A Global Solution of the Einstein-Maxwell Field Equations for Rotating Charged Matter

A stationary axially symmetric exterior electrovacuum solution of the Einstein-Maxwell field equations was obtained. An interior solution for rotating charged dust with vanishing Lorentz force was also obtained. The two spacetimes are separated by a boundary which is a surface layer with surface stress-energy tensor and surface electric 4-current. The layer is the spherical surface bounding the charged matter. It was further shown, that all the exterior physical quantities vanished at the asymptotic spatial infinity where spacetime was shown to be flat. There are two different sets of junction conditions: the electromagnetic junction conditions, which were expressed in the traditional 3-dimensional form of classical electromagnetic theory; and the considerably more complicated gravitational junction conditions. It was shown that both—the electromagnetic and gravitational junction conditions—were satisfied. The mass, charge and angular momentum were determined from the metric. Exact analytical formulae for the dipole moment and gyromagnetic ratio were also derived. The conditions, under which the latter formulae gave Blackett’s empirical result for rotating stars, were investigated.


Introduction
There are difficulties in finding exact solutions of the Einstein or of the Einstein-Maxwell field equations for a volume distribution of rotating bounded matter [1].Such solutions should consist of an interior filled with matter and an asymptotically flat vacuum or electrovacuum exterior, these being separated by a surface on which appropriate boundary conditions should be satisfied.The main aim of this work is to obtain an exterior and matching interior solution of the Einstein-Maxwell field equations with finite bounded rotating charged matter as a source of the spacetime.Due to the rotation, the boundary will actually be an oblate spheroid, but it is assumed that it is a spherical surface with equation r = a.The main objective and emphasis after all, is to see how far the attempt at finding a solution can be taken-a solution with finite bounded rotating matter as a source of the spacetime.The additional complication of spheroidal coor-dinates is avoided, in a problem which is already enormously complicated.
Most of the equations and expressions for the various physical quantities are difficult to derive and they require involved and lengthy analysis.It is not therefore possible or desirable to include these calculations in the paper, but directions in which to proceed are indicated.

The Einstein-Maxwell Field Equations
Consider electrically charged pressure-free matter (charged dust) bounded by the hypersurface r = a and rotating with constant angular velocity about the polar axis 0   under zero Lorentz force.It is assumed that the current is carried by the dust.The transformed expression (2.1) in [2] for the Weyl-Lewis-Papapetrou metric for a stationary axially symmetric spacetime V is where we have taken the signature of the spacetime metric tensor g  to be 2.  It is implicit in the form (1) of the metric that we have assumed, without loss of generality, that We shall use units c = G = 1 where is the vacuum speed of light and G the Newtonian gravitational constant.Unless otherwise specified, we shall adopt the convention in which Roman indices .We shall transform those equations in [2] that are required here, to the spherical polar coordinates and time , tan , , r z z The contravariant and covariant forms  and u  of the 4-velocity are   3 4 .
The electric 4-current J  , the electromagnetic 4-potential A  and the Faraday tensor F 
, are where  is the electric charge density.The Einstein-Maxwell field equations for charged dust are   , , 0 4π .
Here,   is the Einstein tensor : where   is the Ricci tensor of the spacetime defined by its fully covariant form as with   the Christoffel symbols of the second kind based on the metric of V in Equation (1), is the spacetime scalar curvature invariant and g is the determinant of where are, respectively, the matter and electromagnetic stressenergy tensors and Instead of expressing the electromagnetic field equations in 4-dimensional form as in Equations ( 5), we shall use the Maxwell form (Maxwell's equations), because we can make direct comparisons with the results from classical electromagnetic theory.The electric and magnetic intensities and corresponding inductions in 3-vector form, are [4,5] [2] may be written as where the operators  and are defined by Equations ( 12) and ( 13) are the detailed form of the source-containing Maxwell equations given in the second of (5).
The non-zero components of the Ricci tensor obtained from the transformed Equations (2.16)-(2.21) of [2] are: Copyright © 2012 SciRes.JMP The entire Riemannian spacetime V, will be separated into the following 4-dimensional manifolds: the hypersurface with equation  separates V into the interior and exterior spacetimes.We shall use the + and -signs to denote quantities in V and V whenever it is necessary to do so.Quantities without the + or -indicators, may be associated either with or with V . 

