On the Geometry of Curves in Minkowski 3-Space and Its Foldings ()
1. Introduction and Definitions
As is well known, the theory of deformation retract is always one of the interesting topics in Euclidian and Non-Euclidian space and it has been investigated from the various viewpoints by many branches of topology and differential geometry El-Ahmady [1-3].
Minkowski space is originally from the relativity in physics. In fact, a time like curve corresponds to the path of an observer moving at less than the speed of light, a light like curve corresponds to moving at the speed of light and a space like curve moving faster than light El-Ahmady [4,5].
The Minkowski 3-space
is the Euclidean 3-space
provided with the standard flat metric given by
, where (x1, x2, x3) is a rectangular coordinate system of
. Since g is an indefinite metric, recall that a vector
can have one of three Lorentzian causal characters, it can be space like if
0 or
, time like if
and light like if
and
. Similarly, an arbitrary curve
in
can locally be space like, time like or light like, if all of its velocity vectors
are respectively, space like, time like or light like respectively. A curve in Lorentzian space Ln is a smooth map
where I is the open interval in the real line
. The interval has a coordinate system consisting of the identity map u of I. The velocity of
at
is
.
A curve
is said to be regular if
does not vanish for all
.
is space like if its velocity vectors
are space like for all
, similarly for timelike and null. If
is a null curve, we can reparametrize it such that
and
El-Ahmady [5].
Most folding problems are attractive from a pure mathematical standpoint, for the beauty of the problems themselves. The folding problems have close connections to important industrial applications. Linkage folding has applications in robotics and hydraulic tube bending. Paper folding has application in sheet-metal bending, packaging, and air-bag folding El-Ahmady [6]. Following the great Soviet geometer El-Ahmady [5], also, used folding to solve difficult problems related to shell structures in civil engineering and aero space design, namely buckling instability El-Ahmady [7]. Isometric folding between two Riemannian manifold may be characterized as maps that send piecewise geodesic segments to a piecewise geodesic segments of the same length [8,9]. For a topological folding the maps do not preserves lengths El-Ahmady [8-10] i.e. A map
, where M and N are
-Riemannian manifolds of dimension m, n respectively is said to be an isometric folding of M into N, iff for any piecewise geodesic path
, the induced path
is a piecewise geodesic and of the same length as
. If
does not preserve length, then
is a topological folding El-Ahmady [10-12].
A subset A of a topological space X is called a retract of X if there exists a continuous map
such that
,
, where A is closed and X is open. El-Ahmady [7-12] and Gregory [13]. This can be restated as follows. If
is the inclusion map, then
is a map such that
Miles [14] and Martin [15]. If, in addition
, we call r a deformation retract and A a deformation retract of X Jeffrey [16] and John [17].
2. Main Result
Let
be a curve in the space-time
, parameterized by arc length function
Lopez [18] and Formiga [19]. Then for the unit speed curve
with non-null frame vectors the following Frenet equations are given in
(1)
We write following subcases.
1) If
is space-like curve in
, then T is a space-like vector. Thus, we distinguish according to N.
Case 1: If N is space-like vector, then B is time-like vector, then
read
,
. And T, N and B are mutually orthogonal vectors satisfying equations,
,
.
Case 2:
is time-like vector, then
read
.
And T, N and B are mutually orthogonal vectors satisfying equations
.
2) If
is time-like curve in
, then T is timelike vector. Then
read
. And T, N and B are mutually orthogonal vectors satisfying equations,
.
3) If
is light-like curve in
then the following Frenet equations are given in
(2)
Also, if
be a curve in the space-time
, parameterized by arc length function
. Then for the unit speed curve
with non-null frame vectors the following Frenet equations are given in
(3)
Due to character of
, we write following subcases.
1) If
is space-like curve in
, then T is a space-like vector. Thus, we distinguish according to N.
Case 1: If N is space-like vector, then
can have two causal characters.
Case 1.1:
is space-like vector, then
read,
. And
and
are mutually orthogonal vectors satisfying equations

Case 1.2:
is time-like vector, then
read
. And
and
are mutually orthogonal vectors satisfying equations

Case 2: N is time-like vector, then
read
. And
and
are mutually orthogonal vectors satisfying equations
.
2) If
is time-like curve in
, then T is timelike vector. Then
read
,
. And
and
are mutually orthogonal vectors satisfying equations

