<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">MME</journal-id><journal-title-group><journal-title>Modern Mechanical Engineering</journal-title></journal-title-group><issn pub-type="epub">2164-0165</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/mme.2013.32011</article-id><article-id pub-id-type="publisher-id">MME-31639</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Engineering</subject></subj-group></article-categories><title-group><article-title>
 
 
  Vibrating Drivers for Transportation
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>en</surname><given-names>Zion Sandler</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Vladimir</surname><given-names>Chapsky</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref></contrib></contrib-group><aff id="aff1"><addr-line>Mechanical Engineering Department, Ben Gurion University, Beer Sheva, Israel</addr-line></aff><author-notes><corresp id="cor1">* E-mail:<email>sandler@.bgu.ac.il(EZS)</email>;</corresp></author-notes><pub-date pub-type="epub"><day>23</day><month>05</month><year>2013</year></pub-date><volume>03</volume><issue>02</issue><fpage>77</fpage><lpage>84</lpage><history><date date-type="received"><day>January</day>	<month>7,</month>	<year>2013</year></date><date date-type="rev-recd"><day>March</day>	<month>22,</month>	<year>2013</year>	</date><date date-type="accepted"><day>April</day>	<month>11,</month>	<year>2013</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
   The movement of objects by means of vibrations is a widely known idea, used for bodies transportation in automated industry based on vibrating bases, on which the transported elements are placed. We consider an inversed idea: vibration is applied to the movable element. Surface, on which this displacement must be realized, is unmovable. The asymmetry of the friction forces in the different phases of the vibration is the cause of motion in this case. A distinctive feature of the proposed device is a slope of the plane of vibration of the inertial mass, which leads to increasing of the asymmetry of friction. In this paper, we consider an example of application of the device to the lateral vehicle parking. The idea is numerically estimated and tested with a laboratory prototype. The movement along a straight line of the trolley with sloped vibrating mechanism under influence of asymmetric friction forces has been estimated and practically simulated with the laboratory prototype.  
    
 
</p></abstract><kwd-group><kwd>Inertial Drivers; Asymmetric Friction Force; Parking Mechanism</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>In this paper, the author addresses a powerful means for developing new technical concepts, finding novel solutions and solving certain technical problems. It involves a method of thinking that produces results over several different cognitive levels: from the simplest design level in up to the highest conceptual level used to formulate new technical ideas. The method has already been partially described in this author’s book [<xref ref-type="bibr" rid="scirp.31639-ref1">1</xref>].</p><p>The movement of objects by means of vibration is the widely known idea, used for transportation different parts and bodies in automated industry based on the use of vibrating bases, on which the transported elements are placed. This vibration is mainly realized by electromagnets and variable voltage. In this paper we consider the inversed idea: the vibration is applied to the moved element while the surface, on which this displacement must be realized, is unmovable.</p><p>The most known use of vibration of the object to move it himself is the vibro-hammers, used in the building and mining industries. These designs are mainly intended for movement in the vertical direction. Here, except the inertia forces, the force of weight acts in the vertical direction and leads to the asymmetry of the acting forces. Another situation occurs in devices intended for horizontal movement. In them the difference is caused by the asymmetry of the friction forces, acting on the base at different periods of the movement of the inertial mass, mounted on the base.