The Exterior Solution
In accordance with the formalism in [2], we first form the complex function where  and  are harmonic functions.With a star denoting complex conjugation, the metric functions If we denote the real and imaginary parts of   by  and  , then We now choose the functions  and  as follows: where and  are constants whose significance will emerge later.From now on we shall omit writing the argument cos of the Legendre polynomials and we shall write, for example, 2 1 We note the significant fact that at 2 1 0; The function : and the electromagnetic 4potential in the exterior are obtained from where an arbitrary constant in 4 A  b .
was set equal to in order to satisfy the continuity condition of 4 A Note that the full expression for r in the first of (28) is 24) and ( 28)-(31), we obtain the fol- It is a little difficult to solve the two equations in (28) to find in (33).It is even more difficult to solve the two Equations ( 29)-(30) to find 3 w  A  in (34) and complete details of the calculation are not given.Whenever there are two signs in a term, the upper sign gives the expression in 0 π 2    and the lower sign the expression in π 2 π,    as in Equation (32).The function B defined by has Legendre polynomial expansion of the form where 2 2 It therefore follows from (27), that .The function in (36) satisfies the conditions for such an expansion [6] and we have for the odd coefficients With by Equations ( 24) and (26), the metric function F + at becomes It will be shown in Section 4, that everywhere in the interior.In order to satisfy the junction condition at therefore, we must have , which is a constant.If we take this to be equal to 1, we obtain and collecting these relationships together we have The third of Equation ( 39) is the result of substituting the second of these equations into the first, bearing in mind the second of Equation (26) for .For the calculations that follow the functions X and defined by Y (41) will be required.We express   and   as The components of   are therefore calculated using the exterior functions (32)-(35) with Equations ( 16)-( 22) and, whenever necessary, bearing in mind the first of Equation (39).The calculations give the following nonzero components: Here,  E are the nonzero components of the electromagnetic energy tensor.The components of    were obtained from (10) the third of (3) for F  , the exterior electromagnetic potentials in (34) and (35).Equation ( 22) gives 0 R  in and so by (6), , is that the matter energy tensor 0 R  M   will be null as should be the case in the electrovac  .
V The sourceless Maxwell equations in the first of (5) give 41, 42,r . By the third of (3) and with  and given by ( 34) and ( 35), these become which  are trivially satisfied.The source-containing Maxwell Equations ( 12) and ( 13) with 3 A  and 4 A  4 0 J given by Equations ( 34) and (35) will give and 3 0 J   and so the 4-current is null in the electrovac V  .

The Interior Solution
In accordance with the results of [2], the functions , and A  are constant which we shall take as The functions K  and 3 A  satisfy an equation of the form with given by ( 15).This implies that where  is a harmonic function, which therefore satisfies Laplace's equation with given by ( 14).
where the constants are determined from the junction condition . We use Equation (49) for K  with  given by (50) to find We can further show that 1 cos and with this, the above expression for Finally, after a little manipulation, the above expression for The junction condition for the continuity of . Using the expression (33) for w + and bearing in mind that . It therefore follows from (33) and (51), that the constants are given by 2 1 n This implies that K  , but also and w  are given by 3 The functions Z and U defined by will be required to simplify the components of the Einstein tensor.

 
The components of    are calculated using the interior functions (48) and (52) with Equations ( 16)-( 22) and, whenever necessary, bearing in mind the first of Equation (39).The calculations give the following nonzero components: 8π sin   were obtained from (10) the third of (3) for F  , the interior functions in (48) and (52).The components of were obtained from Equations ( 3) and ( 9) together with the interior functions (48) and (52).Equations ( 55 It follows from this and Equation (60 where the second and third of Equation ( 61), represent the values of on the V and V sides of .N   It follows from Equations (32)-( 35), ( 48) and (52) that and  The functions g  and A  are therefore continuous across but one degree of smoothness is lost because the first order partial r-derivatives of these functions are discontinuous on ,  . It follows that the ordinary junction conditions requiring the continuity of the directional derivatives of these functions normal to cannot be applied.The discontinueties of these normal derivatives will generate a surface layer on with surface stress-energy tensor and surface 4-current and a more complicated set of junction conditions will apply.The Equations ( 12) and ( 13) for ,   3 J and 4  J will give rise to expressions with factors of delta-functions and first order partial r-derivatives which are discontinuous on We shall denote these terms by Gothic symbols, and we find from ( 12) and ( 13) that these are .A  are given in (34), ( 35) and ( 52) respectively.To obtain the surface 4-current s and 4  s , we form the integrals of 3  J and 4 J with respect to proper distance measured perpendicularly through  from r a    to r a    and then find the limits as 0.

