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On the basis of the vector formula of the Newton’s law for a viscous liquid and the integrated vector form of the equation of an impulse for a viscous liquid for resistance and carrying power of a profile of any form and the big length dependences are found in a stream. Application of the found dependences at a circulating flow of the cylinder located across a stream is showed. The analysis of a tensor of viscosity for laminar and turbulent flow is carried out.

The cross-section flow around of bodies of any profile arises at flights of planes, movement of hydrofoils, on wires of lines of a high voltage etc. The big contribution to the decision of a problem of a flow wingeous profile a stream of an ideal liquid was brought by outstanding scientist N. E. Zhukovsky’s formula for carrying power calculation, has a strict substantiation and is widely used in aerodynamic calculations [1,2].

At the decision of problems of a flow of bodies, for example, wingeous profile the integrated form of the impulse equation is interesting. Let’s find this form, using the equation of 2nd Newton’s law for elementary volume of a liquid dW in a following kind:

where a—acceleration of the allocated volume dW, r— liquid density,—the forces operating on the allocated volume of a liquid.

Writing acceleration in the form of the sum of local and convective components, we will receive:

Let’s integrate on volume the left and right members of Equation (2):

Let’s designate—A local component of quantity of movement of a liquid in weight dm in volume dW. Besides, we will use the theorem of the vector analysis [

. Believing a liquid incompressible, i.e., we have:

where S—The area of a surface limiting volume W.

The formula (4) represents the integrated form of the equation of an impulse [

Let’s find the amendment to the formula Zhukovsky for the carrying power, arising at the expense of viscosity of a stream of a liquid.

This correcting is carried out by addition to the formula of carrying power of some, poorly proved, additional composed till now [

Let’s consider some body Т which is permanently flowed round by a viscous liquid with accumulating speed and we will find the main (total) vector of forces with which the liquid operates on a body at its continuous flow,

Let some any contour abcd covers this body.

On a liquid between a body and a contour abcd three forces operate: pressure force –F_{p} from external in relation to a contour abcd liquids, force of a friction from external, in relation to this contour, a liquid and force from body Т which we will designate –R. We consider that positive values of forces operate on the contrary, from a liquid between a body and a contour abcd, so that, for example, R—The force operating on body Т from a liquid. The finding of last force also is the main task of the given research.

Believing a profile flow stationary, the integrated Equation (4), with the account and, it is possible to write down in a kind:

Pressure force is equal:

where р—Pressure in a liquid.

Using for force of a friction the vector form of the Newton’s law for viscosity in the form [

Hence, it is possible to present the Equation (5) in a kind:

The vertical component of force R, concerning speed,

The Equation (8) allows to solve essentially a problem of a flow a viscous liquid of a profile of any form. Most interesting from the practical point of view the established flow of a body a liquid concerning small viscosity (air), therefore, with some approach, we will accept communication of pressure and speed of a flow according to the equation of Bernulli:

where C—is a constant.

Substituting (9) in (8), we will receive:

.(10)

Let’s consider crossing by a running liquid of the allocated contour,

The external normal n is connected with ортами coordinates i, j, k and a corner q between axis Х and a tangent to a contour. Between a normal n and axis Х a corner

.

Hence:

.(11)

In last composed (10) we use a parity and the formula:

where V_{X} and V_{Z}—Components of a vector of speed V.

Substituting (11) and (12) in the formula (10), we have:

At substitution we used.

Projecting (13) on an axis of coordinates, we find making forces R:

In the further transformations we used also parities,

or

and

.(16)

Besides, we use also:

.

After corresponding substitutions, formulas (14) and (15) will be transformed to a kind:

In difference, for example, from [1,2] the analysis of a flow of a body we will spend, using flow function y, without entering potential of speed. It is connected by that the potential flow is considered not.

Projections of speed to coordinate axes are connected with flow function:

and. (19)

Let’s accept:

, , , (20)

where the first composed y characterizes a homogeneous stream of a liquid [

Substituting (20) in (17) and (18), we are limited only composed, not containing squares and products derivative from. It is connected by that far from a body derivative from quickly aspire to zero—A flow homogeneous. Actually, we are limited to linear approach of a flow of a body by a liquid. It is as a result found:

where it is designated—Angular speed of rotation of a liquid round a stream-line body [

Using taking into account (16) conditions

and

, we will find:

On

The factor in the first integral in (24) represents circulation of speed [

Using linear dependence of projections of force R on coordinate Y, taking into account (25) and (26) we will write down (23) and (24) in a kind:

Under size Y in this case we mean the size of a streamline body in a direction of axis Y. At from (28) we have the Zhukovsky’s formula for carrying power.

