ 0 , M ( γ ) C 1 [ 0 , ) .

In reference [3], the initial boundary value problem of high-order strongly damped Kirchhoff equation is understood by studying the paper of Guoguang Lin and Chunmeng Zhou,

{ u t t + M ( m u p p ) ( Δ ) 2 m u + β ( Δ ) 2 m u t + | u | ρ u = f ( x ) , α > 0 , u ( x , 0 ) = u 0 ( x ) , u t ( x , 0 ) = u 1 ( x ) , x Ω , u ( x , t ) = j u v j , j = 1 , 2 , , 2 m 1 , x Ω .

where m > 0 , p 2 , Ω R n is the bounded domain with smooth boundary Ω , β > 0 is the dissipation coefficient, β ( Δ ) 2 m u t is the strong dissipative term, | u | ρ u is the nonlinear term among ρ 1 , and f ( x ) is the external term. The existence and uniqueness of the global solution and its continuous dependence on the initial value are proved by Galerkin’s method, and the existence and dimension of the global attractor are obtained.

Based on the above references, Guoguang Lin and Lingjuan Hu [4] studied nonlinear coupled Kirchhoff equations with strong damping

{ u t t + M ( m u 2 + m v 2 ) ( Δ ) m u + β ( Δ ) m u t + g 1 ( u , v ) = f 1 ( x ) , v t t + M ( m u 2 + m v 2 ) ( Δ ) m v + β ( Δ ) m v t + g 2 ( u , v ) = f 2 ( x ) , u ( x , 0 ) = u 0 ( x ) , u t ( x , 0 ) = u 1 ( x ) , x Ω , v ( x , 0 ) = v 0 ( x ) , v t ( x , 0 ) = v 1 ( x ) , x Ω , i u n i = 0 , i v n i = 0 , ( i = 0 , 1 , 2 , , m 1 ) , x Ω .

where Ω R n ( n 1 ) is a bounded domain with a smooth boundary Ω , g 1 ( u , v ) , g 2 ( u , v ) are nonlinear source term, f 1 ( x ) , f 2 ( x ) is the external force disturbance, M ( m u 2 + m v 2 ) ( Δ ) m u , M ( m u 2 + m v 2 ) ( Δ ) m v are rigid terms which M ( m u 2 + m v 2 ) is real function, β ( Δ ) m u t , and β ( Δ ) m v t ( β 0 ) are strong dissipative terms. The existence and uniqueness of the global solution and its continuous dependence on the initial value are proved by Galerkin’s method, and the existence and dimension of the global attractor are obtained.

On the basis of previous studies, this paper further improves the order of the strong dissipative term and the rigid term in Guoguang Lin and Lingjuan Hu [4], where the coefficient of the rigid term is extended from M ( m u 2 + m v 2 ) to

M ( m u p p + m v 2 ) .

With the progress of science and technology and the continuous development of mathematical physics equations, since the 1980s, Kirchhoff equations have been applied in lots of many fields such as Newtonian mechanics, ocean acoustics, cosmic physics, especially in engineering physics, measuring bridge vibration has played a huge role. Therefore, more and more scholars began to pay attention to and study the Kirchhoff equation in depth, including the existence and uniqueness of global solutions, a family of the global attractor, Hausdroff dimension and Fractal dimension, the existence of random attractors, energy decay and explosion of solutions, exponential attractors and inertia manifold, etc. And the relevant specific theoretical basis and research results can be found in the literature [5] - [17].

The main research ideas of this paper are that the existence and uniqueness of solution is verified by Galerkin’s method in E 0 and E k space. Then the solution semigroup S ( t ) is defined, and the bounded absorptive set B k is obtained on the basis of prior estimation. Through using Rellich-Kondrachov compact embedding theorem, it is proved that the solution semigroup S ( t ) has the family of the global attractors A k in space E k . Finally, by linearizing the equation, it is proved that the solution semigroup S ( t ) is Frechet differentiable on E k . So the family of global attractors A k has finite Hausdroff dimension and Fractal

dimension and d H ( A k ) < 3 7 N , d F ( A k ) < 6 7 N .

2. Existence and Uniqueness of Solutions

The following symbols and assumptions are introduced for the convenience of statement:

V 0 = L 2 ( Ω ) , V 2 m = H 2 m ( Ω ) H 0 1 ( Ω ) , V 2 m + k = H 2 m + k ( Ω ) H 0 1 ( Ω ) , V k = H k ( Ω ) H 0 1 ( Ω ) , E 0 = V 2 m × V 0 × V 2 m × V 0 , E k = V 2 m + k × V k × V 2 m + k × V k ( k = 1 , 2 , , 2 m ) .

The inner product of the L 2 ( Ω ) space is ( u , v ) = Ω u ( x ) v ( x ) d x and the norm

is u = u L 2 = ( Ω | u ( x ) | 2 d x ) 1 2 , the norm of L p ( Ω ) space is called u p = u L p ( Ω ) , A k are the family of global attractors, B k is the bounded absorption set of E k , where k = 1 , 2 , , 2 m . C i and C ( R l ) ( l = 1 , 2 , , k ) are constant.

w = u t + ε u , q = v t + ε v , where u , v is the solution of the problem (1)-(5);

u ¯ = u 1 u 2 , v ¯ = v 1 v 2 , where u 1 , u 2 , v 1 , v 2 are the two solutions of the problem (1)-(5);

W = U t + ε U , Q = V t + ε V , where U , V is the solution of the linear initial boundary value problem (66);

y = u _ u U and z = v _ v V is the solution of the problem (67)-(68).

The rigid term and nonlinear source term are assumed as follows:

(H1) M ( s ) = M ( m u p p + m v 2 ) and M ( s ) C 2 ( R + ) ;

(H2) m * M ( s ) m * 1 μ = { m * d d t 2 m u 0 m * d d t 2 m u 0 ;

(H3) g 1 ( u t , v t ) , g 2 ( u t , v t ) C k ( k = 1 , 2 , , 2 m ) , ( g 1 ( u t , v t ) , w ) + ( g 2 ( u t , v t ) , q ) α ( w 2 + q 2 ) ε ( u 2 + v 2 ) γ ( u t 2 + v t 2 ) , where γ is related to α and ε ;

(H4) β 2 γ λ 1 2 m 0 , β 2 C 0 2 ε λ 1 2 m 0 ;

(H5) 0 < ε < min { 1 3 α , β λ 1 2 m + ( β λ 1 2 m ) 2 16 ( 1 m * λ 1 2 m ) 2 , 4 m * λ 1 2 m β λ 1 2 m 2 , ( 4 C 0 ) + ( 4 C 0 ) 2 + β λ 1 2 m 2 } .

Lemma 1. Assuming (H1)-(H5) are true, letting ( u 0 , w 0 , v 0 , q 0 ) E 0 , f 1 ( x ) , f 2 ( x ) L 2 ( Ω ) , then there is a solution ( u , w , v , q ) for problem (1)-(5), which has the following properties:

(i) ( u , w , v , q ) L ( ( 0 , + ) ; E 0 ) ;

(ii) ( u , w , v , q ) E 0 = 2 m u 2 + w 2 + 2 m v 2 + q 2 y ( 0 ) ¯ e α 0 t + C 0 2 α 0 ε β 2 0 T 2 m w 2 + 2 m q 2 d t C 0 2 ε T + y ( 0 ) ¯ ;

(iii) There are normal numbers C ( R 0 ) and t t 0 , such that

( u , w , v , q ) E 0 2 = 2 m u 2 + w 2 + 2 m v 2 + q 2 C ( R 0 ) ,

where y ( 0 ) ¯ = ( μ + ε β 2 ) ( 2 m u 0 2 + w 0 2 + 2 m v 0 2 + q 0 2 ) .