</p><p>Example of such device is the mechanisms described in the patent USP No. 2639777 [<xref ref-type="bibr" rid="scirp.31639-ref2">2</xref>]. It intended for vehicles parking. In the method described in this patent the difference of friction between the wheels and the road in different phases of the rotation of the inertial mass (<xref ref-type="fig" rid="fig1">Figure 1</xref>(a)) is provided by an additional pressure, caused by the force of inertia of the rotating masses. This leads to the displacement of the car (<xref ref-type="fig" rid="fig1">Figure 1</xref>(b)). But calculations showed low efficiency of this design.</p><p>Search the efficiency of this method has led to a method of inertial driver, described in this article. In the new proposed method, the plane of rotation of the inertial mass is inclined to the line of moving direction. Calculations and simulations show that the proposed method is much more efficient than previously known, and can actually be used in practice. In addition, there are prospects for the use of this type of inertial drives to simply move the mobile objects.</p></sec><sec id="s2"><title>2. Description of the Proposed Mechanism</title><sec id="s2_1"><title>2.1. Construction</title><p>The inclined inertial device is shown in Figures 2(a) and (b). It consists of two identical engage gears (1), driven by motor (2). The gears are equipped with two symmet-</p><p>rically fixed masses (3). The gears are assembled in a bearing common base (6) by means of two axes 4 and ball bearings (5). The assembly is mounted on a platform (7) at an inclination angle<img src="3-1860094\b3c88498-1e18-4039-9183-0b7292194174.jpg" />. The platform slides on the surface (8) in the direction X. The transmission of rotation from the motor (2) to gears (1) is provided by two pulleys (9) and belt (10). Two force vectors <img src="3-1860094\f9dd774e-1cb7-4e5d-8964-b2abf8826aa8.jpg" /> and <img src="3-1860094\bfa6b89e-c123-45bf-ab1b-a242da19559a.jpg" /> are created as a result of masses (3) rotation, which influences the normal force creating the friction between surface (8) and the devices support and the driving force moving the body the device is fastened on.</p></sec><sec id="s2_2"><title>2.2. The Working Principle</title><p>We consider the operation of proposed vibration driver mechanism on example of car parking (<xref ref-type="fig" rid="fig3">Figure 3</xref>).</p><p>Laboratory model that demonstrates this movement is shown in the following video [<xref ref-type="bibr" rid="scirp.31639-ref3">3</xref>].</p><p>In following example the proposed mechanism consists from two rotating gear wheels mounted on rear axis of the car at some inclination angle as shown schematically in <xref ref-type="fig" rid="fig4">Figure 4</xref>.</p><p>The working principle is based on difference between friction forces, acting in two half-periods of wheels rotation. The rotation of the inertial masses, fixed on the disks, in the opposite direction leads to inertia forces, acting on the car, in the direction perpendicular to the line connecting the centers of disks (<img src="3-1860094\5fe72453-221e-4d5d-8a32-07d3091d2be8.jpg" />in <xref ref-type="fig" rid="fig4">Figure 4</xref>). The components of inertial forces, acting along the line, connecting the centers of disks, are equals and opposite in direction, so they cancel each other out. If the rotation of the discs is with a constant angular velocity<img src="3-1860094\c223182c-1d9c-4553-b481-8e6b17a0024a.jpg" />, then the function of inertia forces versus time is of a harmonic function with frequency f, as shown in <xref ref-type="fig" rid="fig4">Figure 4</xref>.</p><disp-formula id="scirp.31639-formula77350"><label>(1)</label><graphic position="anchor" xlink:href="3-1860094\2a5cfc20-76d2-4fd3-892f-e5d9917852ae.jpg"  xlink:type="simple"/></disp-formula><p>where <img src="3-1860094\3c4b91cb-d460-4280-87ae-892c1c8d9c27.jpg" /> is magnitude of the inertial force, created by two rotating masses:</p><disp-formula id="scirp.31639-formula77351"><label>(2)</label><graphic position="anchor" xlink:href="3-1860094\8602b313-1e60-4a60-a852-4f5258ee641d.jpg"  xlink:type="simple"/></disp-formula><p>m, mass of one inertial body; f, the frequency of rotation of the discs in Hertz units (or rotations per second); r, the distance between the centers of mass of the inertial bodies and the centers of the rotating disks.