Mass as the Fifth Dimension of the Universe

Newton considered three-dimensional universe endowed with flat space Euclidean geometry, and treated the time as an outside parameter and established his dynamics of the universe. Einstein along with space, considered time, and generated a four-dimensional universe endowed with non-Euclidean curved space-time geometry with time as its fourth dimension, and set up his field equations. Schwarzschild solved Einstein’s field equations around a star in space, which is, otherwise, flat, and obtained a solution. We, along with space and time, considered mass which also included energy according to Einstein’s mass-energy equivalence relation: E = mc, and generated a five-dimensional universe with the mass as its fifth dimension, and solved the Einstein’s field equations, in some simple cases, and obtained solutions around a star in space, which is otherwise, flat.


Introduction
Though, the Newtonian dynamics is ruling the universe endowed with three dimensional flat space Euclidean geometry, it is well known that it suffers from certain serious problems in dealing with all kinds of situations that prevail in the universe.Hence, Einstein [1,2] had to put forth his theories of relativity by taking into consideration the presence of time in each and every event taking place in the universe.He took the time as the fourth dimension of the universe, on the same footing as three space dimensions, in the background of non-Euclidean curved space-time geometry, and set up his field equations.Schwarzschild [3] solved Einstein's field equations around a star in the space, which is otherwise flat, and obtained a solution.Though, the mass is present everywhere in the universe, generally, it has been put aside as one more dimension of the universe in its physical description.When we say mass, here, we mean mass as well as energy.This is due to Einstein's mass-energy equivalence relation: 2

E mc
 .As far back as 1920s, [4,5] and recently, this problem has caught attention of some scientists [6,7].We, along with space and time, considered the mass as the fifth dimension of the universe, and generated five-dimensional universe and solved the Einstein's field equations in some simple cases, and obtained solutions around a star in five-dimensional universe, which is, otherwise flat.

Solution of Einstein's Field Equations with Mass as the Fifth Dimension
The line element in the five-dimensional Euclidean flat space-time in the spherical coordinate system with mass as the fifth dimension can be written down as: The most general line element being: where is the conversion factor which is a universal constant converting mass into length.Note that its value is of the order 26 10  .This is the reason for the fifth-dimension being suppressed.In the region contain-ing higher mass, the effect of the fifth-dimension in the five-dimensional universe may be revealed to an appreciable level.To begin with, we take as functions of r alone, and at large distances from the attracting point mass sitting at the origin of the five-dimensional universe , , 0     as r   to coincide with flat space-time-mass metric Equation (1).
The gravitational potentials   , , 1, 2,3, 4,5 The contravariant metric tensors ij g are given by 2 2 2 e 0 0 0 0 The Christoffel symbols of the second kind are given by   , where   , jk l are the Christoffel symbols of the first kind, and are being given by and il g are contravariant metric tensors.We have , , 1, 2,3, 4,5 i j k  .There are 16 non-vanishing Christoffel symbols of the second kind which are given below: Einstein's field equations are 0, , 1, 2,3, 4,5 where ij G are given by From Equations ( 6)-(8), we get These are equations in r alone.They are difficult to solve in their very general form.We, therefore, begin with the following simple cases: Case (i), μ = μ(r) = constant (say) k.As μ = μ(r) → 0, as r   this constant must be zero.In this simple case, the Equations 9(a)-(f) reduce to the following: These are the Einstein's field equations in five-dimensional universe with mass as its fifth dimension.The solution of these equations is: If the mass is small, the mass dimension is suppressed by the conversion factor which is of the order line element (solution) in five-dimensional universe with mass as its fifth dimension without showing much effect of mass dimension, except that it appears as one of the dimensions in the line element.Case (ii), ν = ν(r) = constant (say) k .As ν = ν(r) → 0 as r   , this constant must be zero.
In this simple case, the Equations 9(a)-(e) reduce to the following: The solution of these equations is more generalized cases are under consideration.

Summary
In MKS (Meter-Kilogram-Second) system, Newton utilized three-dimensional space: length, breadth and height ( , , x y z coordinates) with time as an external parameter.Einstein added one more dimension to the Universe that of time which is also everywhere present.In MKS System Kilogram (mass) remained to be utilized.We now take mass, which also includes energy due to Einstein's energy-mass equivalence relation: 2 E mc  , as the fifth dimension of the Universe, thereby making MKS system fully utilized, and generating five dimensional universe and solving Einstein's field equations, in some simple cases.Work is going on to translate the whole of Maxwell's electrodynamics into five-dimensional space to apply it to solve some problems in the general theory of relativity as well.