_{1}

The non PT-symmetric exactly solvable Hamiltonian describing a system of a fermion in the external magnetic field which couples to a harmonic oscillator through some pseudo-hermitian interaction is considered. We point out all properties of both of the original Mandal and the original Jaynes-Cummings Hamitonians. It is shown that these Hamiltonians are respectively pseudo-hermitian and hermitian REF _Ref536606452 \r \h \* MERGEFORMAT [1] REF _Ref536606454 \r \h [2]. Like the direct approach to invariant vector spaces used in Refs. REF _Ref536606456 \r \h [3] REF _Ref536606457 \r \h [4], we reveal the exact solvability of both the Mandal and Jaynes-Cummings Hamiltonians after expressing them in the position operator and the impulsion operator.

Several new theoretical aspects in quantum mechanics have been developed in last years. In the series of papers [

An alternative property called pseudo-hermiticity for a Hamiltonian to be associated to a real spectrum is shown in details in the Refs. [

Referring the ideas of [

Another direction of quantum mechanics is the notions of quasi exact solvability and exact solvability [

In the last few years, a new class of operators has been discovered. This class is intermediate between exactly solvable operators and non solvable operators. Its name is the quasi-exactly solvable (QES) operators, for which a finite part of the spectrum can be computed algebraically.

This paper is organized as follows:

In Section 2, we briefly describe the general model which is expressed in terms of the creation and the annihilation operators. We show that the Hamiltonian describing the model is pseudo-hermitian if ϕ = − 1 , or it is hermitian if ϕ = + 1 .

In Section 3, we show in details the properties of the Mandal Hamiltonian namely the non-hermiticity, the non PT-symmetry, the pseudo-hermiticity and the exact solvability.

In Section 4, as in the previous section, it was pointed out that the original Jaynes-Cummings Hamiltonian is hermitian and exactly solvable.

In this section, we consider a Hamiltonian describing a system of a fermion in the external magnetic field, B which couples the harmonic oscillator interaction (i.e. ℏ ω a + a ) and the pseudo-hermitian interaction if ϕ = − 1 , or the hermitian interaction if ϕ = + 1 (i.e.

where

σ , σ ± denote Pauli matrices,

ρ , μ are real parameters,

a + , a refer the creation and annihilation operators respectively satisfying the usual bosonic commutation relation

[ a , a + ] = 1 , [ a , a ] = [ a + , a + ] = 0 and σ ± ≡ 1 2 ( σ x ± i σ y ) .

Recall that the matrices σ + , σ − , σ x , σ y and σ z can be expressed in the following matrix forms:

For the sake simplicity, one can choose the external field in the z-direction (i.e. B = B 0 z ) in order to reduce the Hamiltonian given by the Equation (1) and it becomes [

with ε = 2 μ B 0 and ℏ = 1 .

In this section, we reveal that the Hamiltonian described by the Equation (3) is non- hermitian if ϕ = − 1 . It is called Mandal Hamiltonian (i.e. H M ) and it takes the following form:

Taking account to the following identities:

let’s show that the Mandal Hamiltonian given by the above Equation (4) is non hermitian:

H M + = ( ε 2 σ z ) + + ( ω a + a ) + + [ ρ ( σ + a − σ − a + ) ] + ,

Comparing the expressions given by the Equations (4) and (6), we see that they are different (i.e. H M + ≠ H M ), as a consequence, we are allowed to conclude that the Mandal Hamiltonian H M is non-hermitian.

In this section, we prove that the Mandal Hamiltonian is non PT-symmetric [

The effect of the parity operator P implies the following changes [

Notice also the changes of the following quantities under the effect of the time reversal operator T:

Taking account to the relations (7) and (8), one can easily deduce the changes of the Mandal Hamiltonian under the effect of combined operators P et T as follows

This above relation (9) can be written as follows

Comparing the relations (4) and (10), we see that they are different (i.e. H M P T ≠ H M ), it means that the Mandal Hamiltonian H M is not invariant under the combined action of the parity operator P and the time-reversal operator T. In other words, the Mandal Hamiltonian H M is not PT-symmetric.

In this section, we first prove that the non PT-symmetric Mandal Hamiltonian is pseudo-hermitian with respect to third Pauli matrix σ z [

with σ z σ ± σ z − 1 = − σ ∓ and W n = e − ω x 2 2 ( P n − 1 ( x ) , P n ( x ) ) t .

Comparing the Equations (6) and (11), it is seen that the following relation is satisfied:

W n = e − ω x 2 2 ( P n − 1 ( x ) , P n ( x ) ) t (12)

Taking account to this above relation, we are allowed to conclude that the Mandal Hamiltonian is pseudo-hermitian with respect to σ z .

Finally, we reveal a pseudo-hermiticity of H M with respect to the parity operator P:

Here we have used the relations (7) in order to obtain this above equation (13). As a consequence, one can conclude that the Mandal Hamiltonian is pseudo-hermitian with respect to the parity operator P.

Note that even if H M is non hermitian and non PT-symmetric, its eigenvalues are entirely real due to the pseudo-hermiticity property [

In this step, our purpose is to change the Mandal Hamiltonian given by the Equation (4) in appropriate differential operator (i.e. H M is expressed in the position operator x and in the impulsion operator H J C + = ε 2 σ z + ω a + a + [ ρ ( σ + a + σ − a + ) ] ). Thus, referring to the ideas of exactly and quasi-exactly solvable operators studied in the Refs. [

With this aim, we use the usual representation of the creation and annihilation operators of the harmonic oscillator respectively a + and a [

where ω is the oscillation frequency, m denotes the mass, x refers to the position operator and the impulsion operator is

Using appropriate units, we can assume m = ℏ = 1 and the operators a + and a take the following forms:

Replacing the operators a + and a by their expressions given by this above Equation (15) in the Equation (4), the Mandal Hamiltonian H M takes the following form:

In order to reveal the exact solvability of the above operator H M , we first perform the standard gauge transformation [

After some algebraic manipulations, the new Hamiltonian H ˜ M (known as gauge Hamiltonian) is obtained

Replacing the Pauli matrices

Note that one can easily check if this above gauge Hamiltonian H ˜ M preserves the vector spaces of polynomials

Thus, the vector spaces preserved by the operator H M have the following form

where P n − 1 ( x ) and P n ( x ) denote respectively the polynomials of degree n − 1 and n.