Hence, we can formulate the following theorems.
Theorem 1. Under the retraction, a spacelike curve and a timelike curve
in the space-time
parameterized by arc length function s, where
and with non-vanishing curvature, lies in ahyperplane if and only if the torsion vanishes identically.
Proof. Suppose the curve
lies in a hyperplane. Let us assume that we can bring
to lie in the
-hyperplane. Then the parametric equations of
are of the form
. Let
denote the vectors of the canonical coordinate basis. Thus, in these coordinates,

and
.
From (1) we have
. Since
then
has no components in the
-direction, i.e.
.
Thus,
hence from the equation
we conclude that
, where
However,
cannot be zero. Otherwise the set of vectors
would not be linearly independent. Then
must vanish.
Suppose that
. Since
, then B is a constant vector. Let us conveniently choose our coordinate system in such a way that
. Now, since T is orthogonal to B we must have
, which means that
lies in the hyperplane
.
Corollary 1. Under the folding,
, a spacelike curve and a timelike curve
in the space-time
parametrized by arc length function s, with non-vanishing curvature, lies in a hyperplane if and only if the torsion vanishes identically.
Theorem 2. Under the retraction, if the curve is a lightlike curve
in the space-time
parameterized by arc length function s, where
then the curve is not lies in a hyperplane.
Proof. Suppose the curve
lies in a hyperplane. Let us assume that we can bring
to lie in the
-hyperplane. Then the parametric equations of
are of the form
Let
denote the vectors of the canonical coordinate basis. Thus, in these coordinates,

and
.
From (2) we have
. Then
has no components in the
-direction, i.e.
Thus,
, hence from the equation
, we conclude
, where
. But
cannot be zero because the set of vectors
would not be linearly independent, then the curve is not lies in a hyperplane.
Corollary 2. Under the folding,
if the curve is a lightlike curve
in the spacetime
parameterized by arc length function s, then the curve is not lies in a hyperplane.
Theorem 3. Under the retraction, a spacelike curve and a timelike curve
in the space-time
parameterized by arc length function s, where
and with non-vanishing curvature, lies in ahyperplane if and only if the second torsion vanishes identically.
Proof. Let us start with the necessary condition. Suppose the curve
lies in a hyperplane. Let us assume that we can bring
to lie in the
-hyperplane. Then the parametric equations of
are of the form
. Let
denote the vectors of the canonical coordinate basis. Thus, in these coordinates,

and
.
From (3) we have
. Since
then N has no components in the
-direction, i.e.

Thus,
, hence from the equation
and we conclude that
, where
. If
, then
also must vanish, for in this case
is chosen to be constant. If
, then
, hence
Also,
and the third Serret-Frenet equation
we are led to conclude that
, where
.
However,
cannot be zero. Otherwise the set of vectors
would not be linearly independent. Then
must vanish.
Suppose that
. Since
, then 
is a constant vector. Let us conveniently choose our coordinate system in such a way that
. Now, since
is orthogonal to
we must have
, which means that
lies in the hyperplane
.
Corollary 3. Under the contraction, a spacelike curve and a timelike curve
in the space-time
parameterized by arc length function s, where
and with non-vanishing curvature, is lies in a hyperplane if the first and second torsions vanishes identically.
Corollary 4. Under the folding, a spacelike curve and a timelike curve
in the space-time
parameterized by arc length function s, with non-vanishing curvature, lies in a hyperplane if and only if the second torsion vanishes identically.
Corollary 5. Under the folding,
, a spacelike curve and a timelike curve
in the space-time
parameterized by arclength function s, with non-vanishing curvature, is lies in a hyperplane if the first and second torsions vanishes identically.
Theorem 4. Given differentiable functions
and
such that s is the arc length, there exists a regular parameterized spacelike curve under the folding with the spacelike vector N,
, in the space-time
. Also,
is the curvature and
is the torsion of
. Moreover, any other spacelike curve
with the spacelike vector
satisfying the same conditions and
at
then
and the Frenet trihedrons of
and
is identically.
Proof. Now, assume that two curves
and
satisfy the conditions
and
,
. Let T0, N0, B0 and
,
,
be the Frenet trihedrons of
and
at
, respectively. Since
then
,
and
, where
,
,
and
,
,
are the Frenet trihedrons of
and
, respectively. We now observe, by using the Frenet equations at (1), that

for all
. Thus, the above expression is constant, and, since it is zero for
, it is identically zero. It follows that
,
,
for all
.
Since
, we obtain
.
Thus
, where a is a constant vector. Since
, we have
; hence, 
for all
.
Corollary 6. Given differentiable functions
and
,
such that s is the arc length, there exists a regular parameterized spacelike curve under the contraction with the spacelike vector
,
, in the space-time
. Also,
is the curvature and
is the torsion of
. Moreover, any other spacelike curve
with the spacelike vector
satisfying the same conditions and
at
then
and the Frenet trihedrons of
and
is identically.
Theorem 5. Given differentiable functions
,
and
such that s is the arc length, there exists a regular parameterized spacelike curve under the folding with the spacelike vectors
and
,
in the space-time
. Also,
is the curvature,
is the first torsion, and
is the second torsion of
. Moreover, any other spacelike curve
with the spacelike vectors
and
satisfying the same conditions and
where
then
and the FrenetSerret formulas of
and
is identically.
Proof. Now assume that two curves
and
satisfy the conditions
,
and
,
. Let
,
,
,
and
,
,
,
be the Frenet-Serret formulas of
and
at
, respectively. Since
then
,
,
, and
. And
,
,
,
and
,
,
,
are the Frenet-Serret formulas of
and
, respectively. We now observe, by using the Frenet equations at (3), that