Proof: Let w = u t + ε u inner product with Equation (1),

( u t t + M ( m u p p + m v 2 ) ( Δ ) 2 m u + β ( Δ ) 2 m u t + g 1 ( u t , v t ) , w ) = ( f 1 ( x ) , w ) .(6)

Some items are treated as follows:

( u t t , w ) = 1 2 d d t w 2 ε w 2 + ε 2 ( u , w ) , (7)

( M ( s ) ( Δ ) 2 m u , w ) = M ( s ) 2 d d t 2 m u 2 + ε M ( s ) 2 m u 2 μ 2 d d t 2 m u 2 + ε m * 2 m u 2 , (8)

( β ( Δ ) 2 m u t , w ) = ( β 2 2 m u t , 2 m u t + ε 2 m u ) + β 2 ( 2 m w ε 2 m u , 2 m w ) = β 2 2 m u t 2 + ε β 4 d d t 2 m u 2 + β 2 2 m w 2 β ε 2 ( 2 m u , 2 m w ) , (9)

( g 1 ( u t , v t ) , w ) + ( g 2 ( u t , v t ) , q ) α ( w 2 + q 2 ) ε ( u 2 + v 2 ) γ ( u t 2 + v t 2 ) . (10)

Similarly, letting q = v t + ε v inner product with Equation (2),

( v t t + M ( m u p p + m v 2 ) ( Δ ) 2 m v + β ( Δ ) 2 m v t + g 2 ( u t , v t ) , q ) = ( f 2 ( x ) , q ) .(11)

The treatment of each item is similar to (7)-(10), and the above results are sorted out,

1 2 d d t [ ( μ 1 + ε β 2 ) ( 2 m u 2 + 2 m v 2 ) + w 2 + q 2 ] + ( α ε ) ( w 2 + q 2 ) + ε m * ( 2 m u 2 + 2 m v 2 ) + ε 2 [ ( u , w ) + ( v , q ) ] ε ( u 2 + v 2 ) + β 2 ( 2 m u t 2 + 2 m v t 2 ) γ ( u t 2 + v t 2 ) + β 2 ( 2 m w 2 + 2 m q 2 ) β ε 2 [ ( 2 m u , 2 m w ) + ( 2 m v , 2 m q ) ] ( f 1 ( x ) , w ) + ( f 2 ( x ) , q ) . (12)

Some terms are treated as follows by using Holder’s inequality, Young’s inequality and Poincare’s inequality

ε 2 [ ( u , w ) + ( v , q ) ] ε ( u 2 + v 2 ) ε ( w 2 + q 2 ) ( ε 3 4 + ε ) ( u 2 + v 2 ) , (13)

( ε 3 4 + ε ) ( u 2 + v 2 ) 1 λ 1 2 m ( ε 3 4 + ε ) ( 2 m u 2 + 2 m v 2 ) , (14)

γ ( u t 2 + v t 2 ) γ λ 1 2 m ( 2 m u t 2 + 2 m v t 2 ) , (15)

β ε 2 [ ( 2 m u , 2 m w ) + ( 2 m v , 2 m q ) ] β 4 ( 2 m w 2 + 2 m q 2 ) β ε 2 4 ( 2 m u 2 + 2 m v 2 ) , (16)

( f 1 ( x ) , w ) + ( f 2 ( x ) , q ) ε ( w 2 + q 2 ) + 1 4 ε ( f 1 ( x ) 2 + f 2 ( x ) 2 ) . (17)

Insert the inequality (13)-(17) into Equation (12), and get

1 2 d d t [ ( μ + ε β 2 ) ( 2 m u 2 + 2 m v 2 ) + w 2 + q 2 ] + ( α 3 ε ) ( w 2 + q 2 ) + ( ε m * β ε 2 4 ε 3 + 4 ε 4 λ 1 2 m ) ( 2 m u 2 + 2 m v 2 ) + β 4 ( 2 m w 2 + 2 m q 2 ) + ( β 2 γ λ 1 2 m ) ( 2 m u t 2 + 2 m v t 2 ) 1 4 ε ( f 1 ( x ) 2 + f 2 ( x ) 2 ) , (18)

letting 0 < ε < min { 1 3 α , β λ 1 2 m + ( β λ 1 2 m ) 2 16 ( 1 m * λ 1 2 m ) 2 } , β 2 γ λ 1 2 m 0 , β 0 and finally the above Equation (18) is simplified as:

d d t [ ( μ + ε β 2 ) ( 2 m u 2 + 2 m v 2 ) + w 2 + q 2 ] + 2 ( α 3 ε ) ( w 2 + q 2 ) + 2 ( ε m * β ε 2 4 ε 3 + 4 ε 4 λ 1 2 m ) ( 2 m u 2 + 2 m v 2 ) + β 2 ( 2 m w 2 + 2 m q 2 ) 1 2 ε ( f 1 ( x ) 2 + f 2 ( x ) 2 ) , (19)

then (19) is finally simplified as:

d d t y ( t ) ¯ + α 0 y ( t ) ¯ + β 2 ( 2 m w 2 + 2 m q 2 ) C 0 2 ε , (20)

where y ( t ) ¯ = ( μ + ε β 2 ) ( 2 m u 2 + 2 m v 2 ) + w 2 + q 2 , α 0 = min { 2 ( α 3 ε ) , 4 ε m * λ 1 2 m β ε 2 λ 1 2 m ε 3 + 4 ε ( 2 μ + ε β ) λ 1 2 m } .

By using the Gronwall’s inequality,

y ( t ) ¯ y ( 0 ) ¯ e α 0 t + C 0 2 ε α 0 , (21)

β 2 0 T 2 m w 2 + 2 m q 2 d t C 0 2 ε T + y ( 0 ) ¯ , (22)

where y ( 0 ) ¯ = ( μ + ε β 2 ) ( 2 m u 0 2 + w 0 2 + 2 m v 0 2 + q 0 2 ) , so there are normal numbers C ( R 0 ) = C 0 α 0 ε and t 0 = | 1 ε ln C | 2 ε α 0 | | y ( 0 ) ¯ | | , when t > t 0 ,

( u , w , v , q ) E 0 2 = 2 m u 2 + w 2 + 2 m v 2 + q 2 y ( t ) ¯ min { μ + ε β 2 , 1 } C ( R 0 ) . (23)

Lemma 1 is proved.

Lemma 2. Assuming (H1)-(H5) are true, letting ( u 0 , w 0 , v 0 , q 0 ) E k , f 1 ( x ) , f 2 ( x ) H k ( Ω ) , g 1 ( u t , v t ) , g 2 ( u t , v t ) C k where k = 1 , 2 , , 2 m , then there is a solution ( u , w , v , q ) for problem (1)-(5), which has the following properties:

(i) ( u , w , v , q ) L ( ( 0 , + ) ; E k ) , ( k = 1 , 2 , , 2 m ) ;

(ii)

( u , w , v , q ) E k = 2 m + k u 2 + k w 2 + 2 m + k v 2 + k q 2 y 1 ( 0 ) ¯ e α 1 t + C 2 2 α 1 ε ,

β 4 0 T 2 m + k w 2 + 2 m + k q 2 d t C 2 2 ε T + y 1 ( 0 ) ¯ ;

(iii) There are normal numbers C ( R k ) and t t 0 k , such that

( u , w , v , q ) Ε k 2 = 2 m + k u 2 + k w 2 + 2 m + k v 2 + k q 2 C ( R k ) ,

where y 1 ( 0 ) ¯ = ( μ + ε β 2 ) ( 2 m + k u 0 2 + k w 0 2 + 2 m + k v 0 2 + k q 0 2 ) .