 
There are no sign indicators with the metric functions , K F V and in (62) and (63) because their values in both, and V , are required in these integrations, where the only nonzero contributions will arise from the delta-function parts and of

J
J and 4 J in Equations ( 62) and ( 63).With the unit vector in the The electromagnetic junction conditions are is the unit normal to the sphere and is the unit vector in the  direction.In these equations, the contravariant component of The Equations ( 16)-( 22) for R   and will give rise to terms with factors of delta-functions and first order partial r-derivatives which are discontinuous on , R  .Denoting these terms by Gothic symbols, the Einstein tensor   G and the associated matter stress-energy tensor   M are connected through the field equations, and so on  we have

R
we display below the components and as examples: The surface stress-energy tensor   is expressed in terms of the limits as 0  of the integrals of  M given in Equations ( 64).The junction conditions on  are [2,7]   Here, is the extrinsic curvature tensor of  defined by , where the covariant differentiation is connected with the metric of Since   on  this gives ,1 ab ab where the Ricci tensor is given by : the junction conditions (65) may be calculated and these conditions may be shown to be valid.

Mass, Charge, Angular Momentum and the Magnetic Dipole Moment
The mass, charge and angular momentum are defined by their imprints on the spacetime geometry far from the source.To obtain the gravitational mass and electric charge therefore, we expand the exterior metric function F  up to the term 2 2 3 .m r Bearing in mind the first of (39), we then obtain from (32) We may transform F + in (66) to the RN F of the Reissner-Nordstrom solution, by the transformation . This expression therefore implies that the gravitational mass is and the electric charge is and these are connected by [8] If we now expand K + to ( ) where 1 A is obtained from (38) by setting which will then give, bearing in mind (39) 1, n = ( ) If J is the total angular momentum, we have [9] 2 2 sin J r From ( 68) and (70), we then obtain J b a A = and on using (69), this gives The dipole field is the part of the magnetic field Η whose physical components r H and H q contain the factors and respectively.Since only the power is required, we only need the mode of the third of the expressions in (11) for . We find that these components are ( ) ( ) With these, the magnetic dipole moment is therefore, and on using (69), this gives ( ) From ( 71) and (73), we deduce that the gyromagnetic ratio is ( ) In physical units Equations ( 71), ( 73), (74) and the third of (39), become ( ) J and are P It may be shown that the units of respectively, which are the units of angular momentum and magnetic dipole moment.We also find from the second of (26) and the second of (39) that ( ) We stress the fact that all the above formulae are for an electrically charged sphere whose mass m and charge q are related by Equation (67).We note from (75) and (76) that the angular momentum J and dipole moment P depend on but also in a somewhat more subtle way, on the mass to radius ratio through the quantities and .The analytical Formula (77) may be applied to a number of different objects.We note that there exists a formula for the gyromagnetic ratio of stars known as Blackett's empirical Formulas [10][11][12], which reads where is a constant of the order of unity so that (80) becomes Blackett suggested that an explanation of this relation "must be sought in a new fundamental property of matter not contained within the structure of present day physical theory."We note in this connection that the factor G c , occurs in both our analytical Formula (77) and in Blackett's empirical Formula (80).The explanation for the presence of this factor in the analytical Formula (77) however is implicit in its derivation.Furthermore, the coefficient of G c ( ) in this formula is , and in Blackett's Formula (80), it is a constant equal to 1, or approximately equal to 1.The quantity with and b given by ( 78) and (79) respectively, is expected to vary from star to star, but in Blackett's Formula (80) is a constant equal to 1 for all stars, an assertion that seems improbable.In the context of our solution, it is difficult to see why different objects which can be as diverse as the Earth and the Sun, will conform to such a requirement as implied by Blackett's empirical Formula (81).Although the "new physics" idea was subsequently abandoned, it is nevertheless of interest to investigate further under what circumstances, if any, our exact analytical Formula (77) reduces to Blackett's empirical Formula (81).

