Quasilinear Degenerated Elliptic Systems with Weighted in Divergence Form with Weak Monotonicity with General Data

Abstract

We consider, for a bounded open domain Ω in Rn and a function u : Ω → Rm, the quasilinear elliptic system: (1). We generalize the system (QES)(f,g) in considering a right hand side depending on the jacobian matrix Du. Here, the star in (QES)(f,g) indicates that f may depend on Du. In the right hand side, v belongs to the dual space W-1,P(Ω, ω*, Rm), , f and g satisfy some standard continuity and growth conditions. We prove existence of a regularity, growth and coercivity conditions for σ, but with only very mild monotonicity assumptions.

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Barbara, A. , Rami, E. and Azroul, E. (2021) Quasilinear Degenerated Elliptic Systems with Weighted in Divergence Form with Weak Monotonicity with General Data. Applied Mathematics, 12, 500-519. doi: 10.4236/am.2021.126035.

1. Introduction

In this paper, the main point is that we do not require monotonicity in the strict monotonicity of a typical Leray-Lions operator as it is usually assumed in previous papers. The aims of this text are to prove analogous existence results under relaxed monotonicity, in particular under strict quasi-monotonicity. The main technical tool we advocate and use throughout the proof is Young measures. By applying a Galerkin schema, we obtain easily an approximating sequence u k . The Ball theorem [1] and especially the resulting tool mode available by Hungerbühler to partial differential equation theory give them a sufficient control on the gradient approximating sequence D u k to pass to the limit. This method is used by Dolzmann [2], G. J. Minty [3], H. Brezis [4], H. E. Stromberg [5], Muller [6], J. L. Lions [7], Kristznsen, J. Lower [8], M. I. Visik [9] and mainly by Hungurbühler to get the existence of a weak solution for the quasi-linear elliptic system [10]. This paper can be seen as generalization of Hungurbühler and as a continuation of Y-Akdim [11].

This kind of problems finds its applications in the model of Thomas-Fermis in atomic physics [12], and also porous flow modeling in reservoir [13].

2. Priliminaries

Let ω = { ω i j ; 0 i n ; 1 j m } the weight function systems defined in Ω and satisfying the following integrability conditions:

ω i j L l o c 1 ( Ω ) , ω i j 1 p 1 L l o c 1 ( Ω ) , for some p ] 1, [ and s > 0 such that ω i j s L 1 ( Ω ) . (2.1)

with ω * = { ω i j * = ω i j 1 p , 0 i n , 1 j m } , σ = ( σ r s ) with 1 s n , 1 r m and which satisfies some hypotheses (see below).

We denote by I M m × n the real vector space of m × n matrices equipped with

the inner product M : N = i j M i j N i j .

The Jacobian matrix of a function u : Ω I R m is denoted by D u ( x ) = ( D 1 u ( x ) , D 2 u ( x ) , , D n u ( x ) ) with D i = / ( x i ) .

The space W 1, p ( Ω , ω , I R m ) is the set of functions

{ u = u ( x ) / u L p ( Ω , ω 0 ¯ , I R m ) } , D i j u = u i x j L p ( Ω , ω i j , I R m ) , 1 i n , 1 j m .

with

L p ( Ω , ω i j , I R m ) = { u = u ( x ) / | u | ω i j 1 p L p ( Ω , I R m ) }

The weighted space W 1, p ( Ω , ω , I R m ) can be equipped by the norm:

u 1 , p , ω = ( j = 1 m Ω | u j | p ω 0 j d x + 1 i n , 1 j m Ω | D i j u | p ω i j d x ) 1 p

where ω 0 ¯ = ( ω 0 j ) and 1 j m . the norm . 1, ω , p is equivalent to the norm | | | | | | , on W 0 1, p ( Ω , ω , I R m ) , such that, | | | u | | | = ( 1 i n , 1 j m Ω | D i j u | p ω i j d x ) 1 p .

Proposition 2.1 The weighted Sobolev space W 1, p ( Ω , ω , I R m ) is a Banach space, separable and reflexive. The weighted Sobolev space W 0 1, p ( Ω , ω , I R m ) is the closure of C 0 ( Ω , ω , I R m ) in W 1, p ( Ω , ω , I R m ) equipped by the norm . 1, p , ω .

Proof: The prove of proposition is a slight modification of the analogous one in [14] [Kufner-Drabek].

Definition 2.1 A Young measure ( ϑ x ) x Ω is called W 1, p -gradient young measures ( 1 p < ) if it is associated to a sequence of gradients D u k such that u k is bounded in W 1, p ( Ω ) . The W 1, p -gradient young measures ( ϑ x ) x Ω is called homogeneous, if it doesnt depend on x, i-e, if ϑ x = ϑ for a.e. x Ω .

Theorem 2.1 (Kinder Lehirer-Pedregal) let ( υ x ) x Ω , be a family of probability measures in ( C ( M m × n ) ) . Then, ( υ x ) x Ω is W 1, p Young measures if and only if:

1) There is a u W 1, p ( Ω , I R m ) such that D u ( x ) = M m × n A d ϑ x ( A ) , a.e in Ω .

2) Jensens inequality: ϕ ( D u ( x ) ) M m × n ϕ ( A ) d ϑ x ( A ) hold for all ϕ X p quasi-convex, and.

3) The function: ψ ( x ) = M m × n | A | p d ϑ x ( A ) L 1 ( Ω ) . Here, X p denotes the (not separable) space: X p = { ψ C ( M m × n ) : | ψ ( A ) | c × ( 1 + | A | p ) , forall A M m × n } .

proof: see [15].

Theorem 2.2 (Ball) Let Ω I R n be Lebesgue measurable, let K I R m be closed, and let u j : Ω I R m , j I N , be a sequence of Lebesgue measurable functions satisfying u j K , as j , i.e. given any open neighborhood U of K I R m , lim j | x Ω : u j ( x ) U | = 0 . Then there existsa subsequence u k of u j and a family ϑ x , x Ω , of positive measures on I R m , depending measurablyon x, such that

1) ϑ x M = I R m d ϑ x 1 , for a.e x Ω .

2) s u p p ϑ x K for a.e x Ω .