As the gauge Mandal Hamiltonian H ˜ M , it is obvious that the original Mandal Hamiltonian H M is exactly solvable. Due to this property of exact solvability, the whole spectrum of H M can be computed exactly (i.e. by the algebraic methods) [

In this section, considering ϕ = + 1 , the Hamiltonian given by the Equation (3) leads to the standard Jaynes-Cummings Hamiltonian of the following form

H J C = ε 2 σ z + ω a + a + ρ ( σ + a + σ − a + ) (21)

Our aim is now to prove that the above Hamiltonian H J C is hermitian.

Indeed, in order to reveal the hermiticity of the Jaynes-Cummings Hamiltonian given by the above relation (21), the following relation H J C + = H J C must be satisfied.

Consider now the following relation

H J C + = ( ε 2 σ z ) + + ( ω a + a ) + + [ ρ ( σ + a + σ − a + ) ] + , (22)

Taking account to the identities of the relation (5), this above equation leads the following expression:

H J C + = ε 2 σ z + ω a + a + [ ρ ( σ + a + σ − a + ) ] . (23)

Comparing the Equations (21) and (23), one can write that

H J C + = H J C . (24)

Referring to this equation (24), it is obvious that the standard Jaynes-Cummings Hamiltonian is hermitian. As a consequence, its eigenvalues are real due to the property of hermiticity.

Along the same lines as in the above section 3.4, our purpose is to change the Jaynes-Cummings Hamiltonian given by the Equation (21) in appropriate differential operator (i.e. H J C is expressed in the position operator x and in the impulsion operator p = − i d d x ).

With this purpose, we use the usual expressions of the creation and annihilation operators of the harmonic oscillator respectively a + and a given by the Equation (15).

Substituting (15) in the Equation (21), the Jaynes-Cummings Hamiltonian H J C is written now as follows

H J C = ε 2 σ z + p 2 − ω + ω 2 x 2 2 + ρ [ σ + ( p − i ω x ) + σ − ( p + i ω x ) ] 2 ω (25)

Operating on the above operator H J C the standard gauge transformation as

H ˜ J C = R − 1 H J C R , R = exp ( − ω x 2 2 ) , (26)

after some algebraic manipulations, the new Hamiltonian H ˜ J C (known as gauge Hamiltonian) is obtained

H ˜ M = ε 2 σ z − 1 2 d 2 d x 2 + ω x d d x + ρ [ σ + p + σ − ( p + 2 i ω x ) ] 2 ω = ε 2 σ z + p 2 2 + i ω x p + ρ [ σ + p + σ − ( p + 2 i ω x ) ] 2 ω (27)

Replacing the Pauli matrices σ z , σ + and σ − respectively by their matrix form given by the relation (2), the final form of the gauge Hamiltonian H ˜ J C is

H ˜ M = ε 2 ( 1 0 0 − 1 ) + ( p 2 2 + i ω x p 0 0 p 2 2 + i ω x p ) + ρ ( 0 p 2 ω p + 2 i ω x 2 ω 0 ) ,

H ˜ M = ( p 2 2 + i ω x p + ε 2 ρ p 2 ω ρ p + 2 i ω x 2 ω p 2 2 + i ω x p − ε 2 ) . (28)

Note that one can easily check if this above gauge Hamiltonian H ˜ J C preserves the finite dimensional vector spaces of polynomials namely V n = ( P n − 1 ( x ) , P n ( x ) ) t with n ∈ Ν . As the integer n is arbitrary, the gauge Jaynes-Cummings Hamiltonian H ˜ J C is exactly solvable.

As a consequence, its all eigenvalues can be computed algebraically. Indeed, the vector spaces preserved by the operator H J C have the following form

W n = e − ω x 2 2 ( P n − 1 ( x ) , P n ( x ) ) t (29)

where P n − 1 ( x ) and P n ( x ) denote respectively the polynomials of degree n − 1 and n.

As the gauge Jaynes-Cummings Hamiltonian H ˜ J C , it is obvious that the standard Jaynes-Cummings Hamiltonian H J C is exactly solvable. In other words, all eigenvalues associated to the Hamiltonian H J C can be calculated algebraically (i.e. by the algebraic methods) [1-3].

In this paper, we have put out all properties of the original Mandal Hamiltonian. We have shown that the Mandal Hamiltonian H M is non-hermitian and non-invariant under the combined action of the parity operator P and the time-reversal operator T. Even if the previous properties are not satisfied, it has been proved that the Mandal Hamiltonian H M is pseudo-hermitian with respect to P and with respect to σ 3 also. With the direct method, we have revealed that H M preserves the finite dimensional vector spaces of polynomials namely V n = ( P n − 1 ( x ) , P n ( x ) ) t . Indeed, the Mandal Hamiltonian H M is said to be exactly solvable [

I thank Pr. Yves Brihaye of useful discussions.

The author declares no conflicts of interest regarding the publication of this paper.

Nininahazwe, A. (2019) Pseudo-Hermitian Matrix Exactly Solvable Hamiltonian. Open Journal of Microphysics, 9, 1-9. https://doi.org/10.4236/ojm.2019.91001