</p><p>The vertical component of force <img src="3-1860094\87d029de-49e8-4375-98fb-9cc75f4d09e2.jpg" /> changes the pressure on the car axle, and consequently changes the force of friction in the different phases of the rotation of the discs. The horizontal component of harmonic force <img src="3-1860094\24f53ca1-ea0e-41c5-8d4e-13f4de74c575.jpg" /> together with the different friction forces in the different phases of the discs rotation, leads to the movement of the car.</p></sec><sec id="s2_3"><title>2.3. Calculation of the Angle of Car Displacement</title><p>In common case the movement of the car consists of three parts in each period of disc rotation: 1) sliding, the motion with friction, when the horizontal component of force is greater than the friction force and the vertical force component is less than the weight of the moving object; 2) hovering above the road, when the vertical component of force is greater than the weight of the moving object (which leads to its flying); 3) deceleration, motion in the presence of the friction force after touching the road.</p><p>Let’s assume some restrictions on the physical model for considered here numerical examples (the estimated quantities are approximate):</p><p>• The friction index does not depend on the motion speed;</p><p>• Vehicle mass is much greater than the inertial mass of rotating bodies;</p><p>• The magnitude of the loading force, acting on bearing of rotating rings does not exceed 10,000 Newton;</p><p>• The rotation speed of the rings does not exceed 1200 rpm.</p><p>As shown in <xref ref-type="fig" rid="fig3">Figure 3</xref>, the car’s back part is mowed inside the free place due to the vibrating driver. The same way, after the device is rotated for 180 degrees, it can be used for bringing the car out of the parking place by moving it reverse.</p><p>For the numerical example of the calculation of turning the car, we will take the geometric and physical pa-</p><p>rameters of the vehicle and the inertial unit close to the real. Here are the following data:</p><p>• mass of the car is<img src="3-1860094\83461a9e-81b9-4777-8ccf-e45e2626b39e.jpg" />;</p><p>• distance between rear and front axles is <img src="3-1860094\9b1fde3d-da21-4b36-beab-49b3b7d18bd4.jpg" /> meters;</p><p>• moment of inertia of the car relative to center of the front suspension<img src="3-1860094\5c758d8c-2e36-41a5-805e-7fd089a84c0d.jpg" />;</p><p>• pressure on the rear axle due to gravitation weight of the car is <img src="3-1860094\d285f324-c7f3-4b3c-85fe-0bb804c8b8e9.jpg" /> (Newton);</p><p>• radius of rotation disc is <img src="3-1860094\225e6975-a293-4d8c-923f-3cb063b8258e.jpg" /> meter;</p><p>• mass of the inertial body<img src="3-1860094\d7fd6fd1-f56d-4caa-9b57-5e4e6e0e1336.jpg" />;</p><p>• rotation speed is 1200 rpm<img src="3-1860094\8bbfc6ea-64f4-4236-bd65-535e8a9e9b0b.jpg" />;</p><p>• inclination angles are<img src="3-1860094\d2cdbce8-905a-4003-a31a-b6f0e2c5c321.jpg" />;</p><p>• index of friction is<img src="3-1860094\b518c6ef-45c6-4a97-ac78-44dac947e963.jpg" />;</p><p>• the permissible load on the bearings of the rotation discs assumed as<img src="3-1860094\5c074b38-3b0c-44ae-8c9c-fe3e9d4ce6f2.jpg" />.</p><p>The purpose of the calculation is to estimate the angular displacement of the car relative the center of front suspension for all given α during one cycle, one second, and ten seconds.</p><p>For definiteness, the initial conditions assume as:</p><p>• The discs are already spinning with angular velocity <img src="3-1860094\44c7b494-54d5-484a-a95c-20d201998880.jpg" /></p><p>• At the time <img src="3-1860094\7ef33d80-51cf-42b0-9b7c-d883bb2a2a04.jpg" /> the position of the inertial body<img src="3-1860094\40181060-4626-4fc0-ae63-837c706b000e.jpg" />.</p><p>• The car is not moving.</p><p>1) Sliding. For calculation of the first part of displacement, when car moves with friction, the time, when car starts to move and time when car starts to hover should be defined. Also, we need to define the equation of motion in horizontal direction.</p><p>Let <img src="3-1860094\64804c71-8ae1-4993-8805-a346b9cd6c13.jpg" /> be the time function of the vertical component of the inertial force<img src="3-1860094\fb8c62a0-3320-4792-bdd4-f7de935b3187.jpg" />:</p><disp-formula id="scirp.31639-formula77352"><label>(3)</label><graphic position="anchor" xlink:href="3-1860094\8d3e2880-da6b-4c7a-8717-98e015829ae0.jpg"  xlink:type="simple"/></disp-formula><p>where <img src="3-1860094\5089c669-2036-480f-a47e-287683577891.jpg" /> is the period of disc rotation. F<sub>0</sub>, magnitude of the inertial force (Equation 3);</p><p><img src="3-1860094\53292df2-8394-4fc2-9543-45dd2d80d8d2.jpg" />. (The load on the bearings F<sub>b</sub> = F<sub>0</sub>/2 = 4737.41 N is less than permissible.