3) f ( u k ) ϑ x , f = I R m f ( λ ) d ϑ x ( λ ) in L ( Ω ) for each continuous functions f : I R m I R satisfying

lim f ( λ ) = 0, | λ | [1].

Theorem 2.3 (vitali) Let Ω I R n be an open bounded domain and let u n be a sequence in L p ( Ω , I R m ) with 1 p < .

Then u n is a cauchy sequence in the L p -norm if and only if the two following conditions hold:

1) u n is cauchy in measure (i.e. ε > 0 , | { x Ω , | u n ( x ) u m ( x ) | ε } | = 0 as m , n .

2) | u n | p is equiintegrable i.e.:

( s u p n Ω | u n | p d x < and ε > 0 , δ > 0 such that E | u n | p d x < ε for all n whenever E Ω and | E | < δ ). Note that if u n converges pointiest, then u n is cauchy in measure.

Hypotheses (H0) (Hardy-Type inequalities): There exist some constant c > 0 , some weighted function γ and some real q ( 1 < q < ) such that,

( j = 1 m Ω | u j ( x ) | q γ j ( x ) d x ) 1 q c ( 1 i n , 1 j m Ω | D i j u | p ω i j ) 1 p ,

for all u W 0 1, p ( Ω , ω , I R m ) , with γ = { γ j / 1 j m } .

The injection W 0 1, p ( Ω , ω , I R m ) ↪↪ L q ( Ω , γ , I R m ) is compact, and W 0 1, p ( Ω , ω , I R m ) ↪↪ L r ( Ω , I R m ) is compact, (by [14] ) with

{ 1 r n p s n ( s + 1 ) p s if p s n ( s + 1 ) r 1 if n ( s + 1 ) p s

(H1) Continuity: σ : Ω × I R m × I M m × n I M m × n is a Carathéodory function (i-e x σ ( x , u , F ) is measurable for every ( u , F ) I R m × I M m × n and ( u , F ) σ ( x , u , F ) is continuous for almost every x Ω ). (H2) Growths and coercivity conditions: There exist c 1 0 , c 2 > 0 , λ 1 L p ( Ω ) , λ 2 L 1 ( Ω ) , λ 3 L ( p / α ) ( Ω ) , 0 < α < p , 1 < q < and β > 0 such that for all 1 r n , 1 s m , we have:

| σ r s ( x , u , F ) | β w r s 1 / p [ λ 1 ( x ) + c 1 j = 1 m | γ j | 1 / p | u j | q / p + c 1 1 i N , 1 j m ω i j 1 / p | F i j | p 1 ] (2.2)

and

σ ( x , u , F ) : F λ 2 ( x ) j = 1 m ω 0 j ( x ) α / p λ 3 ( x ) | u j | α + c 2 1 i n , 1 j m ω i j ( x ) | F i j | p (2.3)

(H3) Monotonicity conditions: σ satisfies one of the following conditions:

1) For all x Ω , and all u I R m , the map F σ ( x , u , F ) is a C 1 -function and is monotone (i-e, ( σ ( x , u , F ) σ ( x , u , G ) ) : ( F G ) 0 , for all x Ω , all u I R m and all F , G I M m × n ).

2) There exists a function W : Ω × I R m × I M m × n I M m × n such that σ ( x , u , F ) = W F ( x , u , F ) and F W ( x , u , F ) is convex and C 1 function.

3) For all x Ω , and for all u I R m the map F σ ( x , u , F ) is strictly monotone (i.e., σ ( x , u ,. ) is monotone and: [ ( σ ( x , u , F ) σ ( x , u , G ) ) : ( F G ) = 0 ] F = G ).

4) σ ( x , u , F ) is strictly p-quasi-monotone in F, i.e.,

I M m × n ( σ ( x , u , λ ) σ ( x , u , λ ¯ ) ) : ( λ λ ¯ ) d ϑ ( λ ) > 0,

for all homogeneous W 1, p , w -gradient young measures ϑ with center of mass λ ¯ = ϑ , i d which are not a single Dirac mass.

The main point is that we do not require strict monotonicity or monotonicity in the variables ( u , F ) in (H3) as it is usually assumed in previous work (see [15] or [16] ).

( F 0 ) : (continuity) f : Ω × I R m × I M m × n I R m is a Carathéodory function i-e: x f ( x , u , F ) is measurable for every u I R m , and F I M m × n , ( u , F ) f ( x , u , F ) is continuous for almost every x Ω .

( F 1 ) : (growth condition): The exist: b 1 L p ( Ω ) , c 1 > 0 , c 2 > 0 such that:

| f j ( x , u ) | [ b 1 ( x ) + c 1 γ j 1 p | u j | q p + c 2 r , s ω r s 1 P | F r s | p 1 ] ω 0 j 1 P ;

1 j m ( G 0 ) : (continuity) the map g : Ω × I R m I M m × n is a Carathéodory function. ( G 1 ) : (growth condition) There exist: b 2 L p ( Ω )

| g r s | ω r s 1 p [ b 2 + j γ j 1 p | u j | q p ]

For all 1 r n and 1 s m .

Our aim of this paper is to prove the existence of the problem ( Q E S ) f , g in the space W 0 1, P ( Ω , ω , I R m ) .

Remark 2.1 -The condition ( F 0 ) and ( G 0 ) ensure the measurability of f and g for all measurable function u.

- ( F 1 ) and ( G 1 ) ensure that growths conditions, in particularly: if u W 0 1, P ( Ω , ω , I R m ) then f ( ., u ( . ) , D ( . ) ) u ( . ) and g ( ., u ) : D u is in L 1 ( Ω , ω ) .

- Exploiting the convergence in measure of the gradients of the approximating solutions, we will prove the following theorem.

Theorem 2.4 If p ( 1, ) and σ satisfies the conditions (H0)-(H3), then the Dirichlet problem ( Q E S ) f , g has a weak solution u W 0 1, p ( Ω , ω , I R m ) , for every v W 1, p ( Ω , ω , I R m ) , f satisfies ( F 0 ) and ( F 1 ) and g satisfies ( G 0 ) and ( G 1 ) .