for all
. Thus, the above expression is constant and, since it is zero for
, it is identically zero. It follows that

for all
. Since
. We obtain
. Thus
, where
is a constant vector. Since
, we have
; hence,
for all
.
Theorem 6. Given differentiable functions
,
and
such that s is the arc length, there exists a regular parameterized spacelike curve under the deformation retract with the spacelike vectors
and
,
, in the space-time
. Also,
is the curvature,
is the first torsion, and
is the second torsion of
. Moreover, any other spacelike curve
with the spacelike vectors
and
satisfying the same conditions and
where
then
and the Frenet-Serret formulas of
and
is identically.
Theorem 7. Let
be a simple closed hyperplane curve under the folding in
with length
, and let A be the area of the region bounded by
. Then
(4)
and equality holds if and only if
is a circle.
Proof. Let E and
be two parallel lines which do not meet the closed curve
and moves them together until they first meet
We thus obtain two parallel tangent lines to
, L and
, so that the curve is entirely contained in the strip bounded by L and
. Consider a circle
which is tangent to both L and
and does not meet
. Let O be the center of
and take a coordinate system with origin at O and the
axis perpendicular to L and
. Parameterize
by arc length, since
simple closed a hyperplane curve, then
, so that it is positively oriented and the tangency points of L and
are
and
, respectively. We can assume that the equation of
is
, where 2r is the distance between L and
. Denoting by
the area bounded by
, we have

thus
(5)
We now notice the fact that the geometric mean of two positive numbers is smaller than or equal to their arithmetic mean, and equality holds if and only if they are equal. It follows that
(6)
Therefore, 
Now, assume that equality holds in Equation (4). Then equality must hold everywhere in Equations (5) and (6). From the equality in Equation (6) it follows that
. Thus,
and
does not depend on the choice of the direction of
. Furthermore, equality in Equation (5) implies that
, or
; that is,


Since
does not depend on the choice of the direction of
, we can interchange
and
in the last relation and obtain
. Thus,
and
is a circle.
Theorem 8. Let
be a simple closed a hyperplane curve under the deformation retract in
with length
, and let
be the area of the region bounded by
. Then
, and equality holds if and only if
is a circle.
Corollary 7. Let
be a simple closed a hyperplane curve under the contraction in
with length
, and let
be the area of the region bounded by
. Then
, and equality holds if and only if
is a circle.
Any n vectors forming a basis for
will be written
, i.e. the basis will be written
. Relative to a basis
, any vector
in
is uniquely expressible in the form


The numbers
, where
, are called the components of
relative to the basis
. If
are the components of another vector
relative to the same basis
. Let the vectors
form another basis of
. Since each vector
is uniquely expressible as a linear combination of the vectors
, we have
(7)
where
is an
matrix, non-singular because the vectors
, are linearly independent. Similarly, the vector
is uniquely expressible in the form
(8)
where
is a non-singular
matrix. Then

The linear independence of the basis vectors implies that
, where
called the kroneckel delta, takes the value 1 if
and is otherwise zero.
Theorem 9. The components of a vector
in
where defined relative to the basis
, and a change of basis will induce a change of components.
Proof. The law of transformation for the components of the vector
will now be found when the basis is change from
to
according the Equation (7). If the vector
has components
relative to the basis
, it is convenient to write
for it’s components relative to the new basis
, related to the former by (7). Then
(9)
Equations (7), (9) give

From which, since the basis vectors
are linearly independent, it follows that
(10)
Similarly, substitute in (9) for
from (8) to get

From which, since the basis vectors
are linearly independent
(11)
The Equation (11) expresses the new components in terms of the old component, while Equation (10) expresses the old components in terms of the new component.
Theorem 10. Under the retraction, given differentiable functions
,
and
, there exists a retraction of regular parameterized timelike curve
,
, such that
is the curvature,
and
are, respectively, the first and second torsion of
. Any other curve
satisfying the same conditions, different from
By a Poincaré transformation.
Proof. Let us assume that two timelike curves
and
satisfy the conditions
,
and
, with
, where
is an open interval of
, and
,
and
are, respectively, the curvature, first and second torsion of
. Let
and
, where
be the Serret-Frenet tetrads at
of
and
, respectively. Now, the two Serret-Frenet tetrads of
and
satisfy the equations

and

This can be written in a more compact form as
(12)

where
, with
and
denoting the elements of the Serret-Frenet matrix. Clearly, the two tetrads
,
are related by an equation of the type
(13)
with the elements of the matrix
satisfying the condition

Since we are assuming that 
From (12) and (13) we obtain a system of first-order differential equations for the elements of
given by
(14)
By assumption,
are differentiable functions of the proper parameter s. From the theory of ordinary differential equations, we know that if we are given a set of initial conditions
then the above system admits a unique solution

defined in an open interval
containing
. On the other hand, it is easily seen that
is a solution of (14). Therefore, we conclude that
.