The Generalized Burning Number of Gear Graph and Sun Graph

Abstract

Graph burning is a model for describing the spread of influence in social networks and the generalized burning number b r ( G ) of graph G is a parameter to measure the speed of information spread on network G . In this paper, we determined the generalized burning number of gear graph, which is useful model of social network. We also provided properties of the generalized burning number of sun graphs, including characterizations and bounds.

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Wu, J. and Li, Y. (2025) The Generalized Burning Number of Gear Graph and Sun Graph. Journal of Applied Mathematics and Physics, 13, 157-165. doi: 10.4236/jamp.2025.131007.

1. Introduction

Graph burning is a discrete-time process on graphs, which is a model for describing the spread of influence in social networks. In [1], Bonato et al. introduced the burning number of graph G to measure the speed of contagion spread on G . Research on graph burning see [2]. In [3], authors generalized the concept of burning number b( G ) of graph G and proposed the generalized burning b r ( G ) with b 1 ( G )=b( G ) .

For a given graph G with the maximum degree Δ( G ) and a positive integer 1rΔ( G ) , we defined a r -burning process on G : When t=0 , all vertices are unburned. At time t1 , an unburned vertex is chosen to burn (call it a fire source) and a vertex v will be burned at time t if and only if v has at least r neighbor vertices have been burned before time t . They defined the generalized burning number of G is the minimum number of time steps of r -burning process of G . If graph G can be burned in k steps and the i -th fire source is x i ( 1ik ) , the sequence ( x 1 , x 2 ,, x k ) call a r -burning sequence of G . Clearly, the generalized burning number b r ( G ) is the length of the shortest r -burning sequence of G , such sequence call an optimal r -burning sequence of G .

The gear graph G n is obtained from the wheel graph W n by adding a vertex between every pair of adjacent vertices of the n -cycle. A sun graph is a graph obtained from a g -cycle by attaching pendant edges to some vertices. We by

S={ S g a 1 ,, a g :n=g+ i=1 g a i } denote the sun graph with g -cycle C g ={ v 1 , v 2 ,, v g } and v i has a i leaf vertices (see Figure 1).

(a) gear graph G n

(b) sun graph S g a 1 ,, a g

Figure 1. Gear graph G n and sun graph S g a 1 ,, a g .

In [4], Wei et al. determined the Wiener index of gear graph. In [5], Prajapati et al. discussed the product cordial labeling of gear graph. Ali et al. studied the radio number of generalized gear graph in [6]. Khan determined the L(1,1,1)-chromatic number for sun graph in [7]. In this paper, we determined the generalized burning number of gear graph and sun graph.

All graphs considered in this paper are finite and simple. We use book [8] for notation and terminology not defined here. We by d G ( u,v ) denote the distance between vertex u and v , by N k [ v ] denote the k -th closed neighborhood of v . Without causing confusion, d G ( u,v ) and N 1 [ v ] are simplified by d( u,v ) and N[ v ] , respectively.

2. Preliminaries

Proposition 2.1. [3] Let C n be a cycle of order n . Then b 2 ( C n )= n 2 +1 .

A subgraph H of graph G is called an isometric subgraph if for every pair of nodes u and v in H , we have that d H ( u,v )= d G ( u,v ) .

Proposition 2.2. [1] For any isometric subgraph H of a graph G , we have that b( H )b( G ) .

Proposition 2.3. [9] A graph G satisfies b( G )=2 if and only if G has order at least 2 and has maximum degree n1 or n2 .

Proposition 2.4. [9] For a cycle C n , we have b( C n )= n   .

Proposition 2.5. [9] If ( x 1 , x 2 ,, x k ) is a sequence of nodes in a graph G, such that N k1 [ x 1 ] N k2 [ x 2 ] N 0 [ x k ]=V( G ) , then b( G )k .

3. Main Results

In this section, we determined the generalized burning number of gear graph and sun graphs and gave bound of the generalized burning number. By the definition of the generalized burning number, we directly get the following Lemma.

Lemma 3.1. Let G be a connected graph of order n and 1rΔ( G ) . If there are k vertices with degree more than r , then nk b r ( G )n .

Now we determined the generalized burning number of the gear graph G n .

Theorem 3.2. Let G n be a gear graph of order 2n+1 for n3 . Then

b r ( G n )={ 3, ifr=1; n 2 +3, ifr=2; n+2, ifr=3; 2n, if4rn.

Proof. Suppose V( G n )={ v, v 1 , v 2 ,, v n , w 1 , w 2 ,, w n } , we distinguish cases as follow.

Case 1. r=1

By Proposition 2.3, we know that b( G n )3 . On the other hand, let x 1 =v , x 2 = v 1 and x 3 = w n1 . Consider N 2 [ x 1 ] N 1 [ x 2 ] N 0 [ x 3 ]=V( G n ) , by Proposition 2.5, thus b( G n )3 . Hence, we have b( G n )=3 .