In order to prove theorems, we will apply a Galerkin scheme, with this aim in view, we establish in the following subsections, the key ingredient to pass to the limit for this, we assume that the conditions: (H0)-(H3), ( F 0 ) , ( F 1 ) , ( G 0 ) and ( G 1 ) .

Lemma 2.1 For arbitrary u W 0 1, p ( Ω , ω , I R m ) and v W 1, p ( Ω , ω , I R m ) , the functional

F ( u ) : W 0 1, p ( Ω , ω , I R m ) I R φ Ω σ ( x , u ( x ) , D u ( x ) ) : D φ ( x ) d x v , φ Ω f ( x , u , D u ) : φ d x + Ω g ( x , u ) : D φ d x .

is well defined, linear and bounded.

Proof For all φ W 0 1, p ( Ω , ω , I R m ) , we denote

F ( u ) ( φ ) = I 1 + I 2 + I 3 + I 4

with

I 1 = Ω σ ( x , u ( x ) , D u ( x ) ) : D φ ( x ) d x ,

and

I 2 = v , φ .

I 3 = Ω f ( x , u , D u ) : φ d x

I 4 = Ω g ( x , u ) : D φ d x

We define

I r s = Ω σ r s ( x , u ( x ) , D u ( x ) ) : D r s φ ( x ) d x

Firstly, by virtue of the growth conditions (H2) and the Hölder inequality, one has

| I r s | Ω | σ r s ( x , u ( x ) , D u ( x ) ) | : | D r s φ ( x ) | d x Ω β ω r s 1 / p ( x ) [ λ 1 ( x ) + c 1 j = 1 m | γ j ( x ) | 1 / p | u j ( x ) | q / p + c 1 1 i n , 1 j m ω i j 1 / p | D i j u | p 1 ] | D r s φ | d x β [ ( Ω | λ 1 ( x ) | p d x ) 1 / p ( Ω | D r s φ ( x ) | p ω r s d x ) 1 / p + ( Ω | D r s φ ( x ) | p ω r s ) 1 / p ( j = 1 m Ω | u j | q γ j d x ) 1 / p + ( 1 i n , 1 j m Ω | D i j u | p ω i j d x ) 1 / p ( Ω | D r s φ | p ω r s d x ) 1 / p ]

with ( p = p ( p 1 ) ) , and thanks to Hardy inequality we have:

| I r s | c β [ λ 1 p φ 1, p , ω r s + c 1 D φ p , ω r s ( Ω | u | q γ d x ) 1 / p + c 1 i j D φ p , ω i j D u p , ω r s ] c β [ λ 1 p φ 1, p , ω r s + φ 1, p , ω r s u q , γ + u 1, p , ω φ 1, p , ω r s ]

with c = max ( c ,1 ) . Which gives

| I 1 | c β [ λ 1 p + u 1 , p , ω q / p + u 1 , p , ω ] φ 1 , p , ω < .

and

| I 2 | Ω | v | | φ | d x v 1 , p , ω * φ 1 , p , ω < .

I 3 = j Ω f j ( x , u , D u ) φ j ( x ) d x

We denote I 3, j = | Ω f j ( x , u , D u ) φ j ( x ) d x | .

I 3, j Ω | f j ( x , u , D u ) | | φ j ( x ) | d x Ω b 1 ( x ) | φ j ( x ) | ω 0 j 1 P d x + c 1 Ω γ j 1 p | u j | q p | φ j ( x ) | ω 0 j 1 P + c 2 Ω r s | φ j ( x ) | | D r s u | p 1 ω 0 j 1 P d x ( Ω | b 1 ( x ) | p ) 1 p ( Ω | φ j ( x ) | p ω 0 j d x ) 1 p + ( Ω γ j ( x ) | u j | q d x ) 1 p ( Ω | φ j ( x ) | p ω 0 j d x ) 1 p + r s ( Ω | φ j | p ω 0 j ) 1 p ( Ω | D r s u | p ( p 1 ) ω r s ) 1 p b 1 p φ 1 , p , ω + c 1 ( j Ω γ j ( x ) | u j | q d x ) 1 p φ 1 , p , ω + c 2 φ 1 , ω , p D u 1 , p , ω p p

b 1 p φ 1 , p , ω + c 1 D u 1 , p , ω φ 1 , p , ω + c 2 φ 1 , ω , p D u 1 , p , ω p p ( b 1 + c 1 D u 1 , p , ω + c 2 D u 1 , p , ω p p ) φ 1 , p , ω .

I 4 = r s Ω g r s ( x , u ) D r s φ d x

Ω | g r s | : | D r s φ | d x Ω b 2 ω r s 1 p D r s φ d x + j Ω γ j 1 p ( x ) | u j | q p ω r s 1 p D r s φ d x ( Ω | b 2 | p d x ) 1 p ( Ω | D r s φ | p ω r s d x ) 1 p + j ( Ω | u j | q γ j ( x ) d x ) 1 p ( Ω | D r s φ | p ω r s ( x ) d x ) 1 p b 2 p D r s φ 1 , p , ω r s + u q , γ q p ( Ω | D r s φ | p ω r s d x ) 1 p

I 4 b 2 p D r s φ 1 , p , ω r s + u q , γ q p ( Ω | D r s φ | p ω r s d x ) 1 p b 2 p D φ 1 , p , ω + u q , γ q p D φ 1 , p , ω c φ 1 , p , ω

Hence I c 4 φ 1, p , ω . With c 4 < .

Finally the functional F ( . ) is bounded.

Lemma 2.2 The restriction of F to a finite dimensional linear subspace V of W 0 1, p ( Ω , ω , I R m ) is continuous.

Proof Let d be the dimension of V and ( e 1 , e 2 , , e d ) a basis of V. Let u j = 1 i d a j i e i be a sequence in V which converges to u = 1 i d a i e i in V. The sequence ( a j ) converge to a I R d , so u j u and D u j D u a.e., on the other hand u j p and D u j p are bounded by a constant c. Thus, it follows by the continuity conditions (H1), that

σ ( x , u j , D u j ) : D φ σ ( x , u , D u ) : D φ

for all φ W 0 1, p ( Ω , ω , I R m ) and a.e. in Ω . Let Ω be a measurable subset of Ω and let φ W 0 1, p ( Ω , ω , I R m ) .