</p><p>At the time, when the vertical component of inertial force equals or greater than the pressure force on the rear car axle, it breaks away from the road.</p><disp-formula id="scirp.31639-formula77353"><label>(4)</label><graphic position="anchor" xlink:href="3-1860094\d46df222-98d8-4835-9567-255f55fa9f91.jpg"  xlink:type="simple"/></disp-formula><p>The break time t<sub>break</sub> was calculated from Equations (3) and (4). The graphs of function <img src="3-1860094\2dc973eb-9555-4f53-b083-5cd13a8602d0.jpg" /> for different inclination angles and the break time t<sub>break</sub> were calculated using the Wolfram’s Mathematica 8 software, shown in <xref ref-type="fig" rid="fig5">Figure 5</xref>. As shown in <xref ref-type="fig" rid="fig5">Figure 5</xref>, for <img src="3-1860094\6463c227-2d51-428e-bc14-2f759afa0378.jpg" /> t<sub>break</sub> = 0.0067 seconds. As can be seen from <xref ref-type="fig" rid="fig5">Figure 5</xref>, in the current example only for α<sub>1</sub> the hovering takes place. Thus, further we consider the current example separately for<img src="3-1860094\a8e02e4e-9cdc-447a-a1bf-913377bfc913.jpg" />, and then for <img src="3-1860094\d152393e-a047-41a7-b61b-866547008030.jpg" /> and<img src="3-1860094\b06e85b9-7ba6-4782-b8f1-06854155cd95.jpg" />.</p><p>Determination of time t<sub>start</sub> when back part of the car starts to move transversal with friction, sliding.</p><p>The condition for horizontal moving is the horizontal component of the inertial force becomes greater than friction force. The following equation expresses this condition:</p><disp-formula id="scirp.31639-formula77354"><label>(5)</label><graphic position="anchor" xlink:href="3-1860094\4f54d31b-191c-47a1-9821-445b42326876.jpg"  xlink:type="simple"/></disp-formula><p>where<img src="3-1860094\35fd060a-cdce-4b5a-a263-a0b13a534b15.jpg" />, the magnitude of horizontal component of inertial force.</p><p>From Equation (5) implies that:</p><p><img src="3-1860094\7b839433-d94e-4505-b08d-4f016be23d8e.jpg" />and</p><disp-formula id="scirp.31639-formula77355"><label>(6)</label><graphic position="anchor" xlink:href="3-1860094\84899467-6c06-4797-9360-86620d0f3f9c.jpg"  xlink:type="simple"/></disp-formula><p>Equation (6) is true for all <img src="3-1860094\834153b0-8933-4207-a841-3584508b30c9.jpg" /> and<img src="3-1860094\5dc73c80-a638-45bb-a8d2-e6048c64df7e.jpg" />. Calculation gives the following:</p><p><img src="3-1860094\4da00908-64f2-4a5a-aef5-4e3ed5892ee6.jpg" /></p><p>Let <img src="3-1860094\e0365ff2-8384-403a-be7b-c60e2cbaa9ef.jpg" /> be the horizontal component of the inertial force<img src="3-1860094\0516823a-2663-42cf-a5af-982f958ecaab.jpg" />, <img src="3-1860094\f3e16152-686d-4ff3-9e58-055910531a81.jpg" />be the locomotive power, defined as difference of horizontal component of the inertial force and force of friction<img src="3-1860094\634cf74a-ccc2-4fdd-b4ba-b489e781bef9.jpg" />:</p><p>where:</p><disp-formula id="scirp.31639-formula77356"><label>(7)</label><graphic position="anchor" xlink:href="3-1860094\a0eb13d4-73b7-4396-86e8-f6b5e1de3a8e.jpg"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.31639-formula77357"><label>(8)</label><graphic position="anchor" xlink:href="3-1860094\57db35fe-4f99-4887-90b4-99e4c2eee4df.jpg"  xlink:type="simple"/></disp-formula><p>The moments of the corresponding forces relative to center of the front axle are:</p><p><img src="3-1860094\46e28326-0e35-46fa-a522-8072af1c03df.jpg" />, the moment of vertical component of inertial force,</p><p><img src="3-1860094\7e2d4f3b-c5bb-4f4c-8d3d-992a8ef00ee0.jpg" />, the moment of horizontal component of inertial force,</p><p><img src="3-1860094\5d3fc414-c775-4268-ad42-cee2af60606c.jpg" />, the moment of friction force,</p><p><img src="3-1860094\bbe5477b-f9ad-4fc9-a868-b339ac031ad5.jpg" />, the moment of locomotive powerwhere L, the distance between rear and front axles.