Proof: Let ( Δ ) k w = ( Δ ) k u t + ε ( Δ ) k u inner product with Equation (1),

( u t t + M ( D m u p p + D m v 2 ) ( Δ ) 2 m u + β ( Δ ) 2 m u t + g 1 ( u t , v t ) , ( Δ ) k w ) = ( f 1 ( x ) , ( Δ ) k w ) . (24)

Some items are treated as follows:

( u t t , ( Δ ) k w ) = 1 2 d d t k w 2 ε k w 2 + ε 2 ( k u , k w ) , (25)

( M ( s ) ( Δ ) 2 m u , ( Δ ) k w ) = M ( s ) 2 d d t 2 m + k u 2 + ε M ( s ) 2 m + k u 2 μ 2 d d t 2 m + k u 2 + ε m * 2 m + k u 2 , (26)

( β ( Δ ) 2 m u t , ( Δ ) k w ) = ( β 2 Δ 2 m u t , 2 m + k u t + ε 2 m + k u ) + β 2 ( 2 m + k w ε 2 m + k u , 2 m + k w ) = β 2 2 m + k u t 2 + ε β 4 d d t 2 m + k u 2 + β 2 2 m + k w 2 β ε 2 ( 2 m + k u , 2 m + k w ) , (27)

( g 1 ( u t , v t ) , ( Δ ) k w ) + ( g 2 ( u t , v t ) , ( Δ ) k q ) k g 1 ( u t , v t ) k w + k g 2 ( u t , v t ) k q C 1 ( k u t k w + k v t k q ) C 1 2 λ 1 2 m ε ( 2 m + k u t 2 + 2 m + k v t 2 ) + ε C 1 2 ( k w 2 + k q 2 ) . (28)

Similarly, letting ( Δ ) k q = ( Δ ) k v t + ε ( Δ ) k v inner product with Equation (2),

( v t t + M ( m u p p + m v 2 ) ( Δ ) 2 m v + β ( Δ ) 2 m v t + g 2 ( u t , v t ) , ( Δ ) k q ) = ( f 2 ( x ) , ( Δ ) k q ) . (29)

The treatment of each item is similar to (25)-(28), and the above results are sorted out,

1 2 d d t [ ( μ + ε β 2 ) ( 2 m + k u 2 + 2 m + k v 2 ) + k w 2 + k q 2 ] ( ε + ε C 0 2 ) ( k w 2 + k q 2 ) + ε m * ( 2 m + k u 2 + 2 m + k v 2 ) + ε 2 [ ( k u , k w ) + ( k v , k q ) ] + ( β 2 C 0 2 λ 1 2 m ε ) ( 2 m + k u t 2 + 2 m + k v t 2 ) + β 2 ( 2 m + k w 2 + 2 m + k q 2 ) β ε 2 [ ( 2 m + k u , 2 m + k w ) + ( 2 m + k v , 2 m + k q ) ] ( f 1 ( x ) , ( Δ ) k w ) + ( f 2 ( x ) , ( Δ ) k q ) . (30)

Some terms are treated as follows by using Holder’s inequality, Young’s inequality and Poincare’s inequality

ε 2 [ ( k u , w w ) + ( k v , k q ) ] ε 2 2 ( k w 2 + k q 2 ) ε 2 2 ( k u 2 + k v 2 ) ε 2 2 ( k w 2 + k q 2 ) ε 2 2 λ 1 2 m ( 2 m + k u 2 + 2 m + k v 2 ) , (31)

β ε 2 [ ( 2 m + k u , 2 m + k w ) + ( 2 m + k v , 2 m + k q ) ] β 4 ( 2 m + k w 2 + 2 m + k q 2 ) β ε 2 4 ( 2 m + k u 2 + 2 m + k v 2 ) , (32)

( f 1 ( x ) , ( Δ ) k w ) + ( f 2 ( x ) , ( Δ ) k q ) ε ( k w 2 + k q 2 ) + 1 4 ε ( k f 1 ( x ) 2 + k f 2 ( x ) 2 ) . (33)

Insert the inequality (31)-(33) into Equation (30), get

1 2 d d t [ ( μ + ε β 2 ) ( 2 m + k u 2 + 2 m + k v 2 ) + k w 2 + k q 2 ] + ( ε m * β ε 2 4 ε 2 2 λ 1 2 m ) ( 2 m + k u 2 + 2 m + k v 2 )

+ ( β 2 C 1 2 ε λ 1 2 m ) ( 2 m + k u t 2 + 2 m + k v t 2 ) + ( β λ 1 2 m 8 2 ε ε 2 C 1 ε 2 ) ( k w 2 + k q 2 ) + β 8 ( 2 m + k w 2 + 2 m + k q 2 ) 1 4 ε ( k f 1 ( x ) 2 + k f 2 ( x ) 2 ) , (34)

assuming 0 < ε < min { 4 m * λ 1 2 m β λ 1 2 m 2 , ( 4 C 1 ) + ( 4 C 1 ) 2 + β λ 1 2 m 2 } , β 2 C 1 2 ε λ 1 2 m 0 , β 0 and finally the above Equation (18) is simplified as:

d d t [ ( μ + ε β 2 ) ( 2 m + k u 2 + 2 m + k v 2 ) + k w 2 + k q 2 ] + 2 ( ε m * β ε 2 4 ε 2 2 λ 1 2 m ) ( 2 m + k u 2 + 2 m + k v 2 ) + 2 ( β λ 1 2 m 8 2 ε ε 2 C 1 ε 2 ) ( k w 2 + k q 2 ) + β 4 ( 2 m + k w 2 + 2 m + k q 2 ) 1 2 ε ( k f 1 ( x ) 2 + k f 2 ( x ) 2 ) , (35)

then (35) is finally simplified as:

d d t y 1 ( t ) ¯ + α 1 y 1 ( t ) ¯ + β 4 ( 2 m + k w 2 + 2 m + k q 2 ) C 2 2 ε , (36)

where y 1 ( t ) ¯ = ( μ + ε β 2 ) ( 2 m + k u 2 + 2 m + k v 2 ) + k w 2 + k q 2 , α 1 = min { 4 λ 1 2 m ε m * β ε 2 λ 1 2 m ε 2 ( 2 μ + ε β ) λ 1 2 m , 2 ( β λ 1 2 m 8 2 ε ε 2 C 1 ε 2 ) } .

By using the Gronwall’s inequality,

y 1 ( t ) ¯ y 1 ( 0 ) ¯ e α 1 t + C 2 2 ε α 1 , (37)

β 4 0 T 2 m + k w 2 + 2 m + k q 2 d t C 2 2 ε T + y 1 ( 0 ) ¯ , (38)

where y 1 ( 0 ) ¯ = ( μ + ε β 2 ) ( 2 m + k u 0 2 + k w 0 2 + 2 m + k v 0 2 + k q 0 2 ) , so there are normal numbers C ( R k ) = C 2 ε α 1 and t 0 k = | 1 α 1 ln C 2 | 2 ε α 1 | | y 1 ( 0 ) ¯ | | , when t t 0 k ,

( u , w , v , q ) Ε k 2 = 2 m + k u 2 + k w 2 + 2 m + k v 2 + k q 2 y 1 ( t ) ¯ min { μ + ε β 2 , 1 } C ( R k ) (39)

Lemma 2 is proved.

Theorem 1. Assuming (H1)-(H5) is true, ( u 0 , w 0 , v 0 , q 0 ) E k , f 1 ( x ) , f 2 ( x ) H k ( Ω ) , g 1 ( u t , v t ) , g 2 ( u t , v t ) C 2 , then the initial boundary value problem (1)-(5) has a unique solution

( u ( x , t ) , w ( x , t ) , v ( x , t ) , q ( x , t ) ) L ( ( 0 , + ) ; Ε k ) ( k = 0 , 1 , 2 , , 2 m ) .

Proof: First, the existence of the solution is proved by Galerkin’s method:

Step 1: Approximate solution

( Δ ) 2 m + k ω j = λ j 2 m + k ω j ( k = 0 , 1 , 2 , , 2 m ) , where λ j represents the eigenvalue of ( Δ ) with homogeneous Dirichlet boundary on Ω , ω j represents the eigenfunction determined by corresponding eigenvalue λ j , and ω 1 , ω 2 , , ω h , constitute the normal orthonormal basis of H 2 m + k ( Ω ) .

Assuming u h = u h ( t ) = j = 1 h g j h ( t ) ω j , v h = v h ( t ) = j = 1 h f j h ( t ) ω j are approximate solutions of the initial boundary value problem (1)-(5), it is obvious that ( u h , v h ) is dense in H 2 m + k × H 2 m + k , where g j h ( t ) , f j h ( t ) is determined by the following conditions

{ ( u h + M ( m u h p p + m v h 2 ) ( Δ ) 2 m u h + β ( Δ ) 2 m u h + g 1 ( u h , v h ) , ( Δ ) k ω j ) = ( f 1 ( x ) , ( Δ ) k ω j ) , ( 40 ) ( v h + M ( m u h p p + m v h 2 ) ( Δ ) 2 m v h + β ( Δ ) 2 m v h + g 2 ( u h , v h ) , ( Δ ) k ω j ) = ( f 2 ( x ) , ( Δ ) k ω j ) , ( 41 )

where j = 1 , 2 , , h . And the nonlinear ordinary differential Equations (40) and (41) satisfy the initial conditions

u h ( 0 ) = u 0 h = j = 1 h α j h ω j u 0 , ( h ) in H 0 2 m + k ( Ω ) L 2 ( Ω ) , (42)

u h ( 0 ) = u 1 h = j = 1 h β j h ω j u 1 , ( h ) in H 0 k ( Ω ) L 2 ( Ω ) , (43)

v h ( 0 ) = v 0 h = j = 1 h α j h ω j v 0 , ( h ) in H 0 2 m + k ( Ω ) L 2 ( Ω ) , (44)

v h ( 0 ) = v 1 h = j = 1 h β j h ω j v 1 , ( h ) in H 0 k ( Ω ) L 2 ( Ω ) , (45)

so when h , ( u o h , u 1 h , v o h , u 1 h ) ( u o , u 1 , v o , u 1 ) is in E k .

