Existence of Positive Solutions to Semipositone Fractional Differential Equations ()
Received 19 June 2016; accepted 14 August 2016; published 17 August 2016

1. Introduction
The aim of this paper is to investigate the existence of positive solutions to the semipositone fractional differential equation
(1)
where
,
is the standard Riemann-Liouville fractional derivative of order
which is defined as follows:

where
denotes the Euler gamma function and
denotes the integer part of number
, provided that the right side is pointwise defined on
, see [1] . Here, by a positive solution to the problem (1), we mean a function
, which is positive in
, and satisfies (1).
Fractional differential equations have gained much importance and attention due to the fact that they have been proved to be valuable tools in the modelling of many phenomena in engineering and sciences such as physics, mechanics, economics and biology. In recent years, there exist a great deal of researches on the existence and/or uniqueness of solutions (or positive solutions) to boundary value problems for fractional-order differential equations. Sun [2] studied the existence of positive solutions for the following boundary value pro- blems:

where
,
is continuous and
on
. But paper [2] did not give the results of the existence of positive solution when the nonlinearity can take negative value, i.e. semipositone problems.
The purpose of the present paper is to apply the method of varying translation together with the fixed point theorems in cone to discuss (1) without nonnegativity imposed on the nonlinearity. Meanwhile, we also allow the nonlinearity to have many finite singularities on
.
2. Preliminaries and Lemmas
In this section, we present several lemmas that are useful to the proof of our main results. For the forthcoming analysis, we need the following assumptions:
(H1)
is continuous. For any
, there exist constants ![]()
such that ![]()
(H2)
with
and
,
where
![]()
will be defined in the following text.
In [3] , the authors obtained the Green function associated with the problem (1). More precisely, the authors proved the following lemma.
Lemma 2.1 [3] . For any
, the unique solution of the boundary value problem
(2)
is given by
(3)
where
(4)
Lemma 2.2 [4] . The Green function
defined by (4) satisfies the inequality
(5)
here
![]()
Remark 2.1. A simple computation shows that there exists a constant
such that
![]()
Remark 2.2 [5] . If
satisfies (H1), then for any
is increasing on ![]()
and for any
, ![]()
Lemma 2.3 [6] . Let X be a real Banach space,
be a bounded open subset of X with
and
is a completely continuous operator, where P is a cone in X.
(i) Suppose that
then
.
(ii) Suppose that
then
.
Consider the Banach space
with the usual supremum norm
and define the
cone
. Let
, then
is the unique solution
to (2) for
. Now we first consider the singular nonlinear boundary value problem
(6)
where
We have the following Lemma.
Lemma 2.4. If the singular nonlinear boundary value problem (2) has a positive solution
such that
for any
. Then boundary value problem (1) has a positive solution
.
Proof. In fact, if u is a positive solution to (6) such that
for any
. Let
, then
. Since
is the unique solution to (2) for
for any
, we
have
, which implies that
. So
. Consequently
is positive solution to (1). This complete the proof of Lemma 2.4.
For any
, define an operator
(7)
Since for any fixed
, we can choose
such that
. Note that
so by (H1), we have
![]()
Consequently, for any
, we have
(8)
Therefore, the operator T is well defined and ![]()
Lemma 2.5. Assume that (H1), (H2) hold. Then
is a completely continuous operator.
Proof. For any
, in view of (2) we conclude that
![]()
Whence, it follows from (8) that
which implies ![]()
Next we show that
is continuous. Suppose
, and
Then, there exists a constant
such that
. Since for any ![]()
, by Remark 2.2, we have
(9)
Thus, we have
![]()
and
. It follows from the Lebesgue control convergence theorem that
![]()
which implies
is continuous.
In what follows, we need to prove that
is relatively compact.
Let
be any bounded set. Then there exists a constant
such that
for any
. Similarly as (9), for any
we have
(10)
Consequently
(11)
Therefore
is uniformly bounded.
Now we show that
is equicontinuous on
. For any
, by (9), (11) and the Lebesgue control convergence theorem, and noticing the continuity of
, we have
(12)
Thus,
is equicontinuous on [0,1]. The Arezlà-Ascoli Theorem guarantees that
is relatively compact set. Therefore
is completely continuous operator.
Lemma 2.6. Let
then
.
Proof. Assume that there exists
such that
Then
and
Thus we have
![]()
This contradiction shows that
.
Lemma 2.7. There exists a constant
such that
, where ![]()
Proof. Choose constants
and N such that
![]()
From Remark (2.2), there exists
, such that
(13)
Let
Obviously,
Now we show that
In
fact, otherwise, there exists
such that
By (2), for any
we have
![]()
So
![]()
Consequently,
That is
This
contradiction shows that
.
3. Main Results
Theorem 3.1. Suppose that (H1), (H2) hold. Then, the boundary value problems (1) has at least one positive solution
, and exists a constant
such that ![]()
Proof of Theorem 3.1. Applying Lemma 2.6 and Lemma 2.7 and the definition of the fixed point index, we have
Thus T has a fixed point
in
with
. Since
, we have
![]()
Let
It follows from Lemma (2.4) that
is a positive solution to boundary value problem (1), and there exists a constant
such that ![]()
Acknowledgements
We thank the Editor and the referee for their comments. This research was supported financially by the National Natural Science Foundation of China (11471187, 11571197), the Natural Science Foundation of Shandong Province of China (ZR2014AL004) and the Project of Shandong Province Higher Educational Science and Technology Program (J14LI08), the Project of Scientific and Technological of Qufu Normal University (XKJ201303).