Case 2. r=2

If n is odd, let n=2k1 , x 1 =v , x k+2 = w n2 and x i = w 2i3 for 2ik+1 . Clearly, ( x 1 , x 2 ,, x k+2 ) is a 2-burning sequence of G n and thus b 2 ( G n )k+2 . Now, suppose ( x 1 , x 2 ,, x b ) is an optimal 2-burning sequence of G n and bk+1 . Consider x 1 and x b can only burn themselves. The total number vertices of G n can be burned at most 2+4( b2 )=4b64( k+1 )6=4k2 , a contradiction. Therefore,

b 2 ( G n )k+2 and b 2 ( G n )=k+2= n 2 +3 .

If n is even, let n=2k , x 1 =v , x k+2 = w n2 , x k+3 = w n and x i = w 2i3 for 2ik+1 . Clearly, ( x 1 , x 2 ,, x k+3 ) is a 2-burning sequence of G n and thus b 2 ( G n )k+3 . Conversely, suppose ( x 1 , x 2 ,, x b ) is an optimal 2-burning sequence of G n and bk+2 . Obviously, x 1 and x b can only burn themselves. Consider x 2 and x b1 can affect at most two neighboring vertices. After b steps, the vertices of G n can be burned at most 8+4( b4 )=4b84( k+2 )8=4k , a contradiction. Thus b 2 ( G n )k+3

and b 2 ( G n )=k+3= n 2 +3 .

Case 3. r=3

Let x n+1 =v , x n+2 = v 1 and x i = w i for 1in . Clearly, ( x 1 , x 2 ,, x n+2 ) is a 3-burning sequence of G n and thus b 3 ( G n )n+2 . Next, we show b 3 ( G n )n+2 . Since d( w i )=2 and r=3 for 1in , then w i and v must be fire sources in any optimum 3-burning sequence of G n . Moreover, there are at least one vertex of v i as fire source for 1in . Therefore, b 3 ( G n )n+2 and b 3 ( G n )=n+2 .

Case 4. 4rn

In this case, 4rn , then d( v )r , and by Lemma 3.1, we get that b r ( G n )2n . Conversely, let x i = v i for 1in and x j = v jn for n+1j2n . Obviously, ( x 1 , x 2 ,, x 2n ) be r -burning sequence of G n and thus b r ( G n )2n . Hence, we get b r ( G n )=2n . This completes the proof. □

Next, we determined the generalized burning number of S g a 1 .

Theorem 3.3. Let S g a 1 be a sun graph of order n . Then

(1) b( S g a 1 )= g ;

(2) b 2 ( S g a 1 )={ g 2 +1, if a 1 =1; g 2 +2, if a 1 =2; a 1 + g 2 1, if a 1 3.

(3) For 3r a 1 +2

b r ( S g a 1 )={ n, ifr= a 1 +2andg=3; n1, otherwise.

Proof. Let C g = v 1 v 2 v g v 1 and suppose the leaf vertices of v 1 are u i for 1i a 1 , we distinguish cases by r to complete the proof.

Case 1. r=1

Let k= g   , x 1 = v 1 and x ki = v n i 2 ik+1 for 0ik2 . Clearly, ( x 1 , x 2 ,, x k ) is a burning sequence of S g a 1 and thus b( S g a 1 )k= g . On the other hand, C g is an isometric subgraph of S g a 1 . By Proposition 2.2 and Proposition 2.4, we directly get b( S g a 1 )b( C g )= g . Hence, b( S g a 1 )= g .

Case 2. r=2

First, consider the case for a 1 =1 , let x k+1 = u 1 and x i = v 2i1 for 1ik . Clearly, ( x 1 , x 2 ,, x k+1 ) is a 2-burning sequence of S g a 1 and thus

b 2 ( S g a 1 )k+1= g 2 +1 . Now, we show b 2 ( S g a 1 ) g 2 +1 . Since a 1 =1 , by burning u 1 , we know that v 1 is unburned. Thus, the vertices of C g at least g 2 must be fire source. Because u 1 is leaf vertex, we get b 2 ( S g a 1 ) g 2 +1 . Then b 2 ( S g a 1 )= g 2 +1 .

Then, consider the case a 1 =2 , If g is odd, suppose g=2k1 , otherwise, g=2k . When g is odd, let x 1 = u 1 , x k+1 = u 2 and x i = v 2i2 for 2ik . Clearly, ( x 1 , x 2 ,, x k+1 ) is a 2-burning sequence of S g a 1 and thus

b 2 ( S g a 1 )k+1= g 2 +2 . Next, we will show that b 2 ( S g a 1 ) g 2 +1 . Since a 1 =2 , then v 1 can automatically burn. Hence, the vertices of C g at least g1 2 must be fire source. The leaf vertices must be fire source, we have that b 2 ( S g a 1 ) g1 2 +2= g 2 +2 . Therefore, b 2 ( S g a 1 )= g 2 +2 .