</p><p>The angular acceleration of the car relative to center of front axle, caused by moment of locomotive force during first part of motion (sliding):</p><disp-formula id="scirp.31639-formula77358"><label>(9)</label><graphic position="anchor" xlink:href="3-1860094\a0c7020a-c360-4085-bf4b-22c2aa9ab9d8.jpg"  xlink:type="simple"/></disp-formula><p>Graphs of function <img src="3-1860094\f9db45af-f833-4e9a-a6c8-85b6ea8ff976.jpg" /> versus time for different inclination angles of discs plane are shown in <xref ref-type="fig" rid="fig6">Figure 6</xref>.</p><p>The angular velocity <img src="3-1860094\be035ed7-32f2-4ab3-9b1f-6bebece1af99.jpg" /> of the car relative to center of front axle as function of time is calculated&#160;by integration of the function <img src="3-1860094\f2c98224-0568-4a99-badf-4f95bd6dec3d.jpg" /> over time and is represented in <xref ref-type="fig" rid="fig7">Figure 7</xref>.</p><p>The area under velocity plot from t = t<sub>start1</sub> = 0.00269 sec to<img src="3-1860094\5e307f51-51db-4885-a31b-fb07b1ce3423.jpg" />. numerically equals to angular displacement <img src="3-1860094\35882a67-f4b8-4c72-9563-d67b87f72ae9.jpg" /> of the car during one cycle. The result of calculation gives <img src="3-1860094\4f491098-824d-4fc5-bcaf-fbf19a6626a5.jpg" /> and the angular velocity at the time of breaking<img src="3-1860094\ff232acf-114f-4672-8f46-2bbffd8f97f1.jpg" />:</p><disp-formula id="scirp.31639-formula77359"><label>(10)</label><graphic position="anchor" xlink:href="3-1860094\409f1a09-e69e-47b2-a1fa-5b66d1e7aa2c.jpg"  xlink:type="simple"/></disp-formula><p>2) Hovering. The second part of the motion is the movement of a car under the action of gravitational and inertial forces, without touching the road with an initial velocity.</p><p>The vertical component of the initial angular velocity equals to zero. Equation of the second part of motion (hovering) in vertical direction looks as follows:</p><disp-formula id="scirp.31639-formula77360"><label>(11)</label><graphic position="anchor" xlink:href="3-1860094\91758ada-26d8-43c4-9e3c-4b7afa2cc384.jpg"  xlink:type="simple"/></disp-formula><p>where<img src="3-1860094\e5306b4d-80af-40c9-b53d-b70f83101c53.jpg" />, vertical component of angular acceleration during hovering;<img src="3-1860094\ef7669c2-cf4a-4055-aae6-98fa088f217b.jpg" />, angular displacement in vertical direction during hovering as function of time. The numerical representation of Equation (11) and graph of function <img src="3-1860094\f062a35e-ea3c-45f4-9cb4-e295a040a1bc.jpg" /> for inclination angle <img src="3-1860094\0510354a-a9f8-4a6a-8312-acef3df2db0f.jpg" /> is shown in Equation (12) and <xref ref-type="fig" rid="fig8">Figure 8</xref>.</p><disp-formula id="scirp.31639-formula77361"><label>(12)</label><graphic position="anchor" xlink:href="3-1860094\8fc18c68-3c34-4bad-ba85-f290694eff9a.jpg"  xlink:type="simple"/></disp-formula><p>Obviously only positive values of the vertical displacement make sense. <xref ref-type="fig" rid="fig8">Figure 8</xref> shows that contact with the road exists in the second half of the period T of disks rotation. It means that after the time of <img src="3-1860094\80b7cc81-3360-4cb4-9b58-a3490877b473.jpg" /> inertial force acting opposite the movement of the car and slows it.</p><p>The horizontal component of the initial angular velocity equals to the angular velocity&#160;at the time of breaking<img src="3-1860094\21a6ba3c-7387-44e4-8a67-874c8e0f577f.jpg" />. Equations of the second part of motion (hovering) in horizontal direction looks as follows:</p><disp-formula id="scirp.31639-formula77362"><label>(13)</label><graphic position="anchor" xlink:href="3-1860094\28d87d0c-d2e4-4e94-8824-f64d0727af44.jpg"  xlink:type="simple"/></disp-formula><p>Or in the numeric representation:</p><disp-formula id="scirp.31639-formula77363"><label>(14)</label><graphic position="anchor" xlink:href="3-1860094\85e1be9d-9aeb-4a0a-9911-347c4f82fca3.jpg"  xlink:type="simple"/></disp-formula><p>where<img src="3-1860094\badf1263-441b-4128-a5cc-dda19908f747.jpg" />, horizontal component of angular acceleration during hovering, <img src="3-1860094\b87424b8-753c-480a-8ed6-ef5d05c36faa.jpg" />, horizontal component of angular velocity during hovering, <img src="3-1860094\208a328d-a57f-457e-8bd0-4a0990277fd4.jpg" />, angular displacement in horizontal direction during hovering.