The Exp-Function Method for Solving Two Dimensional Sine-Bratu Type Equations

In this paper, we apply Exp-function method to give traveling wave solutions of second order sineBratu type equations. This method is straightforward, concise and effective.


Introduction
Nonlinear differential equations have an important role in the study of nonlinear physical phenomena in science and technology.This paper investigates the exact solutions of nonlinear second order sine-Bratu type equations using the Exp-function method.Recently, several direct methods such as ( ) G G ′ -expansion method [1]- [3], sine-cosine method [4] [5], tanh-coth method [6] [7], He's homotopy perturbation method [8] [9], F-expansion method [10] [11] and others have been proposed to obtain exact solutions of nonlinear partial differential equations.Using these methods many exact solutions, including the solitary wave solutions, shock wave solutions and periodic wave solutions are obtained for some kinds of nonlinear evolution equations.The application of Exp-function method to obtain more explicit traveling wave solutions to many nonlinear differential equations has been developed by many researchers [12]- [15].The Exp-function method is based on the assumption that the travelling wave solutions can be expressed by a polynomial in Exp-function.It has been shown that this method is direct, concise, basic and effective.The solution procedure of this method, by the help of Maple, Matlab, or any mathematical package, is of utter simplicity.

Exp-Function Method
We suppose that the given nonlinear differential ( ) u x to be in the form
where P is a multivariate polynomial in its arguments.In the following, it is explained the basic for implementing Exp-function method.Taking the change of variable kx wy ξ = + , gives ( ) ( ) where k and w are constants parameter to be determined later.Substituting kx wy ξ = + into the Equation (2.1) yields an ODEs for ( ) where ( ) ( ) 2), term by term one or more times.This introduces one or more constants of integration.According to this method, we introduce the approach where m, n, p, and q are positive integers, which could be freely chosen, i a for , , i n m = −  and j b for , , j q p = −  are unknown constants to be determined.Substituting Equation (2.3) into Equation (2.2) yields an algebraic equation in powers of the Exp-function.Then, to determine the values of m and p, we balance the linear and nonlinear terms of the highest order in the resulting algebraic equation.Similarly, to determine the values of n and q, we balance the linear terms of the lowest order in Equation (2.2) with the lowest order nonlinear terms.

Application of the Exp-Function Method
Consider the following sine-Bratu type equation In order to apply the ( ) And then we use the transformation ( ) ( ) ( ) . Now, we assume that the solution of Equation (3.3) can be expressed in the form shown in Equation (2.3).To determine the constants m and p, we balance vv′′ with 3 v , by simple calculation, we have Similarly, we balance the lowest order terms in Equations (3.4) and (3.5), to determine the values of n and q, we obtain 2 3 3 2 n q n q + = + which leads to the result n q = .It is possible to choose the difference values of m, n, p and q.It is seen that when the equation has multiple solutions (like solitons) the Exp-function method is able to give us these solutions with using different m, n, p and q.Although it worth mentioning that different parameters may lead to equivalent solutions.
Case 1: and 1 q n = = For simplicity, we choose 1 p m = = and 1 q n = = , the trial function, Equation (2.3) becomes as , and k.Solving this system of algebraic equations with the aid of Maple, we obtain and 1 q n = = When the parameters p, m, q and n are chosen 2 p m = = and 1 q n = = , the solution is of the following form: Proceeding in a similar way as illustrated in case 1, we can identify parameters, 2 1 0 1 1 0 1 , , , , , , , ,  a a a a b b b w − − and k in Equation (3.9) as follows: and 2 q n = = As mentioned earlier, the values of m and n can be freely chosen, now we set 2 p m = = and 2 q n = = , Equation (2.3) turns to the following form: By the same manipulation as illustrated earlier, the following relations is obtained where w and 0 b are free parameters.By substituting Equation (3.13) into Equation (3.12), the following exact solution is obtained

Conclusion
In this paper, we have obtained the exact solution of sine-Bratu type equation.We achieved the solution by applying Exp-function method.The results show that Exp-function method is a powerful tool for obtaining solitary solution.It may be concluded that the Exp-function method can be easily extended to all kinds of nonlinear equations.The advantage of this method over other methods is that we can obtain the exact solution by using a simple computer program.The computations associated in this work were performed by using Maple 15.
leading term order m p = .
3.6) into Equation (3.3) and taking the coefficients of ( ) exp nξ in each term zero yield a set of algebraic equations for 1 0 1 0 1 , , , , , a a a b b w − − 0 b are free parameters.Substituting Equation (3.7) into Equation (3.6), it is obtained the following exact solution and 0 b are free parameters.Substituting Equation (3.15) into Equation (3.14), we obtain the following exact solution