l
In order to gain an insight into the relation between the analytical Formula (77) and Blackett's empirical Formula (81), we shall consider three cases with different numerical values for the radius and gravitational mass of the sphere.We shall then proceed to calculate the corresponding quantities in , , and l P J in (78), ( 79) and (77): .
The above masses and radii were deliberately chosen to be numerically equal to those of the Sun, 78 Virginis and the Earth.These correspond to the three astronomical objects that are quoted in the literature by later authors in connection with Blackett's empirical Formula (80) [10].It is seen from the numerical results in (82)-(84), that in the case of our electrically charged spheres, the coefficient of G c is very nearly equal to1 in every case.We must conclude that in situations where the ratio m a ( ) is such that is approximately equal to 1, our analytical Formula (77) will give Blackett's empirical Formula (81).These reductions however, are only possible in the cases where, .Thus, if we consider a typical neutron star as a fourth case we have and this is because .In the context of our equations, we found the precise condition under which our analytical Formula (77) will give Blackett's empirical Formula (81).Again, in the context of our equations, this provides a full explanation why Blackett's formula is sometimes valid and why this occurs only for a range of objects.Our formula for the gyromagnetic ratio P J is not empirical, but an exact analytical formula which is a consequence of the equations derived from the exact global solution of the Einstein-Maxwell field equations found here.It does not require any new fundamental properties of matter or any new physics and it is valid for all values of the ratio m a m q m m q m q .We note that Wilson [12,13] observed that in the case of the Earth and the Sun, the Formula (80) can be accounted for, if we assume that a rotating mass has the same effect as a rotating electrical charge where and q are connected by Equation (67).It is a little puzzling that our electrically charged spheres charged as they are in accordance with Equation (67), seem to echo the above observation by Wilson.In our case however, and are connected by Equation (67) in reality.The quantity of charge required is quite small.As noted by Bonnor [8], if the mass and charge are related by Equation (67), then if in a sphere of neutral hydrogen one atom in 10 18 had lost its electron, this would be sufficient.

Discussion and Conclusions
Exact exterior and interior solutions of the Einstein-Maxwell field equations for rigidly rotating pressure-free matter were obtained.The exterior and interior spacetimes are separated by a boundary which is a surface layer with surface stress-energy tensor and surface electric 4-current.
Perhaps one of the most important aspects of this work is that the source of spacetime, is rotating charged matter bounded by a closed surface.As far as we know, a global solution with a volume distribution of finite bounded rotating matter as a source of the spacetime, does not exist in the literature, although flat disk solutions do indeed exist [1].Another important outcome of this work is the derivation of analytical formulae for the angular mo-mentum, dipole moment and gyromagnetic ratio of a rotating sphere based on general relativistic equations.
The mass, charge, angular momentum and the magnetic dipole moment were determined in Section 5.In particular, we derived the analytical Formula (77) for the gyromagnetic ratio and discussed special cases to establish the facts regarding the connection between the analytical Formula (77) and Blackett's empirical for Formula (80) the conditions under which the analytical Formula (77) reduces to Blackett's empirical formula, were obtained.No new properties of matter and no new physics was required.Perhaps the analytical Formula (77) is valid for all rotating objects and in particular for stars, but we have no data to demonstrate this, except for the cases of the Sun, 78 Virginis and the Earth.
All the physical quantities of interest in the interior and exterior were calculated as well as those associated with the spherical surface layer.In this problem, the ordinary gravitational junction conditions are inappropriate.In fact there are two sets of junction conditions, the electromagnetic and the gravitational ones.The former were expressed in the familiar form of classical electromagnetic theory.The gravitational junction conditions in this problem are more complicated than the usual ones, because of the surface layer.These were clearly stated, although no detailed formulae were displayed.
This solution permits a reversal of the signs of 3 A + and 4 A + in (34) and (35) [14], which will cause a reversal of the signs of with appropriate modifications to the remaining functions in (32)-(34).Our exterior solution, given by these equations, reduces to the solution obtained by Perjes [14].
To find the limit of the exterior solution (32)-(35) when the angular momentum J is reduced to zero, we replace the harmonic function in (27) by zero, choose and base the solution on the single harmonic function in (26).This leads to which is the Papapetrou solution [15] for which Bonnor has found a matching interior solution [8].=0 r K w

r a =
Referring to the surface layer that occurs in our solution, we note the result obtained by Ruffini and Treves in a non-relativistic treatment, in which they had shown that a magnetized rotating object has surface charge and current densities; it is also endowed with a net electric charge [16].This agrees with our results and in particular, it confirms the existence of a surface layer with 4-current and stress-energy tensor on the boundary The mass, charge, angular momentum and the magnetic dipole moment were determined in Section 5.In particular, we derived the analytical Formula (77) for the gyromagnetic ratio and discussed special cases to establish the facts regarding the connection between the analytical Formula (77) and Blackett's empirical Formula (80).The conditions under which the analytical Formula (77) reduces to Blackett's empirical formula, were obtained.No new properties of matter and no new physics were required.Perhaps the analytical Formula (77), is valid for all rotating objects and in particular for stars, but we have no data to demonstrate this, except for the cases of the Sun, 78 Virginis and the Earth.
components of the electromagnetic and mass energy tensors respectively.The components of   

1 D D and the covariant component 2 H
of H from the second and third of Equation(11) were used.
mass of the Sun.It is seen that P

3 A
of the metric functions in (32) and (33)