Now, when g is even, let x 1 = u 1 , x k+2 = u 2 and x i = v 2i2 for 2ik+1 . Clearly, ( x 1 , x 2 ,, x k+2 ) is a 2-burning sequence of S g a 1 , thus b 2 ( S g a 1 )k+2 . To the contrary, suppose ( x 1 , x 2 ,, x b ) is an optimal 2-burning sequence of S g a 1 and bk+1 . Note that x 1 and x b only can burn themselves. Namely, after b steps, the vertices of S g a 1 are burned at most 2+2( b2 )=2b22k , a contradiction, we can conclude that b 2 ( S g a 1 )k+2 . Therefore,

b 2 ( S g a 1 )=k+2= g 2 +2 .

As for the general cases a 1 3 . Let x 1 = u 1 , x 2 = u 2 , x i = v 2i3 for 3ik+1 and x j = u jk+1 for k+2j a 1 +k1 . Clearly, ( x 1 , x 2 ,, x a 1 +k1 ) is a 2-burning sequence of S g a 1 and thus b 2 ( S g a 1 ) a 1 +k1= a 1 + g 2 1 . Conversely, u i

must be fire source for 1i a 1 . Suppose x k is the last fire source. If a 1 3 , let x k u i and u i cause v 1 to burn automatically for 1i a 1 . Thus, the vertices

of C g at least g 2 1 must be fire source, we get b 2 ( S g a 1 ) a 1 + g 2 1 . Then b 2 ( S g a 1 )= a 1 + g 2 1 .

Case 3. 3r a 1 +2

When r= a 1 +2 and g=3 , by simple checking, we directly get b r ( S g a 1 )=n . When 3r< a 1 +2 , since d( v 1 )3 , combine Lemma 3.1, we have

b r ( S g a 1 )n1 . On the other hand, let x i = v i+1 for 1ig1 and x j = u jg+1 for gin1 . Clearly, ( x 1 , x 2 ,, x n1 ) is a r -burning sequence of S g a 1 and thus b r ( S g a 1 )n1 . □

Theorem 3.4. Let S= S g a 1 ,, a g be a sun graph with a i =1 for 1ig . Then

b r ( S )={ g1 +1, ifr=1; g+1, ifr=2; g+ g 2 , ifr=3.

Proof. Let C g = v 1 v 2 v g v 1 and suppose u i are leaf neighbors of the v i for 1ig .

Case 1. r=1

Let k= g1 +1 , we first show that b( S )k . Let x 1 = v 1 , x k = v k and x ki1 = v n i 2 ik+2 for 0ik2 . Clearly, ( x 1 , x 2 ,, x k ) is a burning sequence of S and thus b( S )k .

Now, we show that b( S )k . If g k 2 2k+2 , suppose ( x 1 , x 2 ,, x k ) be an optimal burning sequence of S . Since k is the minimum number satisfying this inequality, we get g1 +1b( S ) for g k 2 2k+2 . If g> k 2 2k+2 . Assume ( x 1 , x 2 ,, x α ) is a burning sequence of S , where α<k . For 1jα , the fire source x j it can spread to the vertices of N αj [ x j ] . For 1jα1 , N αj [ x j ] can contain at most 2( αj )1 leaf vertices of S and | N 0 [ x α ] |=1 .

Therefore, leaf vertices are burned at most 1+ j=1 α1 2( αj )1= α 2 2α+2 . Note

that | S\ C g |=g> k 2 2k+2> α 2 2α+2 , thus b( S )k . Therefore, b( S )=k= g1 +1 .

Case 2. r=2

Let x 1 = v 1 and x i = u i1 for 2ig+1 . Clearly, ( x 1 , x 2 ,, x g+1 ) is a 2-burning sequence of S and thus b 2 ( S )g+1 . Now, we only need to show b 2 ( S )g+1 . Consider d( u i )=1 and r=2 for 1ig , thus all u i must be fire source. If all a i =1 for 1ig , then at least one vertex of C g must also be selected as fire source. Therefore, b 2 ( S )g+1 .

Case 3. r=3

When g is odd, let x i = v 2i1 for 1i g 2 and x j = u j g 2 for g 2 +1jg+ g 2 . When g is even, let x g+ g 2 = u 1 , x i = v 2i1 for 1i g 2 and x j = u j g 2 +1 for g 2 +1jg+ g 2 1 . Clearly, ( x 1 , x 2 ,, x g+ g 2 ) is a 3-burning sequence of S and thus b 3 ( S )g+ g 2 .