Thanks to the condition (H2), we get

Ω | σ ( x , u j , D u j ) : D φ | d x < ,

By the continuity conditions ( F 0 ) and ( G 0 ) we have:

f ( x , u j , D u j ) φ f ( x , u , D u ) φ

And

g ( x , u j ) D φ g ( x , u ) D φ

almost everywhere. Moreover we infer from the growth conditions ( F 1 ) and ( G 1 ) that the sequences:

( σ ( x , u j , D u j ) : D φ ) , ( f ( x , u j , D u j ) φ ) and ( g ( x , u j ) D φ )

Are equi-integrable. Indeed, if Ω Ω is a measurable subset and φ W 0 1, p ( Ω , ω , I R m ) then:

Ω | f ( x , u j , D u j ) φ | d x < (by ( F 1 ) and Hölder inequality).

Ω | g ( x , u j ) D φ | d x < (by ( G 1 ) and Hölder inequality).

Ω | σ ( x , u j , D u j ) : D φ | d x < (by Hölder inequality).

which implies that σ ( x , u j , D u j ) : D φ is equi-integrable. And by applying the Vitali’s theorem, it follows that

Ω σ ( x , u j , D u j ) : D φ d x Ω σ ( x , u , D u ) : D φ d x ,

for all φ W 0 1, p ( Ω , ω , I R m ) .

Finally

lim j F ( u j ) , φ = F ( u ) , φ ,

which means that

F ( u j ) F ( u ) in W 1, p ( Ω , ω , I R m ) .

Remark 2.2 Now, the problem ( Q E S ) f , g is equivalent to find a solution u W 0 1, p ( Ω , ω , I R m ) such that F ( u ) , φ = 0 , for all φ W 0 1, p ( Ω , ω , I R m ) .

In order tofind such a solution we apply a Galerkin scheme.

3. Galerkin Approximation

Remark 3.1 (Galerkin Schema)

Let V 1 V 2 W 0 1, p ( Ω , ω , I R m ) be a sequence of finite dimensional subspaces with k I N V k dense in W 0 1, p ( Ω , ω , I R m ) . The sequence V k exists since W 0 1, p ( Ω , ω , I R m ) is separable.

Let us fix some k, we assume that V k has a dimension d and that ( e 1 , e 2 , , e d ) is a basis of V k . Then, we define the map,

G : I R k I R k ( a 1 , , a k ) ( F ( u ) , e 1 , , F ( u ) , e k ) ; u = i = 1 d a i e i .

Proposition 3.1 The map G is continuous and G ( a ) a tends to infinity when a I R k tends to infinity.

Proof. Since F restricted to V k is continuous by Lemma 2.2, so G is continuous.

Let a I R d and u = 1 i d a i e i in V k , then G ( a ) a = F ( u ) , u and which implies that a I R d tends to infinity if u 1, p , ω tends to infinity.

G ( a ) a = 1 i d F ( u ) , a i e i = F ( u ) , u

and

u 1, p , ω p = 1 i d a i e i 1, p , ω p ( 1 i d | a i | e i 1, p , ω ) p max 1 i d ( e i 1, p , ω p ) ( 1 i d | a i | ) p c a I R p ,

which implies that a I R p tends to infinity if u 1, p , ω tends to infinity.

Now, it suffices to prove that

F ( u ) , u when u 1, p , ω .

Indeed, thanks to the first coercivity condition and the Hölder inequality, we obtain

I = Ω σ ( x , u , D u ) : D u d x λ 2 1 Ω λ 3 ω 0 j α / p | u j | α d x + c 2 1 i , j n , m Ω | D i j u | p ω i j d x

By the Hölder inequality, we have

Ω λ 3 | u j | α ω 0 j α / p d x λ 3 ( p / α ) ( Ω ω 0 j | u j | ( p / α ) α ) α / p c λ 3 ( p / α ) u j 1, p , ω 0 j .

where c is a constant positive. For u 1, p , ω large enough, we can write

| I | λ 2 1 c λ 3 ( p / α ) u j 1, p , ω 0 j α + c 2 1 i , j n , m D u j 1, p , ω i j p λ 2 1 c λ 3 ( p / α ) u 1, p , ω α + c 2 c u 1, p , ω p .

And since

| I | = | v , u | v 1 , p , ω u 1 , p , ω

Finally, it follows from the growth condition ( F 1 ) and G 1 that:

| I | = | Ω f ( x , u , D u ) u d x | ( b 1 p + c 1 D u 1, p , ω + c 2 D u 1, p , ω ) u 1, p , ω c 3 u 1, p , ω

| I | = | Ω g ( x , u ) D u d x | ( b 2 p + u q , γ q p ) D u 1, p , ω c 4 u 1, p , ω ;

with c 4 is a constant. With; 0 < α < p and p > 1 , we get:

I I I c 2 c u 1, p , ω p v 1, p , ω u 1, p , ω c λ 3 ( p / α ) u 1, p , ω α λ 2 1 c 3 . u 1, p , ω (3.1)

Consequently, by using (3.1), we deduce

I I I as u 1, p , ω .

and

I as u 1, p , ω .

F ( u ) , u as u 1, p , ω .

Remark 3.2 The properties of G allow us to construct our Galerkin approximations.

Corollary 3.1 For all k I N , there exists ( u k ) V k such that F ( u k ) , φ = 0 , for all φ V k .

Proof By the proposition 3.1, there exists R > 0 , such that for all a B R ( 0 ) I R d , we have G ( a ) a > 0 . And the usual topological argument see [Zei 86 proposition 2.8] [17] implies that G ( x ) = 0 has a solution x B R ( 0 ) . So, for all k I n , there exists ( u k ) V k , such that

F ( x j e j ) , e j = 0 for all 1 j d , with d = dim V k

Taking u k = ( x k i e i ) , e i V k , so we obtain:

F ( u k ) , φ = 0, for all φ V k .

Proposition 3.2 The Galerkin approximations sequence constructed in corollary (3.1) is uniformly bounded in W 0 1, p ( Ω , ω , I R m ) ; i.e.,

There exists a constant R > 0 , such that u k 1 , p , ω R , for all k I N .

Proof Like in the proof of proposition (3.1), we can see that

F ( u ) , u as u 1, p , ω .