The general results of nonlinear ordinary differential equations guarantee the existence of approximate solutions on the interval [ 0 , t h ] .

Step 2: prior estimation

Multiply both sides of the Equation (40) by g j h ( t ) + ε g j h ( t ) and sum over j; in the same way, multiply both sides of the Equation (41) by f j h ( t ) + ε f j h ( t ) and sum over j. Let w h ( t ) = u h ( t ) + ε u h ( t ) , q h ( t ) = v h ( t ) + ε v h ( t ) , and according to the prior estimation in Lemma 2, can be obtained

( u h , w h , v h , q h ) E k = 2 m + k u h 2 + k w h 2 + 2 m + k v h 2 + k q h 2 C ( R k ) ,(46)

β 4 0 T 2 m + k w 2 + 2 m + k q 2 d t C 2 2 ε T + y 1 ( 0 ) ¯ . (47)

According to (46), ( u h , w h , v h , q h ) is bounded in L ( [ 0 , + ) ; E k ) and it can be seen from (47) that w h is bounded in L 2 ( ( 0 , T ) ; H 0 2 m + k ) and q h is bounded in L 2 ( ( 0 , T ) ; H 0 2 m + k ) .

Step 3: Limit process

According to the Danford-Pttes theorem, L ( [ 0 , + ) ; E k ) is conjugate to L 1 ( [ 0 , + ) ; E k ) , L 2 ( ( 0 , T ) ; H 0 2 m + k ) is conjugate to L 2 ( ( 0 , T ) ; H 0 2 m + k ) , and we can pick subsequence { u s } from sequence { u h } and subsequence { v s } from sequence { v h } , such that

( u s , w s , v s , q s ) ( u , w , v , q ) is weak * convergence in L ( [ 0 , + ) ; E k ) . (48)

By the Rellich-Kondrachov compact embedding theorem, E k is compactly embedding in E 0 , ( u s , w s , v s , q s ) ( u , w , v , q ) is strong convergence in L 2 ( [ 0 , + ) ; E 0 ) almost everywhere.

In Equations (40) and (41) above, letting h = s , and taking the limit, for fixed j and s > j , get

{ ( u s + M ( m u s p p + m v s 2 ) ( Δ ) 2 m u s + β ( Δ ) 2 m u s + g 1 ( u s , v s ) , ( Δ ) k ω j ) = ( f 1 ( x ) , ( Δ ) k ω j ) , ( 49 ) ( v s + M ( m u s p p + m v s 2 ) ( Δ ) 2 m v s + β ( Δ ) 2 m v s + g 2 ( u s , v s ) , ( Δ ) k ω j ) = ( f 2 ( x ) , ( Δ ) k ω j ) . ( 50 )

According to Equation (48) above, it can be concluded that

( u s ( t ) , ( Δ ) k ω j ) ( u ( t ) , λ j k ω j ) is weak * convergence in L [ 0 , + ) ,

( u s ( t ) , ( Δ ) k ω j ) ( u ( t ) , λ j k ω j ) is weak * convergence in L [ 0 , + ) .

So ( u s ( t ) , ( Δ ) k ω j ) = d d t ( u s ( t ) , ( Δ ) k ω j ) ( u ( t ) , λ j k ω j ) converges in D [ 0 , + ) , and similarly ( v s ( t ) , ( Δ ) k ω j ) = d d t ( v s ( t ) , ( Δ ) k ω j ) ( v ( t ) , λ j k ω j ) converges in D [ 0 , + ) , where D [ 0 , + ) is the dual space of D [ 0 , + ) ; ( M ( m u s p p + m v s 2 ) ( Δ ) 2 m u s , ( Δ ) k ω j ) ( M ( m u p p + m v 2 ) ( ) 2 m + k u , λ j 2 m + k 2 ω j ) is weak * convergence in L [ 0 , + ) , similarly ( M ( m u s p p + m v s 2 ) ( Δ ) 2 m v s , ( Δ ) k ω j ) ( M ( m u p p + m v 2 ) ( ) 2 m + k v , λ j 2 m + k 2 ω j ) is weak * convergence in L [ 0 , + ) ;

( β ( Δ ) 2 m u s , ( Δ ) k ω j ) = ( β ( Δ ) 2 m w s , ( Δ ) k ω j ) ( β ( Δ ) 2 m ε u s , ( Δ ) k ω j ) = ( β ( Δ ) k 2 w s , ( Δ ) 2 m + k 2 ω j ) β ε ( ( Δ ) 2 m + k 2 u s , ( Δ ) 2 m + k 2 ω j ) ,

so ( β ( Δ ) 2 m u s , ( Δ ) k ω j ) β ( ( Δ ) k 2 w , λ j 2 m + k 2 ω j ) β ε ( ( Δ ) 2 m + k 2 u , λ j 2 m + k 2 ω j ) is weak * convergence in L [ 0 , + ) , similarly ( β ( Δ ) 2 m v s , ( Δ ) k ω j ) β ( ( Δ ) k 2 q , λ j 2 m + k 2 ω j ) β ε ( ( Δ ) 2 m + k 2 v , λ j 2 m + k 2 ω j ) is weak * convergence in L [ 0 , + ) ; ( f 1 ( x ) , ( Δ ) k ω j ) ( ( Δ ) k 2 f 1 ( x ) , λ j k ω j ) is weak * convergence in L [ 0 , + ) , similarly ( f 2 ( x ) , ( Δ ) k ω j ) ( ( Δ ) k 2 f 2 ( x ) , λ j k ω j ) is weak * convergence in L [ 0 , + ) .

So Equations (49) and (50) above can be deduced that

{ ( u + M ( m u p p + m v 2 ) ( Δ ) 2 m u + β ( Δ ) 2 m u + g 1 ( u , v ) , ( Δ ) k ω j ) = ( f 1 ( x ) , ( Δ ) k ω j ) , ( v + M ( m u p p + m v 2 ) ( Δ ) 2 m v + β ( Δ ) 2 m v + g 2 ( u , v ) , ( Δ ) k ω j ) = ( f 2 ( x ) , ( Δ ) k ω j ) .

It’s true for any j, and from the density of ω 1 , ω 2 , , ω h , can obtain

{ ( u + M ( m u p p + m v 2 ) ( Δ ) 2 m u + β ( Δ ) 2 m u + g 1 ( u , v ) , ( Δ ) k w ) = ( f 1 ( x ) , ( Δ ) k w ) , ( v + M ( m u p p + m v 2 ) ( Δ ) 2 m v + β ( Δ ) 2 m v + g 2 ( u , v ) , ( Δ ) k q ) = ( f 2 ( x ) , ( Δ ) k q ) ,

w H k H 0 1 , q H k H 0 1 .

The existence is proved.