</p><p><xref ref-type="fig" rid="fig9">Figure 9</xref> shows the horizontal component of angular velocity <img src="3-1860094\43e7d5a5-7893-4de8-907b-28a0b8ed53b7.jpg" /> of the car relative to center of front axle as function of time. The area under velocity plot from</p><p><img src="3-1860094\59cb83d6-a158-455e-a340-3916595e6b38.jpg" />to<img src="3-1860094\521c2b49-0574-43b8-868a-ed97385d87ff.jpg" />. Numerically equals to the angular displacement <img src="3-1860094\c6e85bb1-2b0b-48e9-9c16-a9f7a1033831.jpg" /> of the car during one hover. The result of calculation gives:</p><p><img src="3-1860094\5201ed42-43bb-48ed-aa78-593189719cc9.jpg" /></p><p>The horizontal component of angular velocity at the time of contact with road is:</p><disp-formula id="scirp.31639-formula77364"><label>(15)</label><graphic position="anchor" xlink:href="3-1860094\c0e22b07-1816-4e44-b5dd-84524604c41a.jpg"  xlink:type="simple"/></disp-formula><p>3) Deceleration. We assume that the collision with the road was of the nature of the inelastic and there was no rebound. Thus, the third part of movement is the horizontal sliding with presence of friction force with initial angular velocity <img src="3-1860094\efa0b718-3999-44b1-87f0-df1026367820.jpg" /> under action of the moment of horizontal component of inertial force<img src="3-1860094\6cb99d2e-fa12-4b12-8339-91c335caa986.jpg" />. The</p><p>equations of motion for third part are the same, as for the first part, but with other initial conditions. There are as follows:</p><disp-formula id="scirp.31639-formula77365"><label>(16)</label><graphic position="anchor" xlink:href="3-1860094\a8728fbe-9e79-488f-a29c-fc42c0d331b1.jpg"  xlink:type="simple"/></disp-formula><p>where<img src="3-1860094\48878eb2-92a0-411f-8073-19a8737d389b.jpg" />, are the angular acceleration, velocity, and displacement during the third part of movement (deceleration). Numerical representation of the angular velocity <img src="3-1860094\a61de538-da5a-4b6e-b83e-1f1d5c8916ac.jpg" /> is follows:</p><disp-formula id="scirp.31639-formula77366"><label>(17)</label><graphic position="anchor" xlink:href="3-1860094\a49f2e27-8e16-448a-8800-8a54dafc5888.jpg"  xlink:type="simple"/></disp-formula><p>Graph of this function is shown in <xref ref-type="fig" rid="fig1">Figure 1</xref>0. The area under the graph of <img src="3-1860094\d64fecfa-a65c-491b-8792-72fdd80d75f8.jpg" /> numerically equals to angular displacement of the car during part of deceleration:</p><disp-formula id="scirp.31639-formula77367"><label>(18)</label><graphic position="anchor" xlink:href="3-1860094\7246175f-afd7-406d-a8ea-23cfaf34b290.jpg"  xlink:type="simple"/></disp-formula><p>Finally, the absence of a reverse movement should be checked. For this purpose, the model must satisfy the following condition: the value of horizontal force less than the value of friction force, <img src="3-1860094\765a658a-dae8-4b7c-b50d-b942a29f5947.jpg" />, for<img src="3-1860094\7f0080df-58c4-4ec2-8a77-9f80cede7836.jpg" />, or, according to Equation (5):</p><disp-formula id="scirp.31639-formula77368"><label>(19)</label><graphic position="anchor" xlink:href="3-1860094\c909be02-d794-4a57-9e7d-d78d1794fae6.jpg"  xlink:type="simple"/></disp-formula><p>Graphs of left and right sides of Equation (19) are shown in <xref ref-type="fig" rid="fig1">Figure 1</xref>1.</p><p>As clear from <xref ref-type="fig" rid="fig1">Figure 1</xref>1, the condition of Equation (19) is satisfied. Reverse movement during deceleration is absent.</p><p>Full rotation in one cycle is the sum of three parts of angular displacement:</p><disp-formula id="scirp.31639-formula77369"><label>(20)</label><graphic position="anchor" xlink:href="3-1860094\7976347f-31a0-4d6a-8acc-9d7bbd20a5ea.jpg"  xlink:type="simple"/></disp-formula><p>The full rotation in one second is:</p><disp-formula id="scirp.31639-formula77370"><label>(21)</label><graphic position="anchor" xlink:href="3-1860094\53a1fb41-0d17-4dee-ba47-cb4f14122d6d.jpg"  xlink:type="simple"/></disp-formula><p>The full rotation in fifteen seconds is:</p><p><img src="3-1860094\e38b311b-991c-4590-beee-1e4a2da85b89.jpg" />, or in degrees:</p><disp-formula id="scirp.31639-formula77371"><label>(22)</label><graphic position="anchor" xlink:href="3-1860094\ea01c1af-beee-4dc9-8a8e-3671844f99bf.jpg"  xlink:type="simple"/></disp-formula><p>The calculations of the angular displacements for inclination angles <img src="3-1860094\432787fc-5bf7-4b72-9260-d02e5379cf36.jpg" /> and <img src="3-1860094\fdf858a4-75c0-4ac7-b69b-fdcc5fc31aa6.jpg" /> were performed in the same way as for Parts 1 and 3 of previous