Formulas (27) and (28) allow to calculate basically force of resistance and carrying power in a viscous stream for bodies of any form.

Originally we will show that for an ideal liquid additional viscous composed in (27) and (28) are equal to zero owing to not only formal, but also at the expense of arising structure of a stream. For example, for a case uncirculatation flows of the circular cylinder, i.e. at, with use of function [

Let’s consider a circulating flow of the cylinder in radius b an ideal liquid. We will accept communication between speed of a stream and circulation in the form of [

Angular speed we will find from a condition , where. Circulation we will consider as a constant [

Integrals in (29) and (30) are equal among themselves from a condition of coordinate symmetry. These integrals are simple for calculating, using Green’s formula. For example, integral

where transition to polar coordinates is carried out. Hence, both viscous additives to components of force R are equal to zero.

The finding of expressions convenient for calculation viscous composed for components of force R at a flow a liquid of any profiles is generally exclusively challenge.

For example, for the cylinder the formula (27), using

Integration limits in (31) are defined by the following. We consider only area of monotonously growing dependence of projection V_{X} from a corner j where flow lines have circular character. With corner increase j from some minimum value which it is approximately considered equal to zero, to value, the longitudinal component of speed grows from some minimum to the maximum value, which on some small distance from the cylinder equally. Then V_{X} again falls almost to zero. A thickness of an interface it is considered by the small. In vicinities of points A and B,

The question on dependence of force of resistance to a flow a viscous liquid of the cylinder from its radius is of interest. From the analysis of the spent calculation follows that existence of circular lines of a flow, _{X} on radius. But in vicinities of points A and B sharp change of a direction of these lines is observed, there are points of an excess of lines of a flow. It is known that at sharp reduction of radius of the pipeline where the excess of lines of a flow

also is observed, there is a loss of static pressure in a flow viscous liquid which is spent for maintenance of a constancy of dynamic pressure [_{X} on radius, as proves to be true in [

Dependence of factor of resistance of the cylinder on Reynolds’s number in approach (31) looks like:

where, diameter of the cylinder.

On

Let’s estimate carrying power increase at a circulating flow of the cylinder, arising at the expense of viscosity. We will transform the formula (28) similarly transformation (31):

.(33)

Not circulating component at integration on the closed contour can to be considered, since it is symmetric concerning axis Х, with change of a direction in the course of integration.

Circulating component of district speed V_{c}, arising, for example, at cylinder rotation, we will connect since corresponding this speed circulation Г_{1} under the formula , as a result we will find:

Let’s notice that at increase in number of Reynolds carrying power to aspire to that at a circulating flow of the cylinder an ideal liquid. If the circulating component

of speed is defined only by cylinder rotation, for example, at the problem decision on occurrence of effect of Magnus [

We will analyse Newton’s law for force of viscosity (7) in more details. More the general view of this law looks like:

where dS—A vector of the area of contact of layers of a liquid.

Generally viscosity—Tensorous size (affinor) the second rank (i = 1, 2, 3 and j = 1, 2, 3) since it is the linear operator at transition from one vector to another. In coordinate representation the formula (35) can be copied in a kind. At calculation, for example, flow of liquid crystals it is necessary to consider tensorous character of viscosity [

Believing vector bases at the left and on the right in equality (35) identical, we find that

, i.e. a matrix of a tensor the diagonal. Hence, there are three various factors of viscosity on three coordinate axes.

If to consider a liquid newtonous, i.e. all components of a tensor of viscosity the identical. Therefore the formula (35) becomes simpler to (7).

The viscosity tensor becomes not diagonal at transition to liquid turbulent flow. In this case it looks like:

And the tensor represents molecular viscosity, and—Turbulent viscosity. We will notice that the tensor (36) is symmetric.

Using the equation of an impulse (4), and also applying Reynolds’s method of decomposition of speed upon average and pulsation components, we find Reynolds’s pressure:

where i, j, k—is unit vectors and angular brackets is mean sign [

For example in flat geometry, for one of a component of a tensor of pressure of Reynolds it is simple to receive the formula:

where and.

Let’s notice that unlike a hypothesis of Bussineska [

Use of the vector form of the Newton’s law for a viscous liquid allows to solve a problem of a flow around of bodies. Application of the found dependences at a circulating flow of the cylinder located across a stream is showed. In article the way of taking into consideration viscosity at correction N. E. Zhukovsky’s elevating force is showed. Factor of viscosity carries tensor character. The tensor of viscosity includes as molecular, so turbulent viscosity.