Then, there exists R satisfying F ( u ) , u > 1 when u 1 , p , ω > R . Now, for the sequence of Galerkin approximations ( u k ) V k of corollary (3.1), which satisfying F ( u k ) , u k = 0 , we have the uniform bound u k 1, p , ω R , for all k I N .

Remark 3.3 There exists a subsequence ( u k ) of the sequence ( u k ) V k , such that:

u k u in W 0 1, p ( Ω , ω , I R m )

and

u k u in measure in L r ( Ω , I R m ) ;

with

{ 1 r n p s n ( s + 1 ) p s if p s n ( s + 1 ) r 1 if n ( s + 1 ) p s

The gradient sequence ( D u k ) generates the young measure ϑ x . Since u k u in measure, then ( u k , D u k ) generates the Young measure ( δ u ( x ) ϑ x ) , see [2]. Moreover, for almost x in Ω , we have,

1) ϑ x is the probability measure, i.e., ϑ x m e s = 1 .

2) ϑ x is the W 1, p , ω gradient homogeneous young measure.

3) ϑ x , i d = D u ( x ) , see [18].

Proof. See [2]. (Dolzmann, N. Humgerbuhler S. Muller, Non linear elliptic system …)

4. Passage to the Limit

Now, we are in a position to prove our main result under convenient hypotheses.

Let

I k = ( σ ( x , u k , D u k ) σ ( x , u , D u ) ) : ( D u k D u ) . (4.1)

Lemma 4.1 (Fatou lemma type)(See [2] ) Let: F : Ω × I R m × I M m × n I R be a Carathéodory function, and u k : Ω I R m a measurable sequence, such that ( D u k ) generates the Young measure ϑ x , with ϑ x m e s = 1 , for a.e. x Ω . Then:

lim inf k Ω F ( x , u k , D u k ) d x Ω I M m × n F ( x , u , ζ ) d ϑ x ( ζ ) d x , (4.2)

which provided that the negative part of F ( x , u k , D u k ) is equi-integrable.

Proof.

Lemma 4.2 Let p > 1 and u k be a sequence which is uniformly bounded in W 0 1, p ( Ω , ω , I R m ) . There exists a subsequence of u k (for convenience not relabeled) and a function u W 0 1, p ( Ω , ω , I R m ) such that u k u in W 0 1, p ( Ω , ω , I R m )

And such that u k u in measure on Ω and in L r ( Ω , I R m ) , with:

{ 1 r n p s n ( s + 1 ) p s if p s n ( s + 1 ) r 1 if n ( s + 1 ) p s

Proof. see [10].

Lemma 4.3 The sequence ( I k ) is equi-integrable.

Proof

We have

I k = ( σ ( x , u k , D u k ) σ ( x , u , D u ) ) : ( D u k D u ) = [ σ ( x , u k , D u k ) : D u k ] [ σ ( x , u k , D u k ) : D u ] [ σ ( x , u , D u ) : D u k ] + [ σ ( x , u , D u ) : D u ] = I k 1 + I k 2 + I k 3 + I k 4 (4.3)

We denote ( I k 1 ) = [ σ ( x , u k , D u k ) : D u k ] . Thanks to the coercivity condition (H2), we have

Ω | ( I k 1 ) | d x Ω | λ 2 | + c 2 1 j m ω 0 j α p | λ 3 | | u k j | α + c 1 i , j n , m ω i j | D i j u k | p d x λ 2 1 + Ω ( 1 j m ω 0 j α / p | u k j | α ) p / α λ 3 ( p / α ) + c 2 u k 1, ω , p p (4.4)

with p / α 1 . Therefore,

Ω | ( I k 1 ) | d x λ 2 1 + ( 1 j m ω 0 j | u k j | p ) α / p λ 3 ( p / α ) + c 2 u k 1 , ω , p p λ 2 1 + u k p , ω ¯ 00 α λ 3 ( p / α ) + c 2 u k 1 , ω , p p < ,

for all Ω Ω .

Similarly for | ( I k 4 ) | .

Now, by using the growth condition (H2) and the Hardy inequality (H0), we have

Ω | ( I k 2 ) | d x = Ω | σ ( x , u k , D u k ) : D u k | d x β Ω ω r s 1 / p ( λ 1 + c 1 1 j m γ j 1 / p | u k j | q / p + c 2 1 i , j n , m ω i j 1 / p | D i j u k | p 1 ) D r s u k d x . (4.5)

Thus, by the Hölder inequality, we obtain

Ω | ( I k 2 ) | d x β [ λ 1 p ( Ω | D r s u k | p ω r s d x ) 1 / p + c 1 ( Ω | D r s u k | p ω r s d x ) 1 / p ( Ω ( 1 j m γ j 1 / p | u k j | q / p ) p d x ) 1 / p + c 1 ( 1 j m Ω ( | D i j u k ( x ) | p ( p 1 ) ω i j d x ) 1 / p ) ( Ω | D r s u k | p ω r s d x ) 1 / p ] . (4.6)

So, by combining (4.5) and (4.6), we deduce that

Ω | σ ( x , u k , D u k ) : D u k | d x c β ( λ 1 p u k 1, p , ω + u k 1, p , ω ) < . (4.7)

Similarly to | ( I k 2 ) | , we obtain | ( I k 3 ) | . Finally: I k is equi-integrable.

We choose a sequence φ k such that φ k belongs to the same space V k and φ k φ in W 0 1, p ( Ω , ω , I R m ) , this allows us in particular, to use u k φ k as a test function in (3.1). We have:

Ω | σ ( x , u k , D u k ) : ( D u k D φ k ) | d x = v , u k φ k + Ω f ( x , u k , D u k ) ( u k φ k ) d x Ω g ( x , u k ) : ( D u k D φ k ) d x . (4.8)

The first term on the right in 4.8 converge to zero since ( u k φ k ) 0 in W 0 1, p ( Ω , ω , I R m ) . By the choice of φ k , the sequence φ k uniformly bounded in W 0 1, p ( Ω , ω , I R m ) , and lemma (4.2). Next, for the second term: I I k = Ω f ( x , u k , D u k ) ( u k φ k ) d x in 4.8 it follows from the growth condition F 1 and the Hölder inequality that:

| I I k | ( b 1 p + c 1 D ( u k φ k ) 1, p , ω + c 2 D ( u k φ k ) p p ) u k φ k 1, p , ω ( b 1 p + c D ( u k φ k ) 1, p , ω ) u k φ k 1, p , ω

By the equivalence of the norm in W 0 1, p ( Ω , ω , I R m ) and the sequence u k is uniformly bounded in W 0 1, p ( Ω , ω , I R m ) , u k 1, p , ω is bounded.