Then, prove the uniqueness of the solution:

Assuming u 1 , u 2 , v 1 , v 2 are the two solutions of the problem (1)-(5), letting u ¯ = u 1 u 2 , v ¯ = v 1 v 2 , from the initial boundary value problem (1)-(5), obtain that

{ u t t ¯ + M ( s 1 ) ( Δ ) 2 m u 1 M ( s 2 ) ( Δ ) 2 m u 2 β ( Δ ) 2 m u t ¯ = g 1 ( u 2 t , v 2 t ) g 1 ( u 1 t , v 1 t ) , v t t ¯ + M ( s 1 ) ( Δ ) 2 m v 1 M ( s 2 ) ( Δ ) 2 m v 2 β ( Δ ) 2 m v t ¯ = g 2 ( u 2 t , v 2 t ) g 2 ( u 1 t , v 1 t ) , u ¯ ( x , 0 ) = 0 , u t ¯ ( x , 0 ) = 0 , x Ω , v ¯ ( x , 0 ) = 0 , v t ¯ ( x , 0 ) = 0 , x Ω , i u ¯ i n = 0 , i v ¯ i n = 0 , ( i = 0 , 1 , 2 , , 2 m 1 ) , (51)

where s 1 = M ( m u 1 p p + m v 1 2 ) , s 2 = M ( m u 2 p p + m v 2 2 ) .

Let u t ¯ inner product with the first equation of the above (51) and obtain

( u t t ¯ + M ( s 1 ) ( Δ ) 2 m u 1 M ( s 2 ) ( Δ ) 2 m u 2 β ( Δ ) 2 m u t ¯ , u t ¯ ) = ( g 1 ( u 2 t , v 2 t ) g 1 ( u 1 t , v 1 t ) , u t ¯ ) . (52)

Some items are treated as follows

( u t t ¯ , u t ¯ ) = 1 2 d d t u t ¯ , (53)

( β ( Δ ) 2 m u t ¯ , u t ¯ ) = β 2 m u t ¯ 2 , (54)

| ( M ( s 1 ) ( Δ ) 2 m u 1 M ( s 2 ) ( Δ ) 2 m u 2 , u t ¯ ) | = | ( M ( s 1 ) ( Δ ) 2 m u ¯ , u t ¯ ) + ( M ( s 1 ) ( Δ ) 2 m u 2 M ( s 2 ) ( Δ ) 2 m u 2 , u t ¯ ) | μ 2 d d t 2 m u ¯ 2 | ( M ( s 1 ) M ( s 2 ) ) ( ( Δ ) 2 m u 2 , u t ¯ ) | . (55)

Part of the above formula (55) is treated as follows

| ( M ( s 1 ) M ( s 2 ) ) ( ( Δ ) 2 m u 2 , u t ¯ ) | M ( χ ) | m u 1 p p m u 2 p p + m v 1 2 m v 2 2 | 2 m u 2 2 m u t ¯ M ( χ ) | m u 1 p p m u 2 p p | 2 m u 2 2 m u t ¯ + M ( χ ) | m v 1 2 m v 2 2 | 2 m u 2 2 m u t ¯ , (56)

where χ ( s 1 , s 2 ) ; by using Holder’s inequality, Young’s inequality and Poincare’s inequality, (56) is treated as follows,

M ( χ ) | m u 1 p p m u 2 p p | 2 m u 2 2 m u t ¯ p M ( χ ) χ 1 p 1 p 1 m u ¯ 2 m u 2 2 m u t ¯ C 3 1 λ 1 m 2 2 m u ¯ 2 m u t ¯ C 3 2 ε λ 1 m 2 m u ¯ 2 + ε C 3 2 2 m u t ¯ 2 , (57)

where χ 1 ( m u 1 , m u 2 ) ,

M ( χ ) | m v 1 2 m v 2 2 | 2 m u 2 2 m u t ¯ M ( χ ) | m v 1 m v 2 | m v ¯ 2 m u 2 2 m u t ¯ C 4 1 λ 1 m 2 m v ¯ 2 m u t ¯ C 4 2 ε λ 1 m 2 m v ¯ 2 + ε C 4 2 2 m u t ¯ 2 . (58)

Through the (56)-(58), finally (55) will become

| ( M ( s 1 ) ( Δ ) 2 m u 1 M ( s 2 ) ( Δ ) 2 m u 2 , u t ¯ ) | μ 2 d d t 2 m v ¯ 2 C 3 2 ε λ 1 m 2 m u ¯ 2 C 4 2 ε λ 1 m 2 m v ¯ 2 ε ( C 3 + C 4 ) 2 2 m u t ¯ 2 . (59)

Then, according to the mean value theorem, the nonlinear source term is treated as follows,

| ( g 1 ( u 2 t , v 2 t ) g 1 ( u 1 t , v 1 t ) , u t ¯ ) | | ( g 1 ( u 2 t , v 2 t ) g 1 ( u 2 t , v 1 t ) , u t ¯ ) | + | ( g 1 ( u 2 t , v 1 t ) g 1 ( u 1 t , v 1 t ) , u t ¯ ) |

= | g 1 ( u 2 t , χ 2 ) ( v t ¯ , u t ¯ ) | + | g 1 ( χ 3 , v 1 t ) ( u t ¯ , u t ¯ ) | g 1 ( u 2 t , χ 2 ) v t ¯ u t ¯ + g 1 ( χ 3 , v 1 t ) u t ¯ 2 C 5 ( ε 2 v t ¯ 2 + 1 2 ε u t ¯ 2 ) + C 6 u t ¯ 2 . (60)

Similarly, Let v t ¯ inner product with the second equation of the above (51) and obtain

( v t t ¯ + M ( s 1 ) ( Δ ) 2 m v 1 M ( s 2 ) ( Δ ) 2 m v 2 β ( Δ ) 2 m v t ¯ , v t ¯ ) = ( g 2 ( u 2 t , v 2 t ) g 2 ( u 1 t , v 1 t ) , v t ¯ ) . (61)

The treatment of some items in (61) is similar to that (53)-(59), and the above results are sorted out that

d d t ( μ ( 2 m u ¯ 2 + 2 m v ¯ 2 ) + u t ¯ 2 + v t ¯ 2 ) + ( 2 β + ( C 3 + C 4 ) ε ) ( 2 m u t ¯ 2 + 2 m v t ¯ 2 ) 2 C 7 ε λ 1 2 m ( m u ¯ 2 + m u ¯ 2 ) + ( 2 C 8 + C 8 + ε 2 C 8 ε ) ( u t ¯ 2 + v t ¯ 2 ) , (62)

where C 7 = max { C 4 , C 3 } , C 8 = max { C 5 , C 6 } .

So

d d t y 2 ( t ) ¯ α 2 y 2 ( t ) ¯ (63)

where y 2 ( t ) ¯ = μ ( 2 m u ¯ 2 + 2 m v ¯ 2 ) + u t ¯ 2 + v t ¯ 2 , α 2 = max { 2 C 7 ε λ 1 2 m , ( 2 C 8 μ + C 8 + ε 2 C 8 ε μ ) } , according to Gronwall’s inequality

y 2 ( t ) ¯ y 2 ( 0 ) ¯ e α 2 t , (64)

where

y 2 ( 0 ) ¯ = 0 , (65)

then μ ( 2 m u ¯ 2 + 2 m v ¯ 2 ) + u t ¯ 2 + v t ¯ 2 = 0 , so 2 m u ¯ = 2 m v ¯ = u t ¯ = v t ¯ = 0 .

Theorem 1 is proved.

3. The Family of Global Attractors and Dimension Estimation

Theorem 2. [7] Assume E is a Banach space, and { S ( t ) } t 0 is the operator semigroup on E,

S ( t ) : E E , S ( t + r ) = S ( t ) + S ( r ) ( t , r > 0 ) , S ( 0 ) = I

where I is the identity operator, if S ( t ) satisfies

1) Semigroup S ( t ) is uniformly bounded in E, i.e. R > 0 , exists a constant C ( R ) such that when u E R , T, there is S ( t ) u E C ( R ) ( t [ 0 , ) ) ;

2) There exists a bounded absorbing set B 0 in E, that is, for any bounded set B E , there exists a constant t 0 > 0 , such that S ( t ) B B 0 ( t t 0 ) ;

3) { S ( t ) } t 0 is completely continuous operator;

then operator semigroup S ( t ) has compact global attractor A.

In theorem 2, if S ( t ) is a solution semigroup generated by the initial boundary value problem (1)-(5), ( u ( t ) , w ( t ) , v ( t ) , q ( t ) ) = S ( t ) ( u 0 , w 0 , v 0 , q 0 ) , and Banach space E is changed into Hilbert space E k , there are the family of global attractors.