calculation, but only for continuous time range from <img src="3-1860094\357c1643-5ad2-4fa2-be2e-c75d2746b05f.jpg" /> to<img src="3-1860094\65b996e2-b046-43a2-a323-dcd230cedd01.jpg" />. The corresponding start times, which have been calculated previously by Equation (6), are:<img src="3-1860094\06140593-d4bc-4e28-b56e-fe71075a493d.jpg" />, <img src="3-1860094\017add53-6bbb-4119-9470-697e81050fbd.jpg" /></p><p>By integration of function of angular acceleration of the car Equation (9) the function of angular velocity for <img src="3-1860094\ea557251-7648-4b95-9c63-c3abd33dcd1a.jpg" /> and <img src="3-1860094\6fa5700a-b97d-4c4c-bbf5-2cc92f65f6ca.jpg" /> should be obtained. The results of calculations are follows:</p><disp-formula id="scirp.31639-formula77372"><label>(23)</label><graphic position="anchor" xlink:href="3-1860094\6d3eb7dc-828a-481e-9153-f5489e776789.jpg"  xlink:type="simple"/></disp-formula><p>The graphs of listed functions are shown in <xref ref-type="fig" rid="fig1">Figure 1</xref>2.</p><p>The angular displacements numerically equal to arias under graphs<img src="3-1860094\ab0b95b3-a49f-4a0e-866c-7b98b1c2d10c.jpg" />, and should be calculated by integration in time range from t<sub>start</sub> to t<sub>stop</sub>.</p><disp-formula id="scirp.31639-formula77373"><label>(24)</label><graphic position="anchor" xlink:href="3-1860094\142fd3cb-251d-4a4e-b1ea-576c887db081.jpg"  xlink:type="simple"/></disp-formula><p>The results of calculations showed that the proposed model of the inertial drive with inclination angle of discs plane 30˚ - 45˚ is acceptable for use for car parking.</p></sec><sec id="s2_4"><title>2.4. Some Possible Improvements of the Proposed Devise</title><p>The above example shows the opportunity to apply the proposed inertial drive for parking a small car. Some additional design solutions can enhance the capabilities of the devices, described above.</p><p>A design in which exists the possibility of rotation of the device around the vertical axis by 180˚, will allow the car both, to enter inside a parking place and out of it.</p><p>The ability to change the angle (α) of the plane of disks rotating will change the parameters of the lateral movement of the car according to the coefficient of friction between the tires and the road surface.</p><p>For heavy goods vehicles the inertial unit with four or more rotating inertia bodies can be used. The schematic drawings of such units are shown in <xref ref-type="fig" rid="fig1">Figure 1</xref>3 or in Figures 6 and 9 in the patent 4050527 “Vibrodriving apparatus” [<xref ref-type="bibr" rid="scirp.31639-ref4">4</xref>].</p></sec></sec><sec id="s3"><title>3. Brief Discussion about Linear Displacement of the Vehicle</title><p>As it is obvious from the description of the operating principle of the proposed inertial drive, it can also be used for different other vehicles. A necessary condition is the creation as much as possible difference in the friction forces between the vehicle and the road, acting in the various phases of the rotation of the inertial drive. Rectilinear movement of the vehicle with the inertial drive on the normal wheels in the presence of rolling friction (which is much less than sliding friction) is not effective. To use the above described model with the inertial drive for the rectilinear motion of the vehicle, its design shall ensure the presence of the forces of sliding friction.</p>Experimental Model Examination<p>An example of this design is the model of a trolley with inertial drive, which is shown in the following video clip [<xref ref-type="bibr" rid="scirp.31639-ref5">5</xref>].</p><p>In this trolley, the back axle was stalled and was loaded with additional weight, for increasing the force of sliding friction. Also, the line of action of the inertial force passes through the rear axle of the trolley that increases the effect of the vertical component of the force of inertia on value of pressure on the rear axle (<xref ref-type="fig" rid="fig1">Figure 1</xref>4).</p><p>The front swivel wheels provide a stable direction of the trolley motion because in the direction of rectilinear motion acts the force of rolling friction, but in the transverse direction acts the force of sliding friction between rubber tires and the floor, which is much larger than rolling friction.