Moreover, by the construction of φ k , and lemma (4.2) we have:

u k φ k 1, p , ω u k u 1, p , ω + u φ k 1, p , ω

( u k u 1, p , ω + u φ k 1, p , ω ) 0

We infer that the second term in 4.8 vanishes as k . Finally, for the last term

I I I k = Ω g ( x , u k ) : D ( u k φ k ) d x

in 4.8, we note that

g ( x , u k ) g ( x , u )

Strongly in L p ( Ω , M m × n ) by ( G 0 ) , ( G 1 ) and lemma (4.2).

Indeed we may assure that u k u almost everywhere.

I I I k ( b 2 p + u k φ k q , γ q p ) D ( u k φ k ) 1, p , ω c ( b 2 p + u k φ k q , γ q p ) ( u k φ k ) 1, p , ω c ( b 2 p + u k φ k q , γ q p ) ( u k u 1, p , ω + φ k u 1, p , ω )

φ k u 1, p , ω 0 , u k u 1, p , ω 0 and u k φ k q , γ q p 0

Now, we consider ( I k ) = σ ( x , u k , D u k ) : ( D u k D u ) . We have, I k is equi-integrable because I k it is. So, we define

X = lim inf Ω I k d x = lim inf Ω ( I k ) d x Ω I M m × n ( σ ( x , u , λ ) : ( λ D u ) ) d ϑ x ( λ )

So to prove (??), it suffices to prove that:

X 0. (4.9)

Let ε > 0 , so there exists k 0 I N such that, for all k > k 0 , we have d i s t ( u , V k ) < ε since: lim inf φ k V k u φ k 1 , p , ω < ε , ( u k u )

Or in an equivalent manner d i s t ( u k u , V k ) < ε , k > k 0 then for all v k V k , we have

X = lim inf k Ω ( σ ( x , u k , D u k ) : ( D u k D u ) ) d x = lim inf k [ Ω ( σ ( x , u k , D u k ) : D ( u k u φ k ) ) d x + Ω ( σ ( x , u k , D u k ) : D ( φ k ) ) ]

Combining (H2) and (0.1), we get

X lim inf k Ω β ω r s 1 / p [ λ 1 + c 1 1 j m γ j 1 / p | u k j | q / p + c 1 1 i , j n , m ω i j 1 / p | D i j u k | p 1 ] × | D r s ( u k u φ k ) | d x + v , φ k .

For all ε > 0 , we choose φ k V k such that

u k u φ k 1, p , ω 2 ε , (4.10)

For all k k 0 , which implies that

| v , φ k | | v , φ k + ( u u k ) | + | v , u k u | 2 ε v 1, p , ω + o ( k )

Hence lim k v , u k u = 0 . According to Hölder and Hardy inequalities, and by (4.1) we deduce that

X lim inf k c β ( λ 1 p ( Ω | D r s ( u k u φ k ) | p ω r s d x ) 1 / p + c 1 ( Ω | u k | q γ ) 1 / p ( Ω | D r s ( u k u φ k ) | p ω r s d x ) 1 / p + c 1 ( Ω ω i j | D i j u | p ( p 1 ) ) 1 / p ( Ω ω r s | D r s ( u k u φ k ) | p ) 1 / p ) + | v , φ k | lim inf k c ( λ 1 p u k u φ k 1 , p , ω ) + u k 1 , p , ω q u k u φ k 1 , p , ω + 2 ε v 1 , p , ω + o ( k )

Therefore,

X 2 ε c β ( λ 1 p + u 1, p , ω q + v 1, p , ω * ) .

which proves that X 0 , and finally

Ω I M m × n σ ( x , u , λ ) : λ d ϑ x d x Ω I M m × n σ ( x , u , λ ) : D u d ϑ x ( λ ) d x .

Proof of theorem:

For arbitrary φ in W 0 1, p ( Ω , ω , I R m ) . It follows from the continuity condition ( F 0 ) and ( G 0 ) that

f ( x , u k , D u k ) φ ( x ) f ( x , u , D u ) φ ( x )

and

g ( x , u k ) : D φ ( x ) g ( x , u ) : D φ ( x )

almost everywhere. Since, by the growth conditions ( F 1 ) , ( G 1 ) and the uniform bound of u k , f ( x , u k , D u k ) φ ( x ) and g ( x , u k ) : D φ ( x ) are equi-integrable, it follows that the Vitali’s theorem. This implies that:

lim k Ω f ( x , u k , D u k ) φ ( x ) d x = Ω f ( x , u , D u ) φ ( x ) d x

for all φ k = 1 V k and

lim k Ω g ( x , u k ) : D φ ( x ) d x = Ω g ( x , u ) : D φ ( x ) d x

for all φ k = 1 V k We will start with the easiest case

(d): F σ ( x , u , F ) is strict p-quasi-monotone. (4.11)

Indeed, we assume that ϑ x is not a Dirac mass on the set M with x M of positive Lebesgue measure | M | > 0 . Moreover, by the strict p-quasi-monotonicity of σ ( x , u , ) and ϑ x is an homogeneous W 1, p gradient young measure for a.e. x M . So, for a.e. x M , with λ ¯ = ϑ x , I d = a p D u ( x ) , with a p D u ( x ) is the differentiable approximation in x. We get

I M m × n σ ( x , u , λ ) : ( λ D u ) d ϑ x ( λ ) > I M m × n σ ( x , u , D u ) : ( λ D u ) d ϑ x ( λ ) > σ ( x , u , D u ) : I M m × n λ d ϑ x ( λ ) σ ( x , u , D u ) : D u I M m × n d ϑ x ( λ ) > ( σ ( x , u , D u ) : D u σ ( x , u , D u ) : D u ) = 0 > 0

On the other hand (4.9), integrating over Ω , and using the div-cul inequality we have:

Ω I M m × n σ ( x , u , λ ) : λ d ϑ x ( λ ) d x > Ω I M m × n σ ( x , u , λ ) : D u d ϑ x ( λ ) d x Ω I M m × n σ ( x , u , λ ) : λ d ϑ x ( λ ) d x .