Theorem 3. Let S ( t ) is a solution semigroup generated by the initial boundary value problems (1)-(5) under the hypothesis of lemma 1 and lemma 2, then the initial boundary value problems (1)-(5) have the family of global attractors. There are compact sets satisfying:

A k E k E 0 ( k = 1 , 2 , , 2 m ) , and A k = ω ( B k ) = s 0 t s S ( t ) B k ¯ ,

where B k = { ( u , w , v , q ) E k : 2 m + k u 2 + k w 2 + 2 m + k v 2 + k q 2 C ( R k ) } ,

1) S ( t ) A k = A k ;

2) A k attracts all bounded sets of E k , that is, any bounded set B k E k , having

lim t d i s t ( S ( t ) B k , A k ) = 0 , where d i s t ( S ( t ) B k , A k ) = sup x B K inf y A k S ( t ) x y E k ;

then compact set A k are called the family of global attractors of semigroup S ( t ) .

Proof: Verify the three conditions in theorem 2 to prove the existence of family of global attractors, under the condition of theorem 1, and the initial boundary value problems (1)-(5) generate solution semigroups S ( t ) : E k E k

1) So for any bounded set B k E k , having

S ( t ) ( u 0 , w 0 , v 0 , q 0 ) E k 2 = 2 m + k u 2 + k w 2 + 2 m + k v 2 + k q 2 C ( R k ) ,

where t 0 and ( u 0 , w 0 , v 0 , q 0 ) B k , shows that { S ( t ) } t 0 is uniformly bounded in E k ;

2) ( u 0 , w 0 , v 0 , q 0 ) E k , when t max { t 0 , t 0 k } , there is

S ( t ) ( u 0 , w 0 , v 0 , q 0 ) E k 2 = 2 m + k u 2 + k w 2 + 2 m + k v 2 + k q 2 C ( R k ) ,

thus B k is a bounded absorption set of semigroup S ( t ) ;

3) E k is compactly embedded in E 0 , i.e., the bounded set in E k is a compact set in E 0 , so the operator semigroup S ( t ) is completely continuous operator.

Theorem 3 is proved.

After the family of global attractors is obtained, in order to estimate the Hausdroff dimension and Fractal dimension of the family of global attractors, the initial boundary value problem (1)-(5) is linearized and obtain that

{ U t t + M ( m u p p + m v 2 ) ( ( m u p p ) m U + ( m v 2 ) m V ) ( Δ ) 2 m u + M ( m u p p + m v 2 ) ( Δ ) 2 m U + β ( Δ ) 2 m U t + g 1 u t ( u t , v t ) U t + g 1 v t ( u t , v t ) V t = 0 , V t t + M ( D m u p p + D m v 2 ) ( ( m u p p ) m U + ( m v 2 ) m V ) ( Δ ) 2 m v + M ( m u p p + m v 2 ) ( Δ ) 2 m V + β ( Δ ) 2 m V t + g 2 u t ( u t , v t ) U t + g 2 v t ( u t , v t ) V t = 0 , U i ( x , t ) n i | Ω = 0 , V i ( x , t ) n i | Ω = 0 , i = 0 , 1 , 2 , , 2 m 1 , t 0 , U ( x , 0 ) = m 1 , U t ( x , 0 ) = m 2 , V ( x , 0 ) = n 1 , V t ( x , 0 ) = n 2 , (66)

where U t + ε U = W , V t + ε V = Q , ( m 1 , m 2 , n 1 , n 2 ) E k , and ( u , w , v , q ) = S ( t ) ( u 0 , w 0 , v 0 , q 0 ) is the solution of the initial boundary value problem (1)-(5). Given ( u 0 , w 0 , v 0 , q 0 ) A k , S ( t ) : E k E k , for any ( m 1 , m 2 , n 1 , n 2 ) E k , there exists a unique solution ( U ( t ) , W ( t ) , V ( t ) , Q ( t ) ) L ( [ 0 , ) ; E k ) to the linear initial boundary value problem (66).

Lemma 3. For any t > 0 , C ( R k ) > 0 , the mapping S ( t ) : E k E k is Frechet differentiable. The derivative on φ = ( u , w , v , q ) T is a linear operator on E k ,

L : ( m 1 , m 2 , n 1 , n 2 ) T ( U ( t ) , W ( t ) , V ( t ) , Q ( t ) ) T ,

where ( U ( t ) , W ( t ) , V ( t ) , Q ( t ) ) is the solution of the problem (66).

Proof: suppose φ 0 = ( u 0 , w 0 , v 0 , q 0 ) T E k , φ 0 _ = ( u 0 + m 1 , w 0 + m 2 , v 0 + n 1 , q 0 + n 2 ) T E k , where φ 0 E k C ( R k ) ,

φ 0 _ E k C ( R k ) , definition ( u , w , v , q ) T = S ( t ) φ 0 , ( u _ , w _ , v _ , q _ ) T = S ( t ) φ 0 _ . From

this, we can obtain the Lipchitz property of S ( t ) on the bounded set E k , that is

S ( t ) φ 0 _ S ( t ) φ 0 E k 2 e κ t ( m 1 , m 2 , n 1 , n 2 ) E k 2 ,

where κ is arbitrary constant.

Let y = u _ u U , z = v _ v V is the solution of the following problem (67)-(68),

{ y t t + M ( m u p p + m v 2 ) ( Δ ) 2 m y + β ( Δ ) 2 m y t = h 1 , (67) z t t + M ( m u p p + m v 2 ) ( Δ ) 2 m z + β ( Δ ) 2 m z t = h 2 , (68) y ( x , 0 ) = 0 , y ( x , 0 ) = 0 , x Ω , z ( x , 0 ) = 0 , z ( x , 0 ) = 0 , x Ω , i y i n = 0 , i z i n = 0 , i = 0 , 1 , 2 , , 2 m 1 ,

where letting h 1 = h 11 + h 12 , h 2 = h 21 + h 22 ,

h 11 = M ( m u p p + m v 2 ) ( Δ ) 2 m u _ M ( m u _ p p + m v _ 2 ) ( Δ ) 2 m u _ + M ( m u p p + m v 2 ) ( ( m u p p ) m U + ( m v 2 ) m V ) ( Δ ) 2 m u , (69)

h 12 = g 1 ( u t _ , v t _ ) + g 1 ( u t , v t ) + g 1 u t ( u t , v t ) U t + g 1 v t ( u t , v t ) V t , (70)

h 21 = M ( m u p p + m v 2 ) ( Δ ) 2 m v _ M ( D m u _ p p + D m v _ 2 ) ( Δ ) 2 m v _ + M ( D m u p p + D m v p p ) ( ( m u p p ) m U + ( m v 2 ) m V ) ( Δ ) 2 m v , (71)

h 22 = g 2 ( u t _ , v t _ ) + g 2 ( u t , v t ) + g 2 u t ( u t , v t ) U t + g 2 v t ( u t , v t ) V t . (72)

Let ( Δ ) k y t inner product with Equation (69) and obtain,

( y t t + M ( m u p p + m v 2 ) ( Δ ) 2 m y + β ( Δ ) 2 m y t , ( Δ ) k y t ) = ( h 1 , ( Δ ) k y t ) .(73)

Some items are treated as follows

( y t t , ( Δ ) k y t ) = 1 2 d d t k y t 2 , (74)

( M ( m u p p + m v 2 ) ( Δ ) 2 m y , ( Δ ) k y t ) = μ 2 d d t 2 m + k y 2 , (75)

( β ( Δ ) 2 m y t , ( Δ ) k y t ) = β 2 m + k y t 2 . (76)

First deal with Equation (69), for convenience, and the following symbols are introduced

s ¯ = m u , s _ = m u _ , t ¯ = D m v , t _ = D m v _ , u ˜ = u u _ , v ˜ = v v _ ,

N ( s ¯ ) = M ( s ¯ p p + t ¯ 2 ) ( s ¯ p p ) , G ( t ¯ ) = M ( s ¯ p p + t ¯ 2 ) ( t ¯ 2 ) ,