Now, we show b 3 ( S )g+ g 2 . Since r=3 and d( u i ) for 1ig , thus all u i must be fire source. To burn all vertices of S , there are at least g 2 vertices of C g as fire source, we get b 3 ( S )g+ g 2 . Then b 3 ( S )=g+ g 2 . □

At the end of this section, we bounded of the generalized burning number of S g a 1 ,, a g .

Theorem 3.5. Let S= S g a 1 ,, a g be a sun graph with a cycle C g = v 1 v 2 v g and order n , where a i 1 for 1ig . Then

(1) g1 +1b( S ) g +1 ;

(2) ng b 2 ( S )ng+1 ;

(3) n| D r | b r ( S )n | D r | + | D r+1 | 2 for 3rΔ( S ) , where D r ={ v i |d( v i )r,1ig } .

Proof. First, when r=1 . Consider S g 1,,1 is an isometric subgraph of S , by Proposition 2.2 and Theorem 3.4, we derive that g1 +1b( S ) . Now, we show b( S ) g +1 . We set k= g +1 , let x k = u g4 and x ki = v g i 2 +i

for 1ik2 . Also, if g ( k1 ) 2 k+3 , we take x 1 = v g ( k1 ) 2 +( k1 ) ; otherwise x 1 = v 1 . Clearly, ( x 1 , x 2 ,, x k ) is a burning sequence of S . Hence, b( S )k= g +1 .

Now, for r=2 . If d( v i )2 for 1ig , by Lemma 3.1, then b 2 ( S )ng . Now, we show b 2 ( S )ng+1 . Let u i be leaf vertices of S for 1ing . Without loss of generality, set a 1 a i , for 2ig . Let x 1 = v 1 and x i = u i1 for 1ing+1 . Obviously, ( x 1 , x 2 ,, x ng+1 ) is a 2-burning sequence of S . Therefore, we get b 2 ( S )ng+1 .

The general cases for 3rΔ( S ) . If v D r , Lemma 3.1, we gain that

b r ( S )n| D r | . Further, we will show that b r ( S 1 )n | D r | + | D r+1 | 2 . The leaf

vertices and { v i |d( v i )<r,1ig } must be fire sources in any r -burning process of S . Let S 1 = S g a 1 ,, a g with a 1 a 2 a g . Clearly, b r ( S 1 ) b r ( S ) . Further, by simple checking, we find that in any r -burning process of S 1 , there

are at least | D r+1 |+ | D r | | D r+1 | 2 vertices would be burned by some fire sources. Thus we have b r ( S 1 )n( | D r+1 |+ | D r || D r+1 | 2 )n | D r |+| D r+1 | 2 . Hence,

b r ( S )n | D r |+| D r+1 | 2 . This completes the proof. □

By Theorem 3.5, we immediately get Corollary 3.6.

Corollary 3.6. Let S= S g a 1 ,, a t be a sun graph with a cycle C g = v 1 v 2 v g and order n , where t<g . Then

(1) g b( S ) g1 +1 ;

(2) n| D r | b r ( S )n | D r |+| D r+1 | 2 for 2rΔ( S ) , where D r ={ v i |d( v i )r,1ig } .

Proof. For the case r=1 , if all a i 1 and exist a i =1 for 1ig , then S is denoted by S 1 . First, we show that b( S 1 ) g1 +1 . Note that S g 1,,1 is an isometric subgraph of S 1 . Combine Proposition 2.2 and Theorem 3.4, we get g1 +1=b( S g 1,,1 )b( S 1 ) . Now, we will show b( S 1 ) g1 +1 and set k= g1 +1 . Without loss of generality, let a g4 =1 and w be leaf vertex of v g4 . Choose x k =w , x k1 = v g , x k2 = v g2 and x ki = v g1 i 2 +i for

1ik2 . Also, if g ( k1 ) 2 k+3 , we take x 1 = v g1 ( k1 ) 2 +( k1 ) ; otherwise

let x 1 = v 1 . Clearly, ( x 1 , x 2 ,, x k ) is a burning sequence of S 1 , then b( S 1 )k= g1 +1 . Further, we know that S is an isometric subgraph of S 1 , by Proposition 2.2, then b( S )b( S 1 )= g1 +1 .

Next, we show b( S ) g . Obviously, S g a 1 is an isometric subgraph of S , by Proposition 2.2 and Theorem 3.3, we have b( S )b( S g a 1 )= g .

The general cases for 2rΔ( S ) , by Theorem 3.5, we directly get n| D r | b r ( S )n | D r |+| D r+1 | 2 . This completes the proof. □

Acknowledgements

The authors would like to thank anonymous reviewers for their valuable comments and suggest to improve the quality of the article.

Funding

Supported by AFSFQH (2022-ZJ-753) and NSFC (12371352).

Conflicts of Interest

The authors declare no conflicts of interest regarding the publication of this paper.

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