Which is a contradiction with (3.8). Thus ϑ x = δ λ ¯ = δ D u ( x ) for a.e. x Ω . Therefore, D u k D u in measure when k tends to infinity. Then, we get σ ( x , u k , D u k ) σ ( x , u , D u ) for all x Ω . In the other hand, for all φ k I N ϑ k ; σ ( x , u k , D u k ) : D φ σ ( x , u , D u ) : D φ a.e. x Ω . Moveover, for all Ω Ω measurable, it is easy to see that:

Ω σ ( x , u k , D u k ) : D φ d x c β ( λ 1 p + u k 1, p , ω q / p + u k 1, p , ω p / p ) u 1, p , ω < ,

because u k 1, p , ω R . And thanks to Vitali’s theorem, we obtain:

F ( u ) , φ = 0 , for all φ k I N ϑ k .

which proves the theorem in this case.

Remark 4.1 Before treating the cases (a),(b) and (c) of (H3), we note that

Ω I M m × n ( σ ( x , u , λ ) σ ( x , u , D u ) ) : ( λ D u ) d ϑ x ( λ ) d x 0 (4.12)

Since

Ω I M m × n σ ( x , u , λ ) : ( λ D u ) d ϑ x ( λ ) d x = 0,

thanks to the div-Curl inequality in (4.9). On the other hand, the integrand in (4.12) is non negative, by the monotonicity of σ . Consequently, the integrating should be null, a.e., with respect to the product measure d ϑ x d x , which mean

( σ ( x , u , λ ) σ ( x , u , D u ) ) : ( λ D u ) = 0 in s p t ϑ x . (4.13)

Thus,

s p t ϑ x { λ I M m × n / ( σ ( x , u , λ ) σ ( x , u , D u ) ) : ( λ D u ) = 0 } . (4.14)

Case c: We prove that, the map F σ ( x , u , F ) is strictly monotone, for all x Ω and for all u I R m .

Sine σ is strict monotone, and according to (4.14),

s p t ϑ x = { D u } , i .e , ϑ x = δ D u , a .e . in Ω ,

which implies that, D u k D u in measure. For the rest of our prove is similarly to case d.

Case b: We start by showing that for almost all x Ω , the support of ϑ x is contained in the set where W agrees with the supporting hyper-plane.

L = { ( λ , W ( x , u , λ ¯ ) + σ ( x , u , λ ¯ ) : ( λ λ ¯ ) ) } with λ ¯ = D u ( x ) .

So, it suffices to prove that

s p t ϑ x K x = { λ I M m × n / W ( x , u , λ ) = W ( x , u , λ ¯ ) + σ ( x , u , λ ¯ ) : ( λ λ ¯ ) } (4.15)

If λ s p t ϑ x , thanks to (4.14), we have

( 1 t ) ( σ ( x , u , D u ) σ ( x , u , λ ) ) : ( D u λ ) = 0, for all t [ 0,1 ] . (4.16)

On the other hand, since σ is monotone, for all t [ 0,1 ] we have:

( 1 t ) ( σ ( x , u , D u + t ( λ D u ) ) σ ( x , u , λ ) ) : ( D u λ ) 0. (4.17)

By subtracting (4.16) from (4.17), we get

( 1 t ) [ σ ( x , u , λ ¯ + t ( λ λ ¯ ) ) σ ( x , u , λ ¯ ) ] : ( λ ¯ λ ) 0, (4.18)

for all t [ 0,1 ] . Doing the same by the monotonicity in (4.18), we obtain

( 1 t ) [ σ ( x , u , λ ¯ + t ( λ λ ¯ ) ) σ ( x , u , λ ¯ ) ] : ( λ ¯ λ ) 0. (4.19)

Combining (4.18) and (4.19), we conclude that

( 1 t ) [ σ ( x , u , λ ¯ + t ( λ λ ¯ ) ) σ ( x , u , λ ¯ ) ] : ( λ ¯ λ ) = 0, (4.20)

for all t [ 0,1 ] , and for all λ s p t ϑ x .

Now, it follows from (4.19) that

W ( x , u , λ ) = W ( x , u , λ ¯ ) + ( W ( x , u , λ ) W ( x , u , λ ¯ ) ) = W ( x , u , λ ¯ ) + 0 1 [ σ ( x , u , λ ¯ ) + t ( λ λ ¯ ) ] : ( λ λ ¯ ) d t = W ( x , u , λ ¯ ) + σ ( x , u , λ ¯ ) : ( λ λ ¯ )

Witch prove (4.15).

Now, by the coercivity of W, we get

W ( x , u , λ ) W ( x , u , λ ¯ ) + σ ( x , u , λ ¯ ) : ( λ λ ¯ ) ,

for all λ I M m × n . Therefore,

L is a supporting hyper-plane, for all

λ K x . (4.21)

Moveover, the mapping λ W ( x , u , λ ) is continuously differentiable, so we obtain

σ ( x , u , λ ) = σ ( x , u , λ ¯ ) , for all λ K x . (4.22)

Thus,

σ ¯ ( x ) = I M m × n σ ( x , u , λ ) d ϑ x ( λ ) = σ ( x , u , λ ¯ ) . (4.23)

Now, we consider the Carathéodory function

g v ( x , u , ρ ) = | ( σ ( x , u , ρ ) σ ¯ ( x ) ) : D φ | ,

and lets g k ( x ) = g φ ( x , u k , D u k ) is equi-integrable. Thus, thanks to BALL’s theorem, see [6] g k g weakly in L 1 ( Ω ) , and the weakly limit of g is given by

g ¯ φ ( x ) = I R m × I M m × n | σ ( x , η , λ ) σ ¯ ( x ) | d δ u ( x ) ( η ) d ϑ x ( λ ) = s p t ϑ x | σ ( x , u ( x ) , λ ) σ ¯ ( x ) | d ϑ x ( λ ) = 0.