B ( t _ ) = M ( s _ p p + t _ 2 ) ( t _ 2 ) ,

h 11 = ( M ( s ¯ p p + t ¯ 2 ) M ( s _ p p + t _ 2 ) ) ( Δ ) 2 m u _ + M ( s ¯ p p + t ¯ 2 ) ( ( s ¯ p p ) m U + ( t ¯ 2 ) m V ) ( Δ ) 2 m u = h 111 + h 112 , (77)

where

h 111 = ( M ( s ¯ p p + t ¯ 2 ) M ( s _ p p + t ¯ 2 ) ) ( Δ ) 2 m u _ + M ( s ¯ p p + t ¯ 2 ) ( s ¯ p p ) m U ( Δ ) 2 m u , (78)

h 112 = ( M ( s _ p p + t ¯ 2 ) M ( s _ p p + t _ 2 ) ) ( Δ ) 2 m u _ + M ( s ¯ p p + t ¯ 2 ) ( t ¯ 2 ) m V ( Δ ) 2 m u . (79)

Next, h 111 , h 112 is processed as follows

h 111 = M ( χ 4 p p + t ¯ 2 ) ( χ 4 p p ) m u ˜ ( Δ ) 2 m u _ + M ( s ¯ p p + t ¯ 2 ) ( s ¯ p p ) m U ( Δ ) 2 m u = N ( χ 4 ) m u ˜ ( Δ ) 2 m u _ + N ( s ¯ ) m U ( Δ ) 2 m u

= N ( χ 4 ) m u ˜ ( Δ ) 2 m u N ( χ 4 ) m u ˜ ( Δ ) 2 m u ˜ N ( s ¯ ) m u ˜ ( Δ ) 2 m u N ( s ¯ ) m y ( Δ ) 2 m u = N ( χ 5 ) ( m u ˜ ) 2 ( Δ ) 2 m u ( 1 θ 1 ) N ( χ 4 ) m u ˜ ( Δ ) 2 m u ˜ N ( s ¯ ) m y ( Δ ) 2 m u , (80)

h 112 = M ( s _ p p + χ 6 2 ) ( χ 6 2 ) m v ˜ ( Δ ) 2 m u _ + M ( s ¯ p p + t ¯ 2 ) ( t ¯ 2 ) m V ( Δ ) 2 m u = B ( χ 6 ) m v ˜ ( Δ ) 2 m u _ + G ( t ¯ ) m V ( Δ ) 2 m u = B ( χ 6 ) m V ( Δ ) 2 m u _ B ( χ 6 ) m z ( Δ ) 2 m u _ + G ( t ¯ ) m V ( Δ ) 2 m u , (81)

where χ 4 = θ 1 s ¯ + ( 1 θ 1 ) s _ , χ 5 = θ 2 χ 4 + ( 1 θ 2 ) s ¯ , χ 6 = θ 3 t ¯ + ( 1 θ 3 ) t _ , θ 1 , θ 2 , θ 3 ( 0 , 1 ) .

By using Holder’s inequality, Young’s inequality and Poincare’s inequality, ( ( Δ ) k y t , h 11 ) is treated as follows

( ( Δ ) k y t , h 11 ) = ( ( Δ ) k y t , h 111 + h 112 ) C 9 2 m + k u ˜ 2 1 λ 1 k 2 k y t + C 10 k y t 1 λ 1 k m 2 2 m + k u ˜ 2 + C 11 1 λ 1 m 2 2 m + k y k y t + C 12 1 λ 1 m 2 2 m + k z k y t ( C 9 2 λ 1 k + ( C 10 + C 11 + C 12 ) ε 2 ) k y t 2 + C 11 2 λ 1 m ε 2 m + k y 2 + C 12 2 λ 1 m ε 2 m + k z 2 + ( C 9 2 + C 10 2 λ 1 k m ε ) 2 m + k u ˜ 4 . (82)

The following processing is carried out through the mean value theorem

h 12 = g 1 ( u t , v t ) g 1 ( u t _ , v t _ ) + g 1 u t ( u t , v t ) U t + g 1 v t ( u t , v t ) V t = g 1 ( u t , v t ) g 1 ( u t , v t _ ) + g 1 ( u t , v t _ ) g 1 ( u t _ , v t _ ) + g 1 ( u t , v t ) u t U t + g 1 ( u t , v t ) v t V t g 1 ( u t , χ 7 ) χ 7 v ˜ t + g 1 ( χ 8 , v t _ ) χ 8 u ˜ t + g 1 ( u t , v t ) u t U t + g 1 ( u t , v t ) v t V t ( g 1 ( u t , χ 7 ) χ 7 g 1 ( u t , v t ) v t ) v ˜ t + g 1 ( u t , v t ) v t ( v ˜ t + V t ) + ( g 1 ( χ 8 , v t _ ) χ 8

g 1 ( u t , v t _ ) u t ) u ˜ t + ( g 1 ( u t , v t _ ) u t g 1 ( u t , v t ) u t ) u ˜ t + g 1 ( u t , v t ) u t ( u ˜ t + U t ) 2 g 1 ( u t , χ 9 ) χ 9 2 ( 1 θ 4 ) ( v ˜ t ) 2 + g 1 ( u t , v t ) v t z t + 2 g 1 ( χ 10 , v t _ ) χ 10 2 ( 1 θ 5 ) ( u ˜ t ) 2 + 2 g 1 ( u t , χ 11 ) χ 11 2 v ˜ t u ˜ t + g 1 ( u t , v t ) u t y t , (83)

where

χ 7 = θ 4 v t + ( 1 θ 4 ) v t _ , χ 8 = θ 5 u t + ( 1 θ 5 ) u t _ , χ 9 = θ 6 χ 7 + ( 1 θ 6 ) v t ,

χ 10 = θ 7 χ 8 + ( 1 θ 7 ) u t , χ 11 = θ 8 v t _ + ( 1 θ 8 ) v t , θ 4 , , θ 8 ( 0 , 1 ) .

By using Holder’s inequality, Young’s inequality and Poincare’s inequality, ( ( Δ ) k y t , h 12 ) is treated as follows

( ( Δ ) k y t , h 12 ) 2 g 1 ( u t , χ 9 ) χ 9 2 ( 1 θ 4 ) k v ˜ t 2 1 λ 1 k 2 k y t + g 1 ( u t , v t ) v t k z t k y t + 2 g 1 ( χ 10 , v t _ ) χ 10 2 ( 1 θ 5 ) k u ˜ t 2 1 λ 1 k 2 k y t + g 1 ( u t , v t ) u t k y t 2 + 2 g 1 ( u t , χ 11 ) χ 11 2 1 λ 1 k k v ˜ t k u ˜ t C 14 ε 2 k v ˜ t 4 + C 16 ε 2 k u ˜ t 4 + ( C 14 2 λ 1 k ε + C 16 2 λ 1 k ε + C 17 + C 15 2 ) k y t 2 + C 15 2 k z t 2 . (84)

Similarly, Let ( Δ ) k z t inner product with Equation (68) and obtain,

( z t t + M ( m u p p + m v 2 ) ( Δ ) 2 m z + β ( Δ ) 2 m z t , ( Δ ) k z t ) = ( h 2 , ( Δ ) k z t ) . (84)

Some items are treated as follows

( z t t , ( Δ ) k z t ) = 1 2 d d t k z t 2 , (85)

( M ( m u p p + m v 2 ) ( Δ ) 2 m z , ( Δ ) k z t ) = μ 2 d d t 2 m + k z 2 , (86)

( β ( Δ ) 2 m z t , ( Δ ) k z t ) = β 2 m + k z t 2 , (87)

( ( Δ ) k z t , h 21 ) ( C 9 2 λ 1 k + ( C 10 + C 11 + C 12 ) ε 2 ) k z t 2 + C 11 2 λ 1 m ε 2 m + k z 2 + C 12 2 λ 1 m ε 2 m + k y 2 + ( C 9 2 + C 10 2 λ 1 k m ε ) 2 m + k v ˜ 4 , (88)

( ( Δ ) k z t , h 22 ) ( C 14 2 λ 1 k ε + C 16 2 λ 1 k ε + C 17 + C 15 2 ) k z t + C 15 2 k y t + C 14 ε 2 k u ˜ t 4 + C 16 ε 2 k v ˜ t 4 . (89)