</p><p>Calculations using the algorithm described above for car parking (for the sliding motion) gave results similar to those observed in the video clip. The trolley has an average speed of 11.3 cm/second, slightly more than in the video clip (~10.8 cm. per second.). Measuring the distance traveled by the trolley is represented by the graph in <xref ref-type="fig" rid="fig1">Figure 1</xref>5.</p><p>Approximation section <img src="3-1860094\f9d019ef-56b8-4629-82e1-353f0c143d3b.jpg" /> (interrupted line) obviously can be described by a simple formula of the following form:</p><disp-formula id="scirp.31639-formula77374"><label>(25)</label><graphic position="anchor" xlink:href="3-1860094\eb465798-2751-416f-bde5-0686bf6096a9.jpg"  xlink:type="simple"/></disp-formula><p>(Time is taken from about ~1.5 seconds without movement, which is about 15 cm, while further it moves with the speed&#160; about 10.8 cm/sec for about t = 10 sec).</p></sec><sec id="s4"><title>4. Conclusion, Some Possible Designs</title><p>We consider this paper as an example mainly describing the first steps in the design process. The step, where the main idea of the solution, answering the formulated problem the design task requires, must be found, at least one answer, or a number of them. At this stage, the main accent is put on the lay-out or model of the solution. It can be found in already existing designs, or inversed existing idea, or somehow changed, improved existing idea. A consideration of this approach and description of it are given, for instance in some author’s books [1,2] and others.</p>Technical Proposals for Transportation<p>We are speaking about mechanical dynamic vibrations as a reason to create certain displacement of a car, improving the parking possibilities. This dynamic mechanical effect, as is here reminded, is widely used in industry.</p><p>We inversed this idea by deciding to vibrate the back of the car (not the surface the car is standing on) in such a way moving it to the needed place. Another change, which we propose in our design, is not to use electromagnets as a vibration source, which is often used in industrial machines, usually automatic, for transportation parts. We propose pure mechanical vibrator design (see <xref ref-type="fig" rid="fig2">Figure 2</xref>). The simplest consideration brings us to think about counterbalance fly-wheels used in rail-way engines or locomotives. The same solution is sometimes used in crank-shaft mechanisms. The cranks and wheels usually rotate in vertical plane, which makes the inertial forces appearing here not appropriated to create driving the mechanism to certain direction. To reach the effect of certain movement direction, the orientation of the vibrating device in space must be changed and the direction of the driving force must be strictly defined. This is achieved in the given here solution (<xref ref-type="fig" rid="fig2">Figure 2</xref>).</p><p>An idea to drive by the device, considered in <xref ref-type="fig" rid="fig2">Figure 2</xref>, placing it on elastic bases, say, on 4 rubber balls. This may be a specific device, on which the vibrator can be directed in the needed way. Such a device may be a simple toy or a special used carriage.</p></sec><sec id="s5"><title>REFERENCES</title></sec></body><back><ref-list><title>References</title><ref id="scirp.31639-ref1"><label>1</label><mixed-citation publication-type="other" xlink:type="simple">B. Sandler, “Creative Machine Design, Design Innovations and the Right Solutions,” Paragon House Publishers, New York 1985.</mixed-citation></ref><ref id="scirp.31639-ref2"><label>2</label><mixed-citation publication-type="other" xlink:type="simple">M. L. Dull, “Method and Device for Imparting Lateral Movement to an Automobile,” US Patent No: 2639777, 1953.</mixed-citation></ref><ref id="scirp.31639-ref3"><label>3</label><mixed-citation publication-type="other" xlink:type="simple">Video Clip in YouTube. 
http://www.youtube.com/watch?v=B3p4zH4992c&amp;feature=relmfu</mixed-citation></ref><ref id="scirp.31639-ref4"><label>4</label><mixed-citation publication-type="other" xlink:type="simple">J. L. Lebelle, “Vibrodriver Apparatus,” US Patent: 4050527, 1977.</mixed-citation></ref><ref id="scirp.31639-ref5"><label>5</label><mixed-citation publication-type="other" xlink:type="simple">Video Clip in YouTube. 
http://youtu.be/Owu2ANuwPLw</mixed-citation></ref></ref-list></back></article>