According to (4.22) and (4.23), and since g k 0 , it follow that g k 0 strongly in L 1 ( Ω ) by Fatou lemma, which gives

lim k Ω σ ( x , u k , D u k ) : D φ d x = Ω σ ( x , u , D u ) : D φ d x .

Thus

F ( u ) , φ = 0, φ k I N V k .

This completes the proof of the case (b).

Case (a): In this case, on s p t ϑ x , we affirm that,

σ ( x , u , λ ) : M = σ ( x , u , D u ) : M + ( F σ ( x , u , D u ) : M ) : ( D u λ ) , (4.24)

for all M I M m × n , where F is the derivative with respect to the third variable of σ and λ ¯ = D u ( x ) .

Thanks to the monotonicity of σ , we have

( σ ( x , u , λ ) σ ( x , u , D u + t M ) ) : ( λ D u t M ) 0, for all t I R .

By invoking (4.19), we obtain

σ ( x , u , λ ) : ( t M ) σ ( x , u , D u ) : ( λ D u ) + σ ( x , u , D u + t M ) : ( λ D u t M ) .

On the other hand, F σ ( x , u , F ) is a C 1 function, so

σ ( x , u , D u + t M ) = σ ( x , u , D u ) + F ( x , u , D u ) ( t M ) + o ( t ) .

Thus

σ ( x , u , λ ) : ( t M ) σ ( x , u , D u ) : ( t M ) + F σ ( x , u , D u ) ( t M ) : ( λ D u ) + o ( t ) ,

which gives

σ ( x , u , λ ) : ( t M ) t [ F σ ( x , u , D u ) : ( M ) : ( λ D u ) σ ( x , u , D u ) : ( M ) ] + o ( t ) ,

t is arbitrary in (4.24).

Finally for all φ k I N V k the sequence σ ( x , u k , D u k ) : D φ is equi-integrable. Then, by the BALL’s theorem, see [1] the weak limit is s p t ϑ x σ ( x , u , λ ) : D φ d ϑ x ( λ )

By choosing M = D u in (4.24), we obtain

s p t ϑ x ( D u λ ) ( σ ( x , u , λ ) : D φ ) : D φ d ϑ x ( λ ) = s p t ϑ x σ ( x , u , D u ) : D φ d ϑ x ( λ ) + ( F σ ( x , u , D u ) : D φ ) t s p t ϑ x ( D u λ ) d ϑ x ( λ ) = ( σ ( x , u , D u ) : D φ ) s p t ϑ x d ϑ x ( λ ) = σ ( x , u , D u ) : D φ .

Hence:

σ ( x , u k , D u k ) : D φ σ ( x , u , D u ) : D φ strongly

This proves that

F ( u ) , φ = 0 for all φ V k .

And since V k is dense in W 0 1, P ( Ω , ω , I R m ) , so u is a weak solution of ( Q E S ) f , g , as desired.

Remark 4.2 In case (b) σ ( x , u k , D u k ) : D φ σ ( x , u , D u ) : D φ strongly, but in the case (c) and (d) D u k D u in measure.

Exemple 4.1 We shall suppose that the weight functions satisfy: w i 0 j = 0 , j = 1 , 2 , , m for some i 0 I c ; and ω i j ( x ) = w ( x ) ; x Ω , with I c I = { 0 ; 1 ; 2 ; ; n } , for all i I I c , j = 1 , 2 , , m , and i i 0 with w ( x ) > 0 a.e in Ω then, we can consider the Hardy inequality in the form:

( j = 1 m Ω | u j ( x ) | q γ j ( x ) d x ) 1 q c ( 1 i N , 1 j m Ω | D i j u | p ω i j ) 1 p ,

for every u W 0 1, p ( Ω , ω , I R m ) with a constant c > 0 independent of u and for some q > p . Let us consider the Carathéodory functions: ( ⋆ )

σ i j ( x , η , ξ I ) = ω ( x ) | ξ i j | p 1 s n g ( ξ i j ) , j = 1 , 2 , , m , i I

σ i j ( x , η , ξ I c ) = ω ( x ) | ξ i j | p 1 s n g ( ξ i j ) , j = 1 , 2 , , m , i I c , i i 0

σ i 0 j ( x , η , ξ I c ) = 0 , j = 1 , 2 , , m

f j ( x , η , ξ ) = s i g n ( ξ ) r s ω r s 1 p | ξ | p 1 ω 0 j 1 p

The above functions defined by ( ) satisfies the growth conditions (H2).

In particular, let use the special weight function ω , γ expressed in term of the distance to the boundary Ω denote d ( x ) = d i s t ( x ; Ω ) and ω ( x ) = d λ ( x ) , γ j ( x ) = d μ ( x ) the hardy inequality reads:

( j = 1 m Ω | u j ( x ) | q d μ ( x ) d x ) 1 q c ( 1 i N , 1 j m Ω | D i j u | p d λ ( x ) ) 1 p ,

and the corresponding W 0 1, p ( Ω ; ω ; R m ) L q ( Ω ; γ ; R m ) is compact if:

1) For, 1 < p q <

λ < p 1 ; n q n p + 1 0 ; μ q λ p + n q n p + 1 > 0

2) For, 1 q < p <

λ < p 1 ; n q n p + 1 0 ; μ q λ p + 1 q 1 p + 1 > 0

3) For, q > 1

μ ( q 1 ) < 1 , by the simple modifications of the example in [11]. Moreover, the monotonicity condition are satisfied:

i j ( σ i j ( x , η , ξ I ) σ i j ( x , η , ξ I ) ) ( ξ i j ξ i j ) = ω ( x ) i j ( | ξ i j | p 1 s n g ( ξ i j ) | ξ i j | p 1 s n g ( ξ i j ) ) ( ξ i j ξ i j ) 0

for almost all x Ω and for all, ξ , ξ M n . This last inequality cannot be strict, since for ξ I c ξ I c with ξ i 0 j ξ i 0 j for all j = 1 , 2 , , m . But ξ i j = ξ i j for i I c , i i 0 , j = 1 , 2 , , m the corresponding expression is Zero.

Conflicts of Interest

The authors declare no conflicts of interest regarding the publication of this paper.

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