Based on the above Equations (74)-(89), it is sorted out that

d d t ( k y t 2 + k z t 2 + μ ( 2 m + k y 2 + 2 m + k z 2 ) ) + 2 β ( 2 m + k y t 2 + 2 m + k z t 2 ) ( ( C 10 + C 11 + C 13 ) ε + C 14 + C 16 + 2 ε C 9 2 λ 1 k + 2 ( C 15 + C 17 ) ) ( k y t 2 + k z t 2 ) + C 11 + C 12 ε λ 1 m ( 2 m + k y 2 + 2 m + k z 2 ) + ( C 9 + C 10 ε λ 1 k m ) ( 2 m + k u ˜ 4 + 2 m + k v ˜ 4 ) + ( C 14 + C 16 ) ε ( k u ˜ t 4 + k v ˜ t 4 ) , (90)

finally simplified

d d t y 3 ( t ) ¯ α 3 y 3 ( t ) ¯ + α 4 ( 2 m + k u ˜ 4 + 2 m + k v ˜ 4 + k u ˜ t 4 + k v ˜ t 4 ) ,

where α 3 = max { ( C 10 + C 11 + C 13 ) ε + C 14 + C 16 + 2 ε C 9 2 λ 1 k + 2 ( C 15 + C 17 ) , C 11 + C 12 ε λ 1 m μ } ,

α 4 = max { C 9 + C 10 ε λ 1 k m , ( C 14 + C 16 ) ε } ,

y 3 ( t ) ¯ = k y t 2 + k z t 2 + μ ( 2 m + k y 2 + 2 m + k z 2 ) ,

according to Gronwall’s inequality

y 3 ( t ) ¯ y 3 ( 0 ) ¯ e α 3 t + e α 3 0 t 2 m + k u ˜ 4 + 2 m + k v ˜ 4 + k u ˜ t 4 + k v ˜ t 4 d t C 18 e α 3 t ( m 1 , m 2 , n 1 , n 2 ) E k 4 .

when ( m 1 , m 2 , n 1 , n 2 ) E k 2 0 , there is

S ( t ) φ 0 _ S ( t ) φ 0 L ( ( m 1 , m 2 , n 1 , n 2 ) T ) Ε k 2 ( m 1 , m 2 , n 1 , n 2 ) E k 2 C 18 e α 3 t ( m 1 , m 2 , n 1 , n 2 ) E k 2 0 .

Lemma 3 is proved.

Theorem 4. Under the condition of Theorem 3, the global attractors of initial boundary value problems (1)-(5) have finite dimensional Hausdroff dimension

and fractal dimension, and then d H ( A k ) < 3 7 N , d F ( A k ) < 6 7 N .

Proof: In order to estimate the dimension of the global attractor, the initial boundary value problems (1)-(5) are rewritten as

φ t + H φ = F ( φ ) , (91)

where φ = ( u , w , v , q ) T , w = u t + ε u , q = v t + ε v ,

H = ( ε I I 0 0 ( 1 β ε ) ( Δ ) 2 m + ε 2 I β ( Δ ) 2 m ε I 0 0 0 0 ε I I 0 0 ( 1 β ε ) ( Δ ) 2 m + ε 2 I β ( Δ ) 2 m ε I ) ,

F ( φ ) = ( 0 f 1 ( x ) g 1 ( u t , v t ) + ( 1 M ( m u p p + m v 2 ) ) ( Δ ) 2 m u 0 f 2 ( x ) g 2 ( u t , v t ) + ( 1 M ( m u p p + m v 2 ) ) ( Δ ) 2 m v ) .

Let L ( φ ) = φ t = F ( φ ) H φ , ψ t = L t ( φ ) .

According to Lemma 3, L : E k E k is Frechet differentiable, so (91) can be rewritten as

ψ t + P ( φ ) ψ = Γ 1 ( φ ) ψ + Γ 2 ( φ ) ψ , (92)

where ψ = ( U , W , V , Q ) T , W = U t + ε U , Q = V t + ε V ,

P ( φ ) = ( ε I I 0 0 ( 1 β ε ) ( Δ ) 2 m + ε 2 I β ( Δ ) 2 m ε I 0 0 0 0 ε I I 0 0 ( 1 β ε ) ( Δ ) 2 m + ε 2 I β ( Δ ) 2 m ε I ) ,

Γ 1 ( φ ) = ( 0 0 0 0 ε g 1 u t ( u t , v t ) g 1 u t ( u t , v t ) ε g 1 v t ( u t , v t ) g 1 v t ( u t , v t ) 0 0 0 0 ε g 2 u t ( u t , v t ) g 2 u t ( u t , v t ) ε g 2 v t ( u t , v t ) g 2 v t ( u t , v t ) ) ,

Γ 2 ( φ ) = ( 0 0 0 0 ( 1 M ( s ) ) ( Δ ) 2 m D u 0 D u 0 0 0 0 0 D v 0 ( 1 M ( s ) ) ( Δ ) 2 m D V 0 ) ,

D u U = M ( m u p p + m v 2 ) ( m u p p ) m U ( Δ ) 2 m u ,

D u V = M ( m u p p + m v 2 ) ( m v 2 ) m V ( Δ ) 2 m u ,

D v U = M ( m u p p + m v 2 ) ( m u p p ) m U ( Δ ) 2 m v ,

D v V = M ( m u p p + m v 2 ) ( m v 2 ) m V ( Δ ) 2 m v ,

and U , V is the solution of problem (66).

For every fixed ( u , w , v , q ) E k , assume that d 1 , d 2 , , d N are N elements in E k , and ψ 1 ( t ) , ψ 2 ( t ) , , ψ N ( t ) are N solutions of the linearized Equation (92) with an initial value ψ 1 ( 0 ) = d 1 , ψ 2 ( 0 ) = d 2 , , ψ N ( 0 ) = d N , where N is a natural number.

It can be obtained by calculation

d d t ψ 1 ( t ) ψ 2 ( t ) ψ N ( t ) E k 2 2 t r ( L t ( φ ( τ ) ) Q N ( τ ) ) d 1 d 2 d N = 0 ,

where L t ( φ ( t ) ) = L t ( S ( t ) φ 0 ) is a linear mapping, φ ( t ) = S ( t ) φ 0 is the solution of problems (1)-(5), represents the outer product, t r represents the trace of the operator, Q N represents the orthogonal projection from E k to s p a n { ψ 1 ( t ) , ψ 2 ( t ) , , ψ N ( t ) } , and the N dimensional volume j = 1 N d j is

ϖ N ( t ) = sup φ 0 A k sup d j E k ψ 1 ( t ) ψ 2 ( t ) ψ N ( t ) N E k 2 .

Through Gronwall’s inequality, can get

ψ 1 ( t ) ψ N ( t ) N E k 2 ψ 1 ( 0 ) ψ N ( 0 ) N E k 2 exp 0 t t r ( L t ( φ ( τ ) ) Q N ( τ ) ) d τ .

For any given time τ , suppose h j ( τ ) = ( ξ j ( τ ) , ζ j ( τ ) , η j ( τ ) , σ j ( τ ) ) T , j = 1 , 2 , , N are the standard orthogonal basis of space s p a n { ψ 1 ( t ) , ψ 2 ( t ) , , ψ N ( t ) } , then define the inner product on E k

( h j , h j ¯ ) E k = ( 2 m + k ξ j , 2 m + k ξ j ¯ ) + ( k ζ j , k ζ j ¯ ) + ( 2 m + k η j , 2 m + k η j ¯ ) + ( k σ j , k σ j ¯ ) , and norm is

h j E k 2 = ( h j , h j ) E k = 2 m + k ξ j 2 + k ζ j 2 + 2 m + k η j 2 + k σ j 2 = 1 . (93)

Through the above conditions, can get

t r ( L t ( φ ( τ ) ) Q N ( τ ) ) = j = 1 N ( L t ( φ ( τ ) ) Q N ( τ ) h j ( τ ) , h j ( τ ) ) E k = j = 1 N ( L t ( φ ( τ ) ) h j ( τ ) , h j ( τ ) ) E k , (94)

where

( L t ( φ ( τ ) ) h j ( τ ) , h j ( τ ) ) E k = ( Γ 1 ( φ ) h j ( τ ) , h j ( τ ) ) + ( Γ 2 ( φ )

Conflicts of Interest

The authors declare no conflicts of interest